← 返回资讯屏轩教育 · 行业资讯

Mastering Quadratic Equations and Graphs for IGCSE Mathematics | 掌握 IGCSE 数学二次方程与图像

2026-08-21 15:49 · 本文部分内容由AI辅助创作

📚 Mastering Quadratic Equations and Graphs for IGCSE Mathematics | 掌握 IGCSE 数学二次方程与图像

Quadratic equations are a central topic in IGCSE Mathematics, bridging algebra, coordinate geometry and real-world problem solving. A confident grasp of factorising, using the quadratic formula, and interpreting graphs will help you tackle a wide range of exam questions.

二次方程是 IGCSE 数学的核心主题,连接了代数、坐标几何和现实问题解决。熟练掌握因式分解、二次公式以及图像解读,能帮助你应对各种考试题型。

1. What is a Quadratic Expression? | 什么是二次表达式?

A quadratic expression is any algebraic expression of the form ax² + bx + c, where a, b and c are constants and a ≠ 0.

二次表达式是形如 ax² + bx + c 的代数式,其中 a、b、c 为常数且 a ≠ 0。

r bx + c, so the condition a ≠ 0 is essential. In IGCSE exams, a quadratic expression is usually written with descending powers of x, but it may appear in different orders.

如果 a = 0,表达式就变成一次式 bx + c,因此 a ≠ 0 这个条件至关重要。在 IGCSE 考试中,二次表达式通常按 x 的降幂书写,但也可能以不同顺序出现。

Common examples include x² + 5x + 6, 2x² − 3x + 1 and −x² + 4x. The coefficient a controls the shape and direction of the related parabola.

常见例子包括 x² + 5x + 6、2x² − 3x + 1 和 −x² + 4x。系数 a 控制相应抛物线的形状和开口方向。


2. Expanding and Factorising Quadratics | 二次式的展开与因式分解

Expanding two binomials such as (x + p)(x + q) gives x² + (p+q)x + pq. This is the foundation of many IGCSE algebraic manipulations.

展开两个二项式如 (x + p)(x + q) 得到 x² + (p+q)x + pq。这是许多 IGCSE 代数运算的基础。

(x + p)(x + q) = x² + (p + q)x + pq

umbers with sum 7 and product 10, namely 2 and 5. Therefore x² + 7x + 10 = (x + 2)(x + 5).

因式分解是这个过程的逆运算:要因式分解 x² + 7x + 10,需要找到两个数,使它们的和为 7、积为 10,即 2 和 5。因此 x² + 7x + 10 = (x + 2)(x + 5)。

For example, x² − 5x + 6 factorises as (x − 2)(x − 3), because −2 and −3 add to −5 and multiply to 6. When a ≠ 1, use methods such as splitting the middle term or trial and error.

例如,x² − 5x + 6 因式分解为 (x − 2)(x − 3),因为 −2 和 −3 相加为 −5、相乘为 6。当 a ≠ 1 时,可使用拆分中项或试错法。


广告 / Sponsored

3. Solving Quadratic Equations by Factorising | 用因式分解解二次方程

To solve x² + 5x + 6 = 0, first factorise the left-hand side to (x + 2)(x + 3) = 0.

要解 x² + 5x + 6 = 0,先将左边因式分解为 (x + 2)(x + 3) = 0。

ways set the equation to zero first; do not divide by x unless you are certain that x ≠ 0.

因为乘积为零当且仅当至少一个因式为零,所以令 x + 2 = 0 或 x + 3 = 0,得 x = −2 或 x = −3。务必先将方程整理为零;除非确定 x ≠ 0,否则不要直接除以 x。

. This type of equation appears frequently because students sometimes miss the root x = 0.

例:x² − 7x = 0 因式分解为 x(x − 7) = 0,得 x = 0 或 x = 7。这类方程经常出现,因为学生有时会漏掉 x = 0 这个根。


4. The Quadratic Formula | 二次公式

ed easily, use the quadratic formula. It solves any equation of the form ax² + bx + c = 0.

当二次式不易因式分解时,可使用二次公式。该公式可解任何形如 ax² + bx + c = 0 的方程。

x = (−b ± √b² − 4ac) ÷ 2a

a = 2, b = 3, c = −2. Substituting gives x = (−3 ± √(3² − 4 × 2 × (−2))) ÷ (2 × 2) = (−3 ± √9 + 16) ÷ 4 = (−3 ± 5) ÷ 4.

例:解 2x² + 3x − 2 = 0。这里 a = 2,b = 3,c = −2。代入得 x = (−3 ± √(3² − 4 × 2 × (−2))) ÷ (2 × 2) = (−3 ± √9 + 16) ÷ 4 = (−3 ± 5) ÷ 4。

n IGCSE exams, the quadratic formula is especially useful when coefficients are not integers or the expression does not factorise neatly.

因此 x = 2/4 = 1/2 或 x = −8/4 = −2。在 IGCSE 考试中,当系数不是整数或表达式不易分解时,二次公式尤其有用。


Published by TutorHao | IGCSE Mathematics Revision Series | aleveler.com

广告 / Sponsored
【现货】剑桥国际高中教材 Cambridge IGCSE & O Level Additional Mathemati…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥198.0

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao