📚 Grade 4 Math Test Answers | 数学 G4 年级测试答案
This article provides a complete answer key and worked explanations for a typical Grade 4 mathematics test. It covers core topics such as place value, multiplication, division, fractions, decimals, measurement, time, and data. Use the explanations to check your reasoning and to learn from common mistakes.
本文提供一份典型四年级数学测试的完整答案和解题说明，涵盖位值、乘法、除法、分数、小数、测量、时间和数据等核心主题。请使用这些解析来检查你的推理过程，并从常见错误中学习。
1. Mental Addition and Subtraction | 心算加减法
0 = 6,000; 800 + 100 = 900; 60 + 30 = 90; 5 + 4 = 9. Then combine the totals to get 6,999.
第1题要求计算 4,865 + 2,134。一种可靠的心算方法是分别相加千位、百位、十位和个位：4,000 + 2,000 = 6,000；800 + 100 = 900；60 + 30 = 90；5 + 4 = 9。然后合并总数得到 6,999。
You may check by adding 2,522 + 4,681 = 7,203, which confirms the subtraction is correct.
对于减法，例如 7,203 − 4,681，答案是 2,522。你可以通过加法检验：2,522 + 4,681 = 7,203，这能确认减法正确。
2. Multiplication Facts and Missing Factors | 乘法口诀与缺失因数
Question 2 includes 8 × 7 = 56 and a missing factor problem 9 × ? = 63. Since 9 × 7 = 63, the missing factor is 7.
第2题包括 8 × 7 = 56 和缺失因数问题 9 × ? = 63。因为 9 × 7 = 63，所以缺失因数是 7。
63 ÷ 9 = 7. This helps students who are still building fluency with multiplication facts.
一个有用的策略是把缺失因数转化为除法：63 ÷ 9 = 7。这有助于仍在建立乘法口诀熟练度的学生。
3. Division with Remainders | 带余除法
÷ 6. The closest multiple of 6 below 47 is 42, and 47 − 42 = 5. Therefore, 47 ÷ 6 = 7 R5.
第3题要求计算 47 ÷ 6。小于 47 的最接近的 6 的倍数是 42，47 − 42 = 5。因此，47 ÷ 6 = 7 余 5。
In a word problem, 47 apples shared equally among 6 boxes would give 7 apples per box and 5 apples left over. The remainder must be less than the divisor, and here 5 < 6, so the answer is valid.
在应用题中，47 个苹果平均分给 6 个盒子，每盒放 7 个，剩余 5 个。余数必须小于除数，这里 5 < 6，因此答案有效。
4. Place Value and Rounding | 位值与四舍五入
Question 4 asks for the value of the digit 6 in 36,482. Since the 6 is in the thousands place, its value is 6,000.
第4题要求说出 36,482 中数字 6 的值。由于 6 在千位，它的值是 6,000。
Rounding 36,482 to the nearest thousand gives 36,000, because the hundreds digit is 4, so we round down. Rounding to the nearest ten thousand gives 40,000, because the thousands digit is 6, so we round up.
将 36,482 四舍五入到最接近的千位得到 36,000，因为百位数字是 4，所以向下舍入。四舍五入到最接近的万位得到 40,000，因为千位数字是 6，所以向上进位。
5. Equivalent Fractions | 等值分数
Question 5 asks which fraction is equivalent to 1/2. Possible choices include 2/4, 3/6, and 4/8. All of these are correct because multiplying the numerator and denominator by the same number gives an equivalent fraction.
第5题问哪个分数与 1/2 等值。可选的答案包括 2/4、3/6 和 4/8。这些都是正确的，因为分子和分母同乘一个数会得到等值分数。
To check, simplify 4/8 by dividing both the numerator and denominator by 4, which gives 1/2. This shows the two fractions represent the same part of a whole.
要检验，可以将 4/8 的分子和分母同时除以 4，得到 1/2。这说明两个分数表示整体的同一部分。
6. Adding and Subtracting Fractions | 分数加减法
Since the denominators are the same, add the numerators: 3 + 2 = 5, so the answer is 5/8.
第6题要求计算 3/8 + 2/8。由于分母相同，只需将分子相加：3 + 2 = 5，所以答案是 5/8。
giving 3/10. The denominator stays the same because the size of the parts does not change.
