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Grade 7 Maths Test Answers | 七年级数学测试答案解析

2026-08-22 01:11 · 本文部分内容由AI辅助创作

📚 Grade 7 Maths Test Answers | 七年级数学测试答案解析

This revision article works through a typical Grade 7 mathematics test paper and explains the answers step by step. It covers number, algebra, geometry, ratio, and statistics topics commonly assessed at this level.

本文是一篇七年级数学测试答案详解。我们按照常见试卷结构,逐一讲解数与式、代数、几何、比与比例、统计等题型的解题过程与最终答案。

Use the paper as a self-check: attempt each question first, then compare your working with the model answer.

使用时可以先独立作答,再对照答案和解析,找出错误步骤并进行订正。


1. Integers and Order of Operations | 整数与运算顺序

Question 1: Evaluate −5 + 8 × (−3) ÷ 2.

题 1:计算 −5 + 8 × (−3) ÷ 2。

nd division before addition. 8 × (−3) = −24, then −24 ÷ 2 = −12. Finally −5 + (−12) = −17.

解析:按照先乘除后加减的顺序。8 × (−3) = −24,再 −24 ÷ 2 = −12,最后 −5 + (−12) = −17。

−5 + 8 × (−3) ÷ 2 = −17

Answer: −17

答案:−17

Question 2: Work out (−2)³ + (−4)².

题 2:计算 (−2)³ + (−4)²。

tays negative. (−4)² = 16 because a negative number squared is positive. Add: −8 + 16 = 8.

解析:(−2)³ = −8,因为负数奇次方仍为负;(−4)² = 16,因为负数平方为正。相加得 −8 + 16 = 8。

(−2)³ + (−4)² = 8

Answer: 8

答案:8


2. Fractions, Decimals and Percentages | 分数、小数与百分比

Question 1: Convert 7/20 to a decimal and a percentage.

题 1:将 7/20 转换为小数和百分比。

: Divide 7 by 20 to get 0.35. To convert to a percentage, multiply by 100: 0.35 × 100 = 35%.

解析:7 除以 20 得 0.35。转换为百分比时乘以 100:0.35 × 100 = 35%。

Fraction 分数 Decimal 小数 Percentage 百分比
7/20 0.35 35%

Question 2: Find 15% of 240.

题 2:求 240 的 15%。

Solution: Write 15% as 0.15, then multiply: 0.15 × 240 = 36.

解析:将 15% 写作 0.15,再计算 0.15 × 240 = 36。

15% of 240 = 36

Question 3: Work out 2 3/4 + 1 1/3.

题 3:计算 2 3/4 + 1 1/3。

common denominator is 12: 11/4 = 33/12, 4/3 = 16/12. Add: 33/12 + 16/12 = 49/12 = 4 1/12.

解析:化为假分数:2 3/4 = 11/4,1 1/3 = 4/3。最小公分母为 12:11/4 = 33/12,4/3 = 16/12。相加得 33/12 + 16/12 = 49/12 = 4 1/12。

2 3/4 + 1 1/3 = 4 1/12


3. Ratio and Proportion | 比与比例

Question 1: Share $120 between A and B in the ratio 3 : 5.

题 1:按 3 : 5 的比例将 120 美元分给 A 和 B。

= 3 + 5 = 8. One part = 120 ÷ 8 = 15. A receives 3 × 15 = 45, and B receives 5 × 15 = 75.

解析:总份数 = 3 + 5 = 8。一份 = 120 ÷ 8 = 15。A 得 3 × 15 = 45,B 得 5 × 15 = 75。

A = 45, B = 75

Question 2: A recipe uses flour and sugar in the ratio 4 : 1. If 600 g of flour is used, how much sugar is needed?

题 2:一个配方中面粉与糖的比例为 4 : 1。如果用了 600 g 面粉,需要多少糖?

parts and sugar is 1 part. One part = 600 ÷ 4 = 150 g. Therefore sugar = 1 × 150 = 150 g.

解析:4 : 1 表示面粉为 4 份,糖为 1 份。一份 = 600 ÷ 4 = 150 g。因此糖 = 1 × 150 = 150 g。

Answer: 150 g

答案:150 g


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4. Algebraic Expressions | 代数式

Question 1: Simplify 3a + 5b − 2a + 7b.

