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5.4.3 Boyle's Law | 5.4.3 波义耳定律

2026-08-05 06:21 · 本文部分内容由AI辅助创作

📚 5.4.3 Boyle's Law | 5.4.3 波义耳定律

Boyle' 5.4.3 requires you to state the law, use the equation p₁V₁ = p₂V₂, and interpret pressure–volume graphs.

波义耳定律描述了在温度恒定的条件下,一定质量气体的压强与体积之间的关系。这一重要原理能帮助我们理解从呼吸到水下气泡行为等日常现象。在 Edexcel IGCSE 科