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Mastering Quadratic Equations for IGCSE Mathematics | IGCSE 数学二次方程全攻略

2026-08-21 16:12 · 本文部分内容由AI辅助创作

📚 Mastering Quadratic Equations for IGCSE Mathematics | IGCSE 数学二次方程全攻略

Quadratic equations are one of the most important topics in IGCSE Mathematics. They appear in algebra, graphs, inequalities and real-life modelling, so a strong understanding can boost your confidence in multiple exam questions. This article explains the key methods, common pitfalls and exam strategies for quadratics.

二次方程是 IGCSE 数学中最重要的主题之一。它们出现在代数、图像、不等式和实际建模中,因此扎实的理解能增强你在多类考题中的信心。本文讲解二次方程的核心方法、常见错误与应试策略。


1. What Is a Quadratic Equation? | 什么是二次方程?

c = 0, where a, b and c are constants and a ≠ 0. The highest power of the unknown x is 2.

一元二次方程是任何可以写成一般形式 ax² + bx + c = 0 的方程,其中 a、b、c 为常数且 a ≠ 0。未知数 x 的最高次数为 2。

ather than quadratic, because the x² term disappears. Quadratic equations can have two distinct real roots, one repeated real root, or no real roots, depending on the value of the discriminant.

如果 a = 0,方程就变成一次方程,而不是二次方程,因为 x² 项消失了。二次方程可以有两个不同的实根、一个重根或没有实根,这取决于判别式的值。

In IGCSE exams, you will often be asked to solve quadratics, sketch their graphs, use the discriminant, or model a practical situation with a quadratic equation. Recognising the type of quadratic and choosing the most efficient method is a key exam skill.

在 IGCSE 考试中,你经常会被要求解二次方程、画其图像、使用判别式,或用二次方程对实际情形进行建模。识别二次方程的类型并选择最有效的方法是关键的应试技巧。


2. Standard Form and Key Terms | 标准形式与关键术语

cting all terms on one side and setting the other side equal to zero. This step is essential for factorising, using the formula, and identifying a, b and c correctly.

在求解任何二次方程之前,一定要把方程整理成标准形式 ax² + bx + c = 0。这意味着将所有项移到一边,并令另一边等于零。这一步对于因式分解、使用公式以及正确识别 a、b、c 至关重要。

he equation is given as 4x² = 9, first rewrite it as 4x² − 9 = 0 so that c = −9 and b = 0.

系数 a 是二次项系数,b 是一次项系数,c 是常数项。例如,在 3x² − 5x + 2 = 0 中,a = 3,b = −5,c = 2。如果方程给出为 4x² = 9,首先要改写为 4x² − 9 = 0,这样 c = −9,b = 0。

anded to x² + 3x − 4 = 0. Always expand brackets and simplify before deciding on a method.

有些方程一开始看起来不像二次方程。例如,x(x + 3) = 4 可以展开为 x² + 3x − 4 = 0。在决定方法之前,一定要先展开括号并化简。


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3. Solving by Factorising | 因式分解法

rised as (x + p)(x + q) = 0, use the zero product property: either x + p = 0 or x + q = 0.

当二次式可以写成两个一次括号的乘积时,因式分解法非常有效。对于 x² + bx + c = 0 形式的二次式,寻找两个数,使它们相乘等于 c,相加等于 b。一旦分解为 (x + p)(x + q) = 0,就利用零积性质:要么 x + p = 0,要么 x + q = 0。

3) × (−4) = 12 and (−3) + (−4) = −7. Therefore, (x − 3)(x − 4) = 0, giving x = 3 or x = 4.

例如,解 x² − 7x + 12 = 0 时,找两个相乘得 +12、相加得 −7 的数。−3 和 −4 符合,因为 (−3) × (−4) = 12 且 (−3) + (−4) = −7。因此 (x − 3)(x − 4) = 0,得到 x = 3 或 x = 4。

comes 2x(x + 1) + 3(x + 1) = (2x + 3)(x + 1) = 0. The solutions are x = −3 ÷ 2 and x = −1.

当 a ≠ 1 时,你可能需要拆项或使用分组法。对于 2x² + 5x + 3 = 0,将 5x 拆成 2x + 3x,于是表达式变为 2x(x + 1) + 3(x + 1) = (2x + 3)(x + 1) = 0。解为 x = −3 ÷ 2 和 x = −1。

Always check your factorisation by expanding the brackets mentally. A common mistake is to set each bracket equal to the original constant instead of zero, so remember that after factorising, each bracket must equal zero.

始终通过心算展开括号来检查因式分解是否正确。一个常见错误是把每个括号等于原来的常数而不是零,所以要记住,因式分解后,每个括号必须等于零。


4. Solving by Completing the Square | 配方法

Completing the square transforms ax² + bx + c into the form a(x + p)² + q. This method is useful when factorising is difficult, and it is especially important for finding the turning point of a quadratic graph.

配方法将 ax² + bx + c 转化为 a(x + p)² + q 的形式。当因式分解困难时,这种方法非常有用,而且它对于求二次图像顶点尤为重要。

bx = (x + b/2)² − (b/2)². This keeps the value unchanged while creating a perfect square.

对于表达式 x² + bx,加减 (b ÷ 2)² 即可完成配方。一般地,x² + bx = (x + b/2)² − (b/2)²。这样可以在保持值不变的同时构造一个完全平方。

to solve x² + 6x + 1 = 0, take half of 6, which is 3, and square it to get 9. Rewrite the

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