题 1:化简 3a + 5b − 2a + 7b。

: Collect like terms: 3a − 2a = a and 5b + 7b = 12b. The simplified expression is a + 12b.

解析:合并同类项:3a − 2a = a,5b + 7b = 12b。化简结果为 a + 12b。

3a + 5b − 2a + 7b = a + 12b

Question 2: Expand 4(2x − 3).

题 2:展开 4(2x − 3)。

each term inside the bracket by 4: 4 × 2x = 8x and 4 × (−3) = −12. The result is 8x − 12.

解析:将括号内每一项都乘以 4:4 × 2x = 8x,4 × (−3) = −12。结果为 8x − 12。

Question 3: Factorise 6x + 9.

题 3:因式分解 6x + 9。

Solution: The highest common factor of 6x and 9 is 3. Write 6x + 9 = 3(2x + 3).

解析:6x 和 9 的最大公因数是 3。因此 6x + 9 = 3(2x + 3)。

Question 4: Substitute x = −2 into 2x² − 4x.

题 4:将 x = −2 代入 2x² − 4x。

: Replace x with −2: 2(−2)² − 4(−2). Since (−2)² = 4, this becomes 2 × 4 + 8 = 8 + 8 = 16.

解析:用 −2 替换 x:2(−2)² − 4(−2)。因为 (−2)² = 4,所以原式 = 2 × 4 + 8 = 8 + 8 = 16。

2(−2)² − 4(−2) = 16


5. Solving Linear Equations | 解一元一次方程

Question 1: Solve 5x − 7 = 18.

题 1:解方程 5x − 7 = 18。

Solution: Add 7 to both sides: 5x = 25. Then divide both sides by 5: x = 5.

解析:两边同时加 7:5x = 25。然后两边同时除以 5:x = 5。

5x − 7 = 18 → x = 5

Question 2: Solve 2(x + 3) = x − 4.

题 2:解方程 2(x + 3) = x − 4。

he left side: 2x + 6 = x − 4. Subtract x from both sides: x + 6 = −4. Subtract 6: x = −10.

解析:展开左边:2x + 6 = x − 4。两边同时减 x:x + 6 = −4。再减 6:x = −10。

2(x + 3) = x − 4 → x = −10

Question 3: Solve x/4 + 3 = 7.

题 3:解方程 x/4 + 3 = 7。

Solution: Subtract 3 from both sides: x/4 = 4. Multiply both sides by 4: x = 16.

解析:两边同时减 3:x/4 = 4。两边同时乘以 4:x = 16。


6. Inequalities | 不等式

Question 1: Solve 3x − 5 ≤ 10.

题 1:解不等式 3x − 5 ≤ 10。

. Divide both sides by 3: x ≤ 5. The solution is all real numbers less than or equal to 5.

解析:两边同时加 5:3x ≤ 15。两边同时除以 3:x ≤ 5。解集为所有小于或等于 5 的实数。

3x − 5 ≤ 10 → x ≤ 5

Question 2: Solve −2x + 4 > 10.

题 2:解不等式 −2x + 4 > 10。

Solution: Subtract 4 from both sides: −2x > 6. Divide both sides by −2 and reverse the inequality sign: x < −3.

解析:两边同时减 4:−2x > 6。两边同时除以 −2,不等号方向要改变:x < −3。

Key rule: When you multiply or divide an inequality by a negative number, you must reverse the direction of the inequality sign.

关键规则:当不等式两边同时乘以或除以一个负数时,必须改变不等号的方向。


7. Angles and Lines | 角与直线

Question 1: Two angles lie on a straight line. One angle is 72°. Find the other angle.

题 1:两个角在一条直线上,其中一个角为 72°。求另一个角。

tion: Angles on a straight line add up to 180°. So the missing angle is 180° − 72° = 108°.

解析:直线上的相邻角之和为 180°。因此另一个角为 180° − 72° = 108°。

180° − 72° = 108°

Question 2: A triangle has angles of 45° and 60°. Find the third angle.

题 2:一个三角形有两个角分别为 45° 和 60°。求第三个角。

tion: The three angles of a triangle add up to 180°. Third angle = 180° − 45° − 60° = 75°.

解析:三角形内角和为 180°。第三个角 = 180°

Published by TutorHao | Mathematics Revision Series | aleveler.com

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