📚 The General Complex Number | 一般复数
part x and an imaginary part y, and it can be added, subtracted, multiplied and divided just like an algebraic expression, with i² replaced by −1 whenever it appears. This revision article covers the AQA A-Level Further Mathematics content on the general complex number, including its Cartesian form, conjugate, modulus, argument, polar form and basic loci.
复数在求解诸如 x² + 1 = 0 这样的二次方程时自然出现。由于没有任何实数的平方为负,数学家引入了虚数单位 i,其定义性质为 i² = −1。一般复数 z = x + iy 将实部 x 与虚部 y 结合起来,它可以像代数式一样进行加、减、乘、除运算,只要在出现 i² 时将其替换为 −1。本篇复习文章涵盖 AQA A-Level 高等数学中关于一般复数的内容,包括笛卡尔形式、共轭、模、辐角、极坐标形式与基本轨迹。
1. The Imaginary Unit and the General Form | 虚数单位与一般形式
al numbers. This is called Cartesian form because it separates the real direction from the imaginary direction.
虚数单位 i 的定义是 i² = −1。它不是一个实数,因此它扩展了实数系。i 的幂以 4 为周期循环:i¹ = i,i² = −1,i³ = −i,i⁴ = 1。之后规律重复,所以 i⁵ = i,i⁶ = −1 等等。一般复数写作 z = x + iy,其中 x 和 y 都是实数。这种形式称为笛卡尔形式,因为它把实方向与虚方向分离开来。
2. Real and Imaginary Parts | 实部与虚部
is purely imaginary. If z = 7, then Re(z) = 7 and Im(z) = 0, so the number is purely real.
对于复数 z = x + iy,实部为 Re(z) = x,虚部为 Im(z) = y。注意虚部是系数 y,而不是 iy。例如,若 z = 3 − 4i,则 Re(z) = 3,Im(z) = −4。若 z = 2i,则 Re(z) = 0,Im(z) = 2,所以该数为纯虚数。若 z = 7,则 Re(z) = 7,Im(z) = 0,所以该数为纯实数。
3. Equality of Complex Numbers | 复数相等
we can equate real parts: x + y = 3, and imaginary parts: x − y = 1. Solving simultaneously gives x = 2 and y = 1.
两个复数相等,当且仅当它们的实部相等且虚部相等。用符号表示,a + ib = c + id 当且仅当 a = c 且 b = d。这一原理在求解含有未知实部和虚部的方程时非常有用。例如,若 (x + y) + i(x − y) = 3 + i,则我们可以令实部相等:x + y = 3,令虚部相等:x − y = 1。联立解得 x = 2,y = 1。
4. Addition, Subtraction and Scalar Multiplication | 加法、减法与数乘
k gives kz₁ = ka + ikb. For example, (2 + 3i) + (1 − 4i) = 3 − i, and 3(2 + 3i) = 6 + 9i.
复数的加法和减法按分量分别进行。若 z₁ = a + ib,z₂ = c + id,则 z₁ + z₂ = (a + c) + i(b + d),z₁ − z₂ = (a − c) + i(b − d)。用实数 k 进行数乘得到 kz₁ = ka + ikb。例如,(2 + 3i) + (1 − 4i) = 3 − i,3(2 + 3i) = 6 + 9i。
5. Multiplication of Complex Numbers | 复数乘法
+ i(ad + bc). For example, (2 + 3i)(1 − 4i) = 2 − 8i + 3i − 12i² = 2 − 5i + 12 = 14 − 5i.
两个复数相乘时,先用分配律展开括号,再将 i² 替换为 −1。若 z₁ = a + ib,z₂ = c + id,则 z₁z₂ = (a + ib)(c + id) = ac + iad + ibc + i²bd = (ac − bd) + i(ad + bc)。例如,(2 + 3i)(1 − 4i) = 2 − 8i + 3i − 12i² = 2 − 5i + 12 = 14 − 5i。
6. The Complex Conjugate | 复共轭
Im(z), and zz* = x² + y². The last result is particularly important because it is equal to |z| duct of the conjugates, and the conjugate of a quotient is the quotient of the conjugates.
复数 z = x + iy 的共轭记作 z*,定义为 z* = x − iy。从几何上看,共轭是 z 在阿尔冈图中关于实轴的反射。关键性质包括 z + z* = 2Re(z),z − z* = 2i Im(z),以及 zz* = x² + y²。最后一个结果特别重要,因为它等于 |z|²,即 z 的模的平方。和的共轭等于共轭的和,积的共轭等于共轭的积,商的共轭等于共轭的商。
7. Division of Complex Numbers | 复数除法
, (3 + 2i) ÷ (1 − i) = [(3 + 2i)(1 + i)] ÷ [(1 − i)(1 + i)] = (1 + 5i) ÷ 2 = 1/2 + (5/2)i.
两个复数相除时,把分子和分母同时乘以分母的共轭。这样可以使分母变为实数。一般地, (c + id) = [(a + ib)(c − id)] ÷ [(c + id)(c − id)] = [(ac + bd) + i(bc − ad)] ÷ (c² + d²)。例如,(3 + 2i) ÷ (1 − i) = [(3 + 2i)(1 + i)] ÷ [(1 − i)(1 + i)] = (1 + 5i) ÷ 2 = 1/2 + (5/2)i。
8. The Argand Diagram and Modulus | 阿尔冈图与模
s. The complex number z = x + iy is plotted as the point (x, y). The modulus of z, written |z|, is the distance from the origin to that point. It is calculated using |z| = √x² + y². For example, |3 − 4i| = √(3² + (−4)²) = √25 = 5. The modulus is always a non-negative real number.
阿尔冈图把复数表示为平面上的点。横轴是实轴,纵轴是虚轴。复数 z = x + iy 画作点 (x, y)。z 的模记作 |z|,是原点到该点的距离,计算公式为 |z| = √x² + y²。例如,|3 − 4i| = √(3² + (−4)²) = √25 = 5。模始终是非负实数。
Important modulus properties are |z₁z₂| = |z₁||z₂| and |z₁ ÷ z₂| = |z₁| ÷ |z₂| er z₂ ≠ 0. These are used to simplify expressions and to solve equations involving moduli.
重要的模性质有 |z₁z₂| = |z₁||z₂|,以及当 z₂ ≠ 0 时,|z₁ ÷ z₂| = |z₁| ÷ |z₂|。这些性质可用于化简表达式和求解含有模的方程。
9. Argument and Principal Argument | 辐角与主辐角
ent, often written Arg z with a capital A, is usually chosen in the interval (−π, π]. For example, arg(1 + i) = π/4, arg(−1 + i) = 3π/4, and arg(−1 − i) = −3π/4 under this convention.
非零复数 z 的辐角记作 arg z,是从正实轴到阿尔冈图中原点到点 z 的连线所成的角。若 z = x + iy,则 tan θ = y/x,但必须考虑点 (x, y) 所在的象限才能确定正确的角。主辐角通常记作 Arg z(首字母大写),一般取在区间 (−π, π] 内。例如,arg(1 + i) = π/4,arg(−1 + i) = 3π/4,在该约定下 arg(−1 − i) = −3π/4。
10. Modulus-Argument Form and Euler's Formula | 模-辐角形式与欧拉公式
Any non-zero complex number can be written in modulus-argument form, also called
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