对于 7/10 − 4/10，分子相减：7 − 4 = 3，得到 3/10。分母保持不变，因为每一份的大小没有改变。
7. Decimals and Money | 小数与货币
Question 7 asks for the total cost of a $3.45 pencil case and a $ Add the decimals by aligning the decimal points: 3.45 + 1.20 = 4.65, so the total cost is $4.65.
第7题要求计算一个 3.45 美元的铅笔盒和一把 1.20 美元的尺子的总价。小数点对齐后相加：3.45 + 1.20 = 4.65，所以总花费是 4.65 美元。
To find change from $10.00, subtract $4.65 from $10.00: 10.00 − 4.65 = 5.35. The change is $5.35.
要计算从 10.00 美元中找零，用 10.00 减去 4.65：10.00 − 4.65 = 5.35。找零是 5.35 美元。
8. Perimeter and Area | 周长与面积
and width 4 cm. The perimeter is 2 × (9 + 4) = 2 × 13 = 26 cm. The area is 9 × 4 = 36 cm².
第8题给出一个长 9 厘米、宽 4 厘米的长方形。周长是 2 × (9 + 4) = 2 × 13 = 26 厘米。面积是 9 × 4 = 36 平方厘米。
Perimeter = 2 × (length + width)
周长 = 2 × (长 + 宽)
Remember that perimeter measures the distance around the shape, while area measures the surface inside the shape. Always include the correct unit: cm for perimeter and cm² for area.
请记住，周长测量图形外圈的距离，而面积测量图形内部的表面。务必使用正确的单位：周长用厘米，面积用平方厘米。
9. Telling Time and Elapsed Time | 时间与经过时间
Question 9 asks for the elapsed time from 2:45 p.m. to 5:15 p.m. From 2:45 to 3:45 is 1 hour, from 3:45 to 4:45 is another hour, and from 4:45 to 5:15 is 30 minutes. The total elapsed time is 2 hours 30 minutes.
第9题要求计算从下午 2:45 到下午 5:15 经过的时间。从 2:45 到 3:45 是 1 小时，从 3:45 到 4:45 又是 1 小时，从 4:45 到 5:15 是 30 分钟。总共经过的时间是 2 小时 30 分钟。
An alternative method is to count up to the next hour first: 2:45 to 3:00 is 15 minutes, 3:00 to 5:00 is 2 hours, and 5:00 to 5:15 is 15 minutes. The total is also 2 hours 30 minutes.
另一种方法是先补到下一个整点：2:45 到 3:00 是 15 分钟，3:00 到 5:00 是 2 小时，5:00 到 5:15 是 15 分钟。总计同样是 2 小时 30 分钟。
10. Reading Bar Graphs | 条形图阅读
8, and grape reaches 5, then the difference between the highest and lowest is 12 − 5 = 7.
第10题展示了一张关于最喜欢水果的条形图。如果苹果条达到 12，香蕉条达到 8，葡萄条达到 5，那么最高和最低之间的差是 12 − 5 = 7。
reading bar graphs, always check the scale on the y-axis, because one interval may represent more than one unit.
这三根条形显示的总回答数是 12 + 8 + 5 = 25。阅读条形图时，务必检查 y 轴上的刻度，因为一个间隔可能代表多于一个单位。
11. Multi-step Word Problems | 多步应用题
of them to her brother and then buys 10 more stickers. How many stickers does she have now? way 12, so she has 48 − 12 = 36 left. After buying 10 more, she has 36 + 10 = 46 stickers.
第11题说：Maya 有 48 张贴纸。她把其中的 1/4 给了弟弟，然后又买了 10 张贴纸。她现在有多少张贴纸？首先求出 48 的 1/4，即 48 ÷ 4 = 12。她送出 12 张，所以剩下 48 − 12 = 36 张。再买 10 张后，她有 36 + 10 = 46 张贴纸。
Multi-step problems require you to identify the correct order of operations. In this case, division comes first, then subtraction, then addition.
多步问题要求你确定正确的运算顺序。在这个例子中，先做除法，然后是减法，最后是加法。
12. Test Answers Summary | 测试答案总结
Below is a quick reference table for the main answers covered in this Grade 4 test. Use it to check your work and to review any topic where you made a mistake.
下面是一个快速参考表，汇总了这份四年级测试涉及的主要答案。用它来检查你的作业，并复习你做错的任何主题。
| Question / Topic | Answer |
|---|---|
| 1. 4,865 + 2,134 | 6,999 |
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