← 返回资讯屏轩教育 · 行业资讯

Year 9 Core Homework Compressed: Essential Skills and Worked Examples | 九年级核心作业精编:核心技能与例题解析

2026-08-22 00:34 · 本文部分内容由AI辅助创作

📚 Year 9 Core Homework Compressed: Essential Skills and Worked Examples | 九年级核心作业精编:核心技能与例题解析

This revision guide compresses the Year 9 core homework programme into ten essential skill areas. It gives clear rules, worked examples and common pitfalls so that you can complete homework accurately and revise efficiently.

这份复习指南把九年级核心作业计划浓缩为十个核心技能领域。它给出清晰规则、例题和常见易错点,帮助你准确完成作业并高效复习。


1. Number and Place Value | 数与位值

0,000, which equals 32,000. When multiplying by 10ⁿ, move the decimal point n places to the right; when dividing, move it n places to the left.

在九年级核心作业中,你需要熟练掌握正负数、10 的幂和标准形式。例如,3.2 × 10⁴ 表示 3.2 × 10,000,等于 32,000。乘以 10ⁿ 时,小数点向右移动 n 位;除以 10ⁿ 时,小数点向左移动 n 位。

he places from the first non-zero digit, not from the decimal point. With negative indices, the number is smaller than 1.

一个常见错误是把 0.00056 写成 5.6 × 10⁻³,而正确应为 5.6 × 10⁻⁴。要从第一个非零数字开始数位数,而不是从小数点开始数。负指数表示该数小于 1。


2. Fractions, Decimals and Percentages | 分数、小数与百分比

o compare fractions, decimals and percentages, convert them to the same form. For example, ⅗ = 0.6 = 60% To find a percentage of an amount, multiply the amount by the percentage as a decimal: 15% of £80 = 0.15 × 80 = £12.

比较分数、小数和百分比时,先把它们化成同一种形式。例如,⅗ = 0.6 = 60%。求一个数的百分比时,用该数乘以百分比化成的小数:80 英镑的 15% = 0.15 × 80 = 12 英镑。

Percentage increase and decrease often appear in homework. A jumper priced at £40 with a 25% decrease becomes £40 × (1 − 0.25) = £30. To reverse a percentage change, divide by the multiplier.

百分比的增加和减少经常出现在作业中。一件标价 40 英镑的毛衣降价 25%,变为 40 × (1 − 0.25) = 30 英镑。要逆向求原价,则除以对应的乘数。


3. Ratio and Proportion | 比与比例

total volume is 600 ml, one part is 600 ÷ 5 = 120 ml, so the parts are 360 ml and 240 ml.

比用来比较整体中的各个部分。3:2 表示总共有 3 + 2 = 5 等份。如果一种饮料按 3:2 混合,总体积为 600 毫升,则一份是 600 ÷ 5 = 120 毫升,因此两部分分别为 360 毫升和 240 毫升。

means that as one quantity increases, the other increases at the same rate. If 5 pens cost £3, then 20 pens cost £3 × (20 ÷ 5) = £12 because the number of pens is multiplied by 4.

正比例意味着一个量增加时,另一个量以相同速率增加。如果 5 支笔花费 3 英镑,那么 20 支笔花费 3 × (20 ÷ 5) = 12 英镑,因为笔的数量乘了 4。


4. Algebraic Expressions | 代数表达式

Only terms with exactly the same letter part can be combined; a and a² are not like terms.

通过合并同类项来化简表达式。例如,5a + 3b − 2a + 7b = 3a + 10b。只有字母部分完全相同的项才能合并;a 和 a² 不是同类项。

5x + 6. Remember to multiply every term in the first bracket by every term in the second.

去括号使用分配律:4(2x + 3) = 8x + 12。对于双括号,(x + 3)(x + 2) = x² + 5x + 6。记住要把第一个括号中的每一项与第二个括号中的每一项相乘。


5. Solving Linear Equations | 解一元一次方程

= 20, subtract 5 from both sides to get 3x = 15, then divide both sides by 3 to get x = 5.

解方程时,要对两边进行相同的运算以保持等式平衡。对于 3x + 5 = 20,两边先减 5 得到 3x = 15,然后两边除以 3 得到 x = 5。

xample: 5x − 2 = 2x + 7. Subtract 2x from both sides: 3x − 2 = 7. Add 2: 3x = 9, so x = 3.

如果未知数出现在等号两边,就把含未知数的项移到一边。例如:5x − 2 = 2x + 7。两边减去 2x:3x − 2 = 7。再加 2:3x = 9,所以 x = 3。


6. Coordinates and Linear Graphs | 坐标与线性图像

The coordinate (x, y) gives the horizontal position first and the vertical position second. The midpoint of two points (x₁, y₁) and (x₂, y₂) is ((x₁ + x₂) ÷ 2, (y₁ + y₂) ÷ 2). For (2, 3) and (6, 7), the midpoint is (4, 5).

