📚 Unit 3 Algebra: Expressions, Equations and Formulae – Answer Guide | 数学第3单元:代数式、方程与公式答案指南
This answer guide covers the essential skills in Unit 3: algebraic expressions, linear equations, inequalities, formulae, and sequences. Each section gives a clear method, a worked example, and a common mistake to avoid.
本答案指南涵盖第3单元的核心技能:代数式、线性方程、不等式、公式和数列。每一小节都给出清晰方法、范例演示和需要避免的常见错误。
1. Algebraic Expressions and Terms | 代数式与项
An algebraic expression is a combination of numbers, letters, and operations. Terms are separated by + or − signs. For example, in 5x + 3y − 7, the terms are 5x, 3y, and 7.
代数式是数字、字母和运算符号的组合。项由加号或减号分隔。例如,在 5x + 3y − 7 中,项分别是 5x、3y 和 7。
A coefficient is the number multiplying a variable. In 5x, the coefficient is 5; in −3y, the coefficient is −3. A constant is a term with no variable, such as 7.
系数是乘以变量的数。在 5x 中,系数是 5;在 −3y 中,系数是 −3。常数是不含变量的项,例如 7。
Common mistake: forgetting the sign in front of a term. Always take the sign before the term as part of that term.
常见错误:忽略项前面的符号。始终把项前面的符号看作该项的一部分。
2. Collecting Like Terms | 合并同类项
Like terms have exactly the same variable part. You can add or subtract like terms by combining their coefficients. Unlike terms cannot be combined.
同类项具有完全相同的变量部分。你可以通过合并系数来加减同类项。不同类项不能合并。
Worked example: simplify 3x + 5y − 2x + 7y.
范例:化简 3x + 5y − 2x + 7y。
3x + 5y − 2x + 7y = (3 − 2)x + (5 + 7)y = x + 12y
The x terms are combined and the y terms are combined. The answer cannot be simplified further because x and y are unlike terms.
把 x 项合并,把 y 项合并。答案不能进一步化简,因为 x 和 y 是不同类项。
3. Expanding Brackets | 去括号展开
tside by every term inside the bracket. This uses the distributive law a(b + c) = ab + ac.
去括号时,用括号外的项乘以括号内的每一项。这使用了分配律 a(b + c) = ab + ac。
Worked example: expand 3(2x − 4).
范例:展开 3(2x − 4)。
3(2x − 4) = 3 × 2x + 3 × (−4) = 6x − 12
rms and then collect like terms. Example: (x + 2)(x + 3) = x² + 3x + 2x + 6 = x² + 5x + 6.
对于双括号,逐对展开各项,再合并同类项。示例:(x + 2)(x + 3) = x² + 3x + 2x + 6 = x² + 5x + 6。
4. Factorising Expressions | 因式分解
Factorising is the reverse of expanding. Find the highest common factor (HCF) of all terms and place it outside the bracket.
因式分解是去括号的逆运算。找出所有项的最大公因数(HCF),并将其放在括号外。
Worked example: factorise 6x + 9.
范例:因式分解 6x + 9。
6x + 9 = 3(2x + 3)
Check by expanding: 3(2x + 3) = 6x + 9. Always check your factorisation by expanding back.
通过展开检验:3(2x + 3) = 6x + 9。因式分解后一定要展开回去检验。
5. Solving Linear Equations | 解一元一次方程
A linear equation has the variable to the power of 1. To solve it, use inverse operations to isolate the variable on one side.
一元一次方程的变量的次数为 1。解方程时,使用逆运算将变量孤立在等式一边。
Worked example: solve 2x + 3 = 11.
范例:解方程 2x + 3 = 11。
2x + 3 = 11
2x = 8
x = 4
th sides by 2. The solution is x = 4. Check by substitution: 2(4) + 3 = 11, which is true.
步骤1:两边同时减去 3。步骤2:两边同时除以 2。解为 x = 4。代入检验:2(4) + 3 = 11,成立。
6. Equations with Unknowns on Both Sides | 两边均为未知数的方程
If the variable appears on both sides, collect variable terms on one side and constants on the other side.
如果变量同时出现在等式两边,把变量项移到一边,常数项移到另一边。
Worked example: solve 5x + 2 = 3x + 8.
范例:解方程 5x + 2 = 3x + 8。
5x + 2 = 3x + 8
5x − 3x = 8 − 2
2x = 6
x = 3
Subtract 3x from both sides, then subtract 2 from both sides,
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