📚 Solving Quadratic Equations by Factorising, Completing the Square and the Quadratic Formula | 二次方程求解：因式分解、配方法与求根公式
n this revision guide, you will learn three core methods for solving quadratics: factorising, completing the square, and using the quadratic formula. You will also explore the discriminant, graphical meaning, and common exam pitfalls.
二次方程贯穿 IGCSE 数学课程始终，从代数运算到图像绘制和实际问题建模都会出现。二次方程的一般形式为 ax² + bx + c = 0，其中 a ≠ 0。本复习指南将学习三种核心求解方法：因式分解法、配方法和求根公式法。同时还会探讨判别式、图像意义以及常见的考试陷阱。
1. What is a Quadratic Equation? | 什么是二次方程？
re a, b and c are constants and a cannot be zero. If a were zero, the equation would become linear. Quadratic equations can have two real solutions, one repeated solution, or no real solutions depending on the discriminant.
如果未知数的最高次数是 2，则该方程为二次方程。标准形式为 ax² + bx + c = 0，其中 a、b、c 为常数且 a 不能为零。若 a 为零，方程就变成一次方程。二次方程可能有两个实数解、一个重根或没有实数解，这取决于判别式。
Some examples of quadratic equations are shown below. Notice that each equation can be rearranged into the standard form with a non-zero coefficient of x².
以下是一些二次方程的例子。请注意，每个方程都可以整理成标准形式，且 x² 的系数不为零。
- 2x² + 3x − 5 = 0
- x² − 4x + 4 = 0
- 3x² + x + 7 = 0
These equations all have degree 2, even if some terms are missing or the coefficients are negative.
这些方程的次数都是 2，即使某些项缺失或系数为负数也是如此。
2. Standard Form and Key Terms | 标准形式与关键术语
tions to the equation are also called roots or x-intercepts of the graph y = ax² + bx + c.
在求解之前，一定要把方程整理成标准形式 ax² + bx + c = 0。系数 a 是二次项系数，b 是一次项系数，c 是常数项。方程的解也叫作根，或者图像 y = ax² + bx + c 的 x 轴截距。
ding coefficient a tells you whether the parabola opens upwards or downwards, while c gives the y-intercept of the graph.
例如，在方程 2x² − 5x + 3 = 0 中，a = 2，b = −5，c = 3。首项系数 a 决定抛物线开口向上还是向下，而 c 给出图像与 y 轴的截距。
Remember that rearranging terms is often necessary. You may need to bring all terms to one side, combine like terms, and place them in descending powers of x.
请记住，经常需要整理项。你可能需要把所有项移到一边，合并同类项，并按 x 的降幂排列。
3. Solving by Factorising | 因式分解法
rite (x + p)(x + q) = 0 and use the zero product property: if AB = 0, then A = 0 or B = 0.
当二次式可以写成两个一次因式的乘积时，因式分解法最快。对于 x² + bx + c，寻找两个数 p 和 q，使得 p + q = b 且 pq = c。然后写成 (x + p)(x + q) = 0，并利用零乘积性质：如果 AB = 0，则 A = 0 或 B = 0。
Example: x² + 5x + 6 = (x + 2)(x + 3) = 0 ⇒ x = −2 or x = −3
In this example, the numbers 2 and 3 add to 5 and multiply to 6. Writing the equation as a product of two factors allows us to set each factor equal to zero and solve directly.
在这个例子中，2 和 3 相加为 5，相乘为 6。把方程写成两个因式的乘积后，就可以令每个因式等于零并直接求解。
Always check your factorisation by expanding the brackets. This will confirm that the product matches the original quadratic expression.
一定要通过展开括号来检验因式分解。这样可以确认乘积与原来的二次式一致。
4. Factorising When a > 1 | 当二次项系数大于 1 的因式分解
to 7: these are 6 and 1. Write 2x² + 6x + x + 3 = 2x(x + 3) + 1(x + 3) = (2x + 1)(x + 3).
对于 ax² + bx + c 且 a > 1 的二次式，因式分解需要找到两个数，它们的乘积等于 ac，和等于 b。拆开一次项后分组分解，再提取公因式。例如：2x² + 7x + 3。我们需要两个数乘积为 6、和为 7，这两个数是 6 和 1。写出 2x² + 6x + x + 3 = 2x(x + 3) + 1(x + 3) = (2x + 1)(x + 3)。
The ac method is reliable but takes practice. Another approach is trial and error with the possible factors of a and c, checking each combination until the middle coefficient is correct.
ac 法可靠但需要练习。另一种方法是尝试 a 和 c 的可能因数组合，逐一检验，直到一次项系数正确为止。
e same: set each factor equal to zero. For (2x + 1)(x + 3) = 0, we get x = −1/2 or x = −3.
一旦完成因式分解，求解方法完全相同：令每个因式等于零。对于 (2x + 1)(x + 3) = 0，得到 x = −1/2 或 x = −3。
5. Solving by Completing the Square | 配方法
, add (6/2)² = 9 to both sides, giving (x + 3)² = 4. Then x + 3 = ±2, so x = −1 or x = −5.
配方法把二次式改写为 (x + p)² + q = 0 的形式。从 x² + bx + c = 0 开始，将常数移到右边，两边同时加上 (b/2)²，把左边写成完全平方。例如，解 x² + 6x + 5 = 0：x² + 6x = −5，两边加上 (6/2)² = 9，得到 (x + 3)² = 4。于是 x + 3 = ±2，所以 x = −1 或 x = −5。
+ b/2)². This method is especially useful when the quadratic cannot be factorised easily or when you need to find the vertex of the parabola.
关键恒等式是 x² + bx + (b/2)² = (x + b/2)²。当二次式不容易因式分解，或者需要求抛物线顶点时，这种方法特别有用。
If the coefficient a is not 1, first divide every term by a, then complete the square. Do not forget to adjust the constant term accordingly.
如果系数 a 不为 1，先让每一项除以 a，然后再配方。不要忘记相应调整常数项。
6. The Quadratic Formula | 求根公式
x + c = 0. The formula is derived by completing the square on the general form. It states:
当因式分解困难或无法进行时，求根公式可以解任何二次方程 ax² + bx + c = 0。这个公式由配方法推导而来。它给出：
x = (−b ± √b² − 4ac) / (2a)
ues of a, b and c. For example, solve 2x² − 3x − 2 = 0: a = 2, b = −3, c = −2, so x = (3 ± √9 + 16) / 4 = (3 ± 5) / 4. This gives x = 2 or x = −1/2.
代入 a、b、c 的值即可。例如，解 2x² −
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