📚 8C Answers: Combinations, Pascal's Triangle and Binomial Expansion | 8C 答案：组合、帕斯卡三角与二项式展开
In mathematics, the notation 8C_r (read as '8 choose r' e in combinatorics, probability and the binomial expansion of (a + b)⁸. This article provides a complete set of 8C answers, explains how they are calculated, and shows how to use them confidently in exam questions.
在数学中，记号 8C_r（读作“8 选 r”）表示从 8 个不同对象中选出 r 个对象的方法数，并且选择顺序不重要。这些数值在组合数学、概率以及 (a + b)⁸ 的二项式展开中随处可见。本文给出完整的 8C 答案，解释它们的计算方法，并展示如何在考试题目中自信地使用这些答案。
1. What Does 8C Mean? | 8C 表示什么？
ient. It counts the number of unordered subsets of size r that can be formed from a set of 8 objects. For example, 8C₃ tells you how many different groups of 3 can be chosen from 8 people.
符号 8C_r 是一个二项式系数。它计算的是从 8 个对象中能组成多少个大小为 r 的无序子集。例如，8C₃ 告诉你从 8 个人中可以选出多少个不同的 3 人小组。
Because the order does not matter, choosing {A, B, C} is the same as choosing {C, A, B}. This is different from permutations, where order is counted separately.
因为顺序不重要，选择 {A, B, C} 与选择 {C, A, B} 是相同的。这与排列不同，排列会单独计算每一种顺序。
2. The Combination Formula for 8C_r | 8C_r 的组合公式
For any integer r from 0 to 8, the value of 8C_r is given by the factorial formula:
对于 0 到 8 之间的任意整数 r，8C_r 的值由阶乘公式给出：
8C_r = 8! / [r! × (8 - r)!]
Here, n! means n factorial, the product of all positive integers from 1 to n. For example, 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40320.
这里 n! 表示 n 的阶乘，即从 1 到 n 的所有正整数的乘积。例如，8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40320。
you can calculate any 8C_r value exactly. It also shows why 8C₀ = 1 and 8C₈ = 1, because 0! is defined as 1.
使用这个公式，你可以精确计算任意 8C_r 的值。它也能解释为什么 8C₀ = 1 且 8C₈ = 1，因为 0! 被定义为 1。
3. Full List of 8C_r Values | 8C_r 完整数值表
e of 8C_r answers is shown below. These values are symmetric and appear as a row in Pascal's triangle.
下面是 8C_r 的完整答案表。这些数值具有对称性，并出现在帕斯卡三角的一行中。
- 8C₀ = 1
- 8C₁ = 8
- 8C₂ = 28
- 8C₃ = 56
- 8C₄ = 70
- 8C₅ = 56
- 8C₆ = 28
- 8C₇ = 8
- 8C₈ = 1
70. This makes sense: there are more ways to choose exactly half of the objects than to choose very few or very many.
请注意，最大值是 8C₄ = 70。这是合理的：恰好选择一半对象的方法数，比选择很少或很多对象的方法数要多。
4. Symmetry Property of 8C_r | 8C_r 的对称性
One important property is symmetry: 8C_r = 8C8-r. This means 8C₁ = 8C₇, 8C₂ = 8C₆, and 8C₃ = 8C₅.
一个重要的性质是对称性：8C_r = 8C8-r。这意味着 8C₁ = 8C₇，8C₂ = 8C₆，8C₃ = 8C₅。
This occurs because choosing r objects to include is equivalent to choosing 8 - r objects to exclude. You can use this property to save time in calculations.
这是因为选出 r 个对象包含在内，等价于选出 8 - r 个对象排除在外。你可以利用这个性质节省计算时间。
5. Pascal's Triangle Row 8 | 帕斯卡三角第 8 行
The values 1, 8, 28, 56, 70, 56, 28, 8, 1 form the 8th row of Pascal's triangle. Each number is the sum of the two numbers directly above it.
数值 1、8、28、56、70、56、28、8、1 构成帕斯卡三角的第 8 行。每个数字都是其正上方两个数字之和。
Pascal's triangle provides a quick way to read off 8C answers without using the formula repeatedly. It also links directly to binomial coefficients in expansion.
帕斯卡三角提供了一种快速读取 8C 答案的方法，而不需要反复使用公式。它还与二项式展开中的系数直接相关。
6. Using 8C_r in Probability | 在概率中使用 8C_r
if you flip a fair coin 8 times, the number of sequences with exactly 3 heads is 8C₃ = 56.
在概率中，8C_r 经常作为有利结果数或总结果数出现。例如，如果你抛一枚公平硬币 8 次，恰好出现 3 次正面的序列数是 8C₃ = 56。
of possible outcomes is 2⁸ = 256, so the probability of exactly 3 heads is 56/256 = 7/32.
总可能结果数为 2⁸ = 256，因此恰好出现 3 次正面的概率为 56/256 = 7/32。
7. Binomial Expansion of (a + b)⁸ | (a + b)⁸ 的二项式展开
heorem states that (a + b)⁸ expands using 8C_r as the coefficients. The full expansion is:
二项式定理表明 (a + b)⁸ 的展开使用 8C_r 作为系数。完整展开式为：
(a + b)⁸ = a⁸ + 8a⁷b + 28a⁶b² + 56a⁵b³ + 70a⁴b⁴ + 56a³b⁵ + 28a²b⁶ + 8ab⁷ + b⁸
Each term has the form 8C_r × a8-r × br. The powers of a decrease from 8 to 0 while the powers of b increase from 0 to 8.
每一项的形式为 8C_r × a8-r × br。a 的幂从 8 递减到 0，而 b 的幂从 0 递增到 8。
8. Finding a Specific Coefficient | 求特定项的系数
To find a specific term without expanding the whole bracket, use the general term formula:
要在不展开整个括号的情况下找到特定项，可使用通项公式：
Tr+1 = 8C_r × a8-r × br
ple, the coefficient of a⁵b³ in (a + b)⁸ is 8C₃ = 56. The coefficient of a²b⁶ is 8C₆ = 28.
例如，(a + b)⁸ 中 a⁵b³ 的系数是 8C₃ = 56。a²b⁶ 的系数是 8C₆ = 28。
This method is much faster than expanding the whole expression, especially in exam settings.
这种方法比展开整个表达式快得多，尤其是在考试情境中。
9. Common Mistakes with 8C Answers | 8C 答案常见错误
ns with permutations. Remember that 8C_r does not count different orders, while 8P_r does.
一个常见错误是混淆组合与排列。请记住，8C_r 不计算不同顺序，而 8P_r 会计算不同顺序。
Another mistake is forgetting that 0! values for 8C₀ and 8C₈. Also, check that your r value is never negative or greater than 8.
另一个错误是忘记 0! = 1，这会导致 8C₀ 和 8C₈ 的值计算错误。此外，还要检查 r 值不为负数且不超过 8。
10. Worked Example: Choosing a Committee | 例题：选择委员会
A committee of 4 people is to be chosen from 8 candidates. How many different committees are possible?
一个由 4 人组成的委员会需要从 8 名候选人中选出。共有多少种不同的委员会？
Number of committees = 8C₄ = 8! / (4! × 4!) = 40320 / (24 × 24) = 70
dent, secretary, treasurer and member, order matters, so you would use 8P₄ = 1680 instead.
因此有 70 种可能的委员会。如果委员会有主席、秘书、财务和成员等职位，顺序就有影响，此时应改用 8P₄ = 1680。
11. Exam-Style Practice Questions | 考试型练习题
Try these quick questions to test your understanding of 8C answers:
尝试以下快速练习题，检验你对 8C 答案的理解：
- Evaluate 8C₂ + 8C₃. | 计算 8C₂ + 8C₃。
- Find the coefficient of x³y⁵ in (x + y)⁸. | 求 (x + y)⁸ 中 x³y⁵ 的系数。
- A bag has 8 marbles. How many ways can you choose 5 marbles? | 一个袋子里有 8 个弹珠。选出 5 个弹珠有多少种方法？
- What is 8C₅ - 8C₃? | 8C₅ - 8C₃ 等于多少？
e coefficient is 8C₅ = 56; choosing 5 marbles gives 8C₅ = 56; and 8C₅ - 8C₃ = 56 - 56 = 0.
核对答案：8C₂ + 8C₃ = 28 + 56 = 84；系数为 8C₅ = 56；选出 5 个弹珠有 8C₅ = 56 种方法；8C₅ - 8C₃ = 56 - 56 = 0。
12. Quick Reference Summary | 快速参考总结
The nine 8C answers are 1, 8, 28, 56, 70, 56, 28, 8, 1. They form Pascal's triangle row 8 and serve as coefficients in (a + b)⁸.
九个 8C 答案分别是 1、8、28、56、70、56、28、8、1。它们构成帕斯卡三角第 8 行，并作为 (a + b)⁸ 中的系数。
Use the formula 8C_r = 8! / [r!(8-r)!] when you need an exact value, and remember the symmetry property 8C_r = 8C8-r to speed up calculations.
当你需要精确值时，使用公式 8C_r = 8! / [r!(8-r)!]，并记住对称性 8C_r = 8C8-r 以加快计算速度。
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