📚 Circles | AQA A-Level数学第6章:圆
In AQA A-Level Mathematics Chapter 6, circles are studied within coordinate geometry. You need to find centres and radii, complete the square, solve intersections with lines, and use the tangent-radius property accurately.
在 AQA A-Level 数学第6章中,圆属于坐标几何的重要内容。你需要能够求圆心和半径、通过配方法化一般式为标准式、求直线与圆的交点,并准确运用切线与半径垂直的性质。
1. The Standard Equation of a Circle | 圆的标准方程
A circle is the set of points at a fixed distance r from a fixed centre (a, b).
圆是到定点 (a, b) 的距离等于定长 r 的所有点的集合。
(x - a)² + (y - b)² = r²
The values a and b are the x- and y-coordinates of the centre, and r is the radius.
a 和 b 分别是圆心的 x 坐标和 y 坐标,r 是半径。
If the centre is at the origin, the equation simplifies to x² + y² = r².
如果圆心在原点,方程简化为 x² + y² = r²。
2. Centre and Radius by Inspection | 通过观察求圆心和半径
When the equation is given in standard form, the centre is (a, b) and the radius is r, not r².
当方程以标准形式给出时,圆心为 (a, b),半径为 r,而不是 r²。
For (x - 3)² + (y + 2)² = 16, the centre is (3, -2) and the radius is √16 = 4.
例如 (x - 3)² + (y + 2)² = 16,圆心为 (3, -2),半径为 √16 = 4。
brackets because (x - a) means the centre has x-coordinate a, while (x + 2) means a = -2.
注意:括号内会出现符号变化,因为 (x - a) 表示圆心的 x 坐标为 a,而 (x + 2) 表示 a = -2。
3. Completing the Square | 配方法
e expanded equation x² + y² + 2gx + 2fy + c = 0 can be rewritten by completing the square.
展开式 x² + y² + 2gx + 2fy + c = 0 可以通过配方法重写。
x² + y² + 2gx + 2fy + c = 0 → (x + g)² + (y + f)² = g² + f² - c
Complete the square on x² + y² - 6x + 4y - 12 = 0.
对 x² + y² - 6x + 4y - 12 = 0 配方。
ms and y terms: (x² - 6x) + (y² + 4y) = 12, then add the required constants to both sides.
首先将 x 项和 y 项分组:(x² - 6x) + (y² + 4y) = 12,然后在等式两边加上所需常数。
(x - 3)² + (y + 2)² = 25, so the centre is (3, -2) and the radius is 5.
(x - 3)² + (y + 2)² = 25,所以圆心为 (3, -2),半径为 5。
4. General Form and Conditions | 一般式与条件
gx + 2fy + c = 0 with the completed square form to identify the centre (-g, -f) and radius √g² + f² - c.
将一般式 x² + y² + 2gx + 2fy + c = 0 与配方式进行比较,可以确定圆心 (-g, -f) 和半径 √g² + f² - c。
The general form requires g² + f² - c > 0 for a real circle. If it equals 0 the circle has zero radius at a single point; if negative, no real circle exists.
一般式要求 g² + f² - c > 0 才表示实圆。若等于 0,则圆退化为一个点;若小于 0,则不存在实圆。
| Form | Equation | Centre | Radius |
| Standard form | (x - a)² + (y - b)² = r² | (a, b) | r |
| Centre at origin | x² + y² = r² | (0, 0) | r |
| General form | x² + y² + 2gx + 2fy + c = 0 | (-g, -f) | √g² + f² - c |
Always check the sign of g² + f² - c before stating a radius in a general-form question.
在一般式问题中,写出半径前一定要检查 g² + f² - c 的符号。
5. Points and Circles | 点与圆的位置关系
To classify a point P(x₁, y₁), substitute its coordinates into the left-hand side of the circle equation, or compare the distance from the centre to the radius.
要判断点 P(x₁, y₁) 的位置,可将其坐标代入圆的方程左边,或比较该点到圆心的距离与半径。
d² = (x₁ - a)² + (y₁ - b)²
f d² < r² the point is inside; if d² = r² it lies on the circle; if d² > r² it is outside.
若 d² < r²,点在圆内;若 d² = r²,点在圆上;若 d² > r²,点在圆外。
This comparison is useful when proving whether a point lies on a given circle or when checking a tangent point.
这种比较在证明点是否在给定圆上或检验切点时非常有用。
6. Line and Circle Intersections | 直线与圆的交点
Substitute the line equation into the circle equation to obtain a quadratic in one variable.
将直线方程代入圆的方程,得到关于一个变量的二次方程。
Use the discriminant of the resulting quadratic to determine the number of intersections.
利用所得二次方程的判别式来确定交点个数。
Δ = b² - 4ac
ct intersection points; if Δ = 0, the line is tangent; if Δ < 0, there is no intersection.
若 Δ > 0,有两个不同的交点;若 Δ = 0,直线为切线;若 Δ < 0,没有交点。
This method is the standard approach for finding where lines cut circles and for proving tangency conditions.
这是求直线与圆交点以及证明相切条件的标准方法。
7. Tangent-Radius Property | 切线与半径的性质
The radius from the centre to a point of contact is perpendicular to the tangent at that point.
从圆心到切点的半径与该点的切线垂直。
For a circle centre (a, b) and a point P(x₁, y₁) on the circle, the gradient of the radius is (y₁ - b) / (x₁ - a).
对于圆心为 (a, b) 且点 P(x₁, y₁) 在圆上,半径的斜率为 (y₁ - b) / (x₁ - a)。
m(radius) = (y₁ - b) / (x₁ - a), m(tangent) = -(x₁ - a) / (y₁ - b)
The tangent gradient is the negative reciprocal of the radius gradient, provided the radius is not vertical.
切线斜率是半径斜率的负倒数,前提是半径不垂直于 x 轴。
8. Finding Tangent Equations | 求切线方程
Find the tangent to (x - 2)² + (y + 1)² = 10 at P(5, -2).
求圆 (x - 2)² + (y + 1)² = 10 在点 P(5, -2) 处的切线。
irst identify the centre (2, -1). The gradient of the radius is (-2 + 1) / (5 - 2) = -1/3.
首先确定圆心 (2,
Published by TutorHao | A-Level Mathematics Revision Series | aleveler.com
更多咨询请联系16621398022(同微信)

或截图后用「扫一扫 → 相册」选择本图