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Cambridge Primary Mathematics Workbook 5 (2nd Edition) Study Guide | Cambridge Primary 数学练习册5(第二版)学习指南

2026-08-22 00:15 · 本文部分内容由AI辅助创作

📚 Cambridge Primary Mathematics Workbook 5 (2nd Edition) Study Guide | Cambridge Primary 数学练习册5(第二版)学习指南

Written by Emma Low and Mary Wood, the Cambridge Primary Mathematics Workbook 5 (2nd Edition) supports learners following the Cambridge Primary Maths curriculum. This guide highlights the core topics, common challenges, and effective strategies for mastering each section of the workbook.

《Cambridge Primary Mathematics Workbook 5》第二版由 Emma Low 与 Mary Wood 编写,为学习 Cambridge Primary 数学课程的学生提供配套练习。本指南将梳理核心主题、常见难点以及掌握各部分内容的高效策略。

1. Overview of the Workbook | 练习册概述

The Workbook 5 is designed for Stage 5 learners and builds on concepts from earlier stages. It includes practice tasks, problem-solving activities, and investigations that develop both fluency and reasoning.

练习册5面向第五阶段学生,并在前几个阶段的概念基础上进一步拓展。书中包含练习任务、问题解决活动与探究项目,旨在同时培养运算流畅性与推理能力。

The second edition places stronger emphasis on mathematical thinking and real-world applications. Each unit is aligned with the Cambridge Primary Maths curriculum framework, making it suitable for classroom use or independent study.

第二版更加注重数学思维与实际应用。每个单元都与 Cambridge Primary 数学课程框架对齐,既可用于课堂教学,也适合学生自学。


2. Number and Place Value | 数字与位值

Learners work with whole numbers up to 1 000 000, reading, writing, ordering, and comparing large numbers. They also explore the value of each digit according to its position.

学生需要处理最高达 1 000 000 的整数,包括读写、排序与比较较大的数。他们还会探究每个数字根据其位置所代表的值。

Rounding to the nearest 10, 100, 1 000, 10 000, and 100 000 is a key skill. For example, 67 432 rounded to the nearest 1 000 is 67 000.

将数字四舍五入到最近的 10、100、1 000、10 000 和 100 000 是一项关键技能。例如,67 432 四舍五入到最近的 1 000 是 67 000。

Negative numbers are introduced in context, such as temperatures below zero. Learners count backwards through zero and compare negative and positive integers.

负数在温度低于零度等情境中被引入。学生练习倒数经过零,并比较负整数与正整数。


3. Addition and Subtraction | 加法与减法

Stage 5 focuses on fluency with column addition and subtraction for numbers up to five or six digits. Learners check answers using inverse operations, such as using subtraction to verify addition.

第五阶段重点训练五位数或六位数的竖式加法与减法运算。学生使用逆运算检查答案,例如用减法来验证加法结果。

Mental strategies remain important. Adding 999 can be done by adding 1 000 and then subtracting 1, which strengthens number sense.

心算策略仍然很重要。加 999 可以先加 1 000 再减去 1,这有助于增强数感。

Word problems often involve two or more steps. Learners must decide which operations to use and explain their reasoning clearly.

应用题通常涉及两步或更多步骤。学生需要判断使用哪种运算,并清晰地解释自己的推理过程。


4. Multiplication and Division | 乘法与除法

ethods to multiply three-digit numbers by one-digit numbers. For example, 327 × 6 = 1 962.

学生巩固 12 × 12 以内的乘法表,并将书面方法扩展到三位数乘一位数。例如,327 × 6 = 1 962。

A problem such as 83 ÷ 6 gives 13 remainder 5, which learners connect to 13 × 6 + 5 = 83.

除法包含余数,并与乘法事实相关联。例如 83 ÷ 6 得 13 余 5,学生将其与 13 × 6 + 5 = 83 联系起来。

Factors, multiples, and prime numbers are introduced. Learners identify prime numbers below 30 and use divisibility rules for 2, 3, 5, and 10.

因数和倍数以及质数被引入。学生识别 30 以内的质数,并运用 2、3、5 和 10 的整除规则。


5. Fractions, Decimals and Percentages | 分数、小数和百分比

nise that 1/2 = 2/4 = 4/8 and use diagrams or number lines to support their understanding.

等值分数是重点内容。学生认识 1/2 = 2/4 = 4/8,并使用图表或数轴来支持理解。

ame denominator is introduced. For example, 3/8 + 2/8 = 5/8, and 7/10 - 3/10 = 4/10 = 2/5.

同分母分数的加减法开始引入。例如,3/8 + 2/8 = 5/8,7/10 - 3/10 = 4/10 = 2/5。

two decimal places. Learners convert between tenths and hundredths, so 0.7 = 0.70 = 7/10.

小数扩展到两位。学生进行十分位与百分位之间的转换,因此 0.7 = 0.70 = 7/10。

Simple percentages such as 25%, 50%, and 75% are linked to fractions with denominator 100. Leaners find 50% of 240 by halving, giving 120.

25%、50% 和 75% 等简单百分比与分母为 100 的分数相联系。学生通过取一半来求 240 的 50%,得到 120。


6. Measurement | 测量

d time. Learners convert between units, for example 1.5 km = 1 500 m and 2.3 kg = 2 300 g.

练习册5涵盖长度、质量、容量与时间。学生进行单位换算,例如 1.5 千米 = 1 500 米,2.3 千克 = 2 300 克。

angle is found using length × width, and perimeter is the total distance around the shape.

长方形与组合图形的周长和面积开始引入。长方形面积用长 × 宽求得,周长是图形一周的总长度。

Time problems include 12-hour and 24-hour clock conversion. Learners calculate durations across hours and minutes, such as from 14:35 to 17:20.

时间问题包括 12 小时制与 24 小时制的转换。学生计算跨越小时和分钟的持续时间,例如从 14:35 到 17:20。


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7. Geometry: 2D and 3D Shapes | 几何:二维与三维图形

Learners classify 2D shapes by properties including side lengths, parallel sides, and angles. They distinguish between regular and irregular polygons.

学生根据边长、平行边和角度等性质对二维图形进行分类。他们区分正多边形与不规则多边形。

Angles are measured in degrees using a protractor. Acute angles are less than 90°, right angles equal 90°, and obtuse angles are between 90° and 180°.

角度使用量角器以度为单位测量。锐角小于 90°,直角等于 90°,钝角介于 90° 与 180° 之间。

3D shapes are described by faces, edges, and vertices. A cube has 6 faces, 12 edges, and 8 vertices, while a triangular prism has 5 faces, 9 edges, and 6 vertices.

三维图形用面、棱和顶点来描述。立方体有 6 个面、12 条棱和 8 个顶点,三棱柱有 5 个面、9 条棱和 6 个顶点。


8. Position and Movement | 位置与运动

Learners read and plot coordinates in the first quadrant. A point described as (3, 5) means 3 units along the horizontal axis and 5 units up the vertical axis.

学生阅读并在第一象限内绘制坐标。点 (3, 5) 表示沿水平轴移动 3 个单位,再沿垂直轴向上移动 5 个单位。

Translation, reflection, and rotation are introduced using grids. Learners describe movements using left, right, up, down, and quarter turns.

平移、反射和旋转通过方格纸引入。学生使用左、右、上、下和四分之一圈来描述运动。

Symmetry is explored in 2D shapes. A square has four lines of symmetry, while a rectangle has two, unless it is a square.

对称性在二维图形中得到探索。正方形有四条对称轴,而长方形有两条,除非它是正方形。


9. Data Handling and Statistics | 数据处理与统计

Learners collect, organise, and interpret data using frequency tables, pictograms, bar charts, and line graphs. They choose an appropriate scale for each axis.

学生使用频率表、象形图、条形图和折线图来收集、整理与解释数据。他们为每个坐标轴选择合适的刻度。

The mode is identified as the most frequent value in a data set. Learners also compare data by reading values directly from charts and tables.

众数是数据集中出现频率最高的值。学生通过直接读取图表和表格中的数值来比较数据。

Simple probability language is introduced, such as certain, likely, unlikely, and impossible. Learners may use spinners or dice to explore outcomes.

简单的概率语言被引入,例如确定、可能、不太可能与不可能。学生可以使用转盘或骰子来探索结果。


10. Problem Solving and Investigations | 问题解决与探究

The workbook includes regular problem-solving tasks that require learners to apply multiple skills. They are encouraged to draw diagrams, make lists, or work backwards.

练习册包含常规的问题解决任务,要求学生综合运用多种技能。鼓励学生画图、列表或逆向推理。

Investigations often have more than one possible answer. Learners are expected to explain their thinking and justify their solutions using mathematical language.

探究活动通常有不止一个可能的答案。学生需要用数学语言解释自己的思路并证明解答的合理性。

Collaborative tasks help learners discuss strategies and compare methods. This reduces reliance on memorisation and builds deeper understanding.

合作任务帮助学生讨论策略并比较方法。这减少了对死记硬背的依赖,并建立更深层次的理解。


11. How to Use This Workbook Effectively | 如何有效使用本练习册

Complete each unit only after reviewing the corresponding Learner's Book topic. Attempt the questions without looking at the answers first, then check and correct mistakes in a different colour.

在复习《Learner's Book》中对应主题后,再完成每个单元。先尝试独立作答,不要看答案,然后用不同颜色检查和订正错误。

Keep a simple error log to record the type of mistake and the correct method. This helps identify patterns, such as place value errors or fraction misconceptions.

建立一个简单的错题记录,记下错误类型与正确方法。这有助于发现一些模式,例如位值错误或分数误解。

Use the investigations to talk about maths at home or with classmates. Explaining a solution to someone else is one of the strongest ways to consolidate learning.

利用探究活动在家中或与同学讨论数学。向他人解释解决方案是巩固学习最有效的方式之一。


12. Assessment and Exam Tips | 评估与考试技巧

Before an assessment, review the key facts in each unit: place value, multiplication tables, fraction equivalents, and measurement conversions. Use flashcards for quick recall.

评估前复习各单元的关键知识点:位值、乘法表、等值分数和测量换算。使用闪卡帮助快速回忆。

Read word problems twice and underline the important numbers and question words. Show every step of working, even if the answer is correct mentally.

应用题读两遍,并在重要数字和问题关键词下划线。即便心里已算出答案,也要展示每一步计算过程。

xample, 293 + 614 should be close to 300 + 600 = 900, so an answer near 907 is reasonable.

使用逆运算或估算检查答案。例如 293 + 614 应接近 300 + 600 = 900,因此答案 907 是合理的。

Published by TutorHao | Mathematics Revision Series | aleveler.com

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