坐标 (x, y) 先给出水平位置,再给出竖直位置。两点 (x₁, y₁) 和 (x₂, y₂) 的中点坐标是 ((x₁ + x₂) ÷ 2, (y₁ + y₂) ÷ 2)。对于 (2, 3) 和 (6, 7),中点为 (4, 5)。

e y-intercept. If y = 2x + 3, the gradient is 2 and the line crosses the y-axis at (0, 3).

直线的方程是 y = mx + c,其中 m 是斜率,c 是 y 轴截距。如果 y = 2x + 3,则斜率为 2,图像与 y 轴交于 (0, 3)。

by the change in x: m = (y₂ − y₁) ÷ (x₂ − x₁). This is often remembered as rise over run.

两点间的斜率等于 y 的变化量除以 x 的变化量:m = (y₂ − y₁) ÷ (x₂ − x₁)。这通常记作铅垂升高除以水平距离。


广告 / Sponsored

7. Geometry: Area and Perimeter | 几何:面积与周长

2l + 2w. Area is the space inside: A = l × w. Always include units such as cm, m² or cm².

周长是围绕图形一周的长度。长为 l、宽为 w 的长方形,周长 P = 2l + 2w。面积是图形内部的大小:A = l × w。始终要写单位,如 cm、m² 或 cm²。

perpendicular to the base. For a base of 8 cm and height of 5 cm, A = ½ × 8 × 5 = 20 cm².

三角形的面积公式为 A = ½ × 底 × 高。高必须与底垂直。底为 8 厘米、高为 5 厘米时,A = ½ × 8 × 5 = 20 平方厘米。

= ½ × (a + b) × h, where a and b are the parallel sides and h is the perpendicular height.

梯形的面积公式为 A = ½ × (a + b) × h,其中 a 和 b 是两条平行边,h 是垂直高度。


8. Angles and Properties of Shapes | 角与图形的性质

On a straight line, angles add to 180°. Around a point, angles add to 360°. In a triangle, the interior angles add to 180°. These facts allow you to find missing angles without measuring.

直线上的角相加为 180°。一个点周围的角相加为 360°。三角形内角相加为 180°。利用这些事实,你可以不测量就求出缺失的角。

o 180°. If one angle of a parallelogram is 65°, the angle next to it is 180° − 65° = 115°.

在平行四边形中,对角相等,同旁内角相加为 180°。如果平行四边形的一个角为 65°,与它相邻的角就是 180° − 65° = 115°。

Alternate angles and corresponding angles are equal when two parallel lines are cut by a transversal. Recognising these angle pairs is useful for proving that lines are parallel.

当两条平行线被一条截线所截时,内错角相等,同位角相等。识别这些角对有助于证明两条直线平行。


9. Statistics and Probability | 统计与概率

+ 8 + 10 + 11) ÷ 5 = 40 ÷ 5 = 8. The median is the middle value when the data are ordered.

平均数等于所有数值之和除以数值个数。对于 4、7、8、10、11,平均数为 (4 + 7 + 8 + 10 + 11) ÷ 5 = 40 ÷ 5 = 8。中位数是数据按顺序排列后位于中间的值。

umber of outcomes. If a bag has 3 red, 2 blue and 5 green counters, P(red) = 3 ÷ 10 = 0.3.

概率的取值范围是 0 到 1。P(事件) = 有利结果的数量 ÷ 所有结果的总数。如果一个袋子里有 3 个红球、2 个蓝球和 5 个绿球,则 P(红球) = 3 ÷ 10 = 0.3。

happening is 1 − P(event). For example, if P(rain) = 0.4, then P(no rain) = 1 − 0.4 = 0.6.

某事件不发生的概率是 1 − P(事件)。例如,如果 P(下雨) = 0.4,那么 P(不下雨) = 1 − 0.4 = 0.6。


10. Problem-Solving Strategies | 解题策略

Read the problem twice and underline key numbers and units. Write down what you know, what you need to find, and a plan. For multi-step problems, break them into smaller, manageable steps.

把题目读两遍,并在关键数字和单位下画线。写下已知条件、要求解的量以及求解计划。对于多步骤问题,把它拆分成若干较小、可处理的步骤。

Estimate before calculating and check your answer makes sense. For example, if you calculate a speed of 1200 km/h for a bicycle, you have probably mixed up units or placed a decimal point incorrectly.

计算前先估算,并检查答案是否合理。例如,如果你算出一辆自行车的速度为 1200 km/h,那你很可能把单位弄混了或小数点位置写错了。

Use diagrams, tables or algebra to organise information. When stuck, try a simpler version of the problem with smaller numbers, then apply the same logic to the original question.

用图表、表格或代数来组织信息。遇到困难时,可以先用更小的数字简化问题,然后把同样的逻辑应用到原题上。

Published by TutorHao | Mathematics Revision Series | aleveler.com

广告 / Sponsored
英文原版 Oxford IB Diploma Programme IB Prepared: English B Ski…
英语 备考教辅 · 正版现货 · 学习备考通用
查看详情 / View on Taobao参考价 ¥296.0
广告 / Sponsored
英文原版 Oxford IB Diploma Programme Mathematics Analysis And A…
数学 备考教辅 · 正版现货 · 学习备考通用
查看详情 / View on Taobao参考价 ¥653.0

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao