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Quadratic Equations: Solving, Graphing and Applications | 二次方程:求解、图像与应用

2026-08-21 15:54 · 本文部分内容由AI辅助创作

📚 Quadratic Equations: Solving, Graphing and Applications | 二次方程:求解、图像与应用

Quadratic equations are one of the most important topics in IGCSE Mathematics. They appear in algebra, coordinate geometry, and real-world modelling, so a confident command of their solution methods and graphs is essential for exam success.

二次方程是 IGCSE 数学中最重要的主题之一。它出现在代数、坐标几何和现实建模中,因此熟练掌握其解法与图像对考试成功至关重要。


1. What Is a Quadratic Equation? | 什么是二次方程?

ways be arranged into the form ax² + bx + c = 0, where a, b and c are constants and a ≠ 0.

二次方程是变量最高次数为 2 的多项式方程。它总可以整理成 ax² + bx + c = 0 的形式,其中 a、b、c 为常数且 a ≠ 0。

3x − 2 = 0 are quadratic equations. If a = 0, the equation becomes linear, not quadratic.

例如,x² − 5x + 6 = 0 和 2x² + 3x − 2 = 0 都是二次方程。如果 a = 0,方程就变成一次方程,而不是二次方程。


2. Standard Form and Coefficients | 标准式与系数

all terms to one side so that the other side is 0. The standard form is ax² + bx + c = 0.

在求解二次方程之前,应把所有项移到一边,使另一边为 0。标准形式为 ax² + bx + c = 0。

Identifying these correctly is vital when using the quadratic formula or the discriminant.

在方程 3x² − 7x + 2 = 0 中,系数为 a = 3、b = −7、c = 2。正确识别这些系数在使用求根公式或判别式时非常重要。


3. Solving by Factorising | 因式分解法求解

a product of two linear factors. The key principle is: if p × q = 0, then p = 0 or q = 0.

当二次式可以写成两个一次因式的乘积时,因式分解是最快的方法。其核心原理是:若 p × q = 0,则 p = 0 或 q = 0。

3) = 0, then set each factor equal to zero: x − 2 = 0 or x − 3 = 0, giving x = 2 or x = 3.

例题:解 x² − 5x + 6 = 0。因式分解为 (x − 2)(x − 3) = 0,然后令每个因式等于零:x − 2 = 0 或 x − 3 = 0,得 x = 2 或 x = 3。

d error. For 2x² + 3x − 2 = 0, factorise to (2x − 1)(x + 2) = 0, giving x = 1/2 or x = −2.

当 a ≠ 1 时,可使用拆中项法或试探法。例如 2x² + 3x − 2 = 0,因式分解为 (2x − 1)(x + 2) = 0,得 x = 1/2 或 x = −2。


4. Solving by Completing the Square | 配方法求解

s especially useful when factorising is difficult or when you need to find the turning point of a graph.

配方法将二次式改写为 (x + p)² = q 的形式。当因式分解困难或需要求图像的顶点时,这一方法尤为有用。

² + 6x + 2 = 0, complete the square: x² + 6x + 9 = 7, so (x + 3)² = 7. Therefore x + 3 = ±√7, giving x = −3 ± √7.

对于 x² + 6x + 2 = 0,配方:x² + 6x + 9 = 7,所以 (x + 3)² = 7。因此 x + 3 = ±√7,得 x = −3 ± √7。

If the coefficient of x² is not 1, divide through by that coefficient first. Completing the square also leads directly to the quadratic formula.

如果 x² 的系数不是 1,先除以该系数。配方法还可直接推导出求根公式。


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5. The Quadratic Formula | 求根公式

The quadratic formula solves any quadratic equation ax² + bx + c = 0. It is given by:

求根公式可以解任何二次方程 ax² + bx + c = 0。公式如下:

x = (−b ± √b² − 4ac) / (2a)

Example: solve 3x² − 7x + 2 = 0. Here a = 3, b = −7, c = 2. Substitute:

例题:解 3x² − 7x + 2 = 0。这里 a = 3、b = −7、c = 2。代入公式:

x = (7 ± √49 − 24) / 6 = (7 ± 5) / 6

is method always works, including when the roots are irrational or complex at advanced level.

因此 x = (7 + 5)/6 = 2 或 x = (7 − 5)/6 = 1/3。该方法始终有效,即使根是无理数(在更高阶段还包括复数根)。


6. The Discriminant | 判别式

= b² − 4ac tells you how many real solutions a quadratic equation has without solving it.

判别式 D = b² − 4ac 可以在不求根的情况下判断二次方程有多少个实数解。

Discriminant | 判别式Number of real roots | 实数根个数
D > 0Two distinct real roots | 两个不相等的实根
D = 0One repeated real root | 一个重根
D < 0No real roots | 无实根

r example, x² − 4x + 4 = 0 has D = (−4)² − 4(1)(4) = 0, so it has one repeated root x = 2.

例如,x² − 4x + 4 = 0 的判别式 D = (−4)² − 4(1)(4) = 0,因此它有一个重根 x = 2。


7. Graphs of Quadratic Functions | 二次函数图像

. If a > 0, the parabola opens upward and has a minimum point. If a < 0, it opens downward and has a maximum point.

y = ax² + bx + c 的图像是一条抛物线。如果 a > 0,抛物线开口向上且有

Published by TutorHao | IGCSE Mathematics Revision Series | aleveler.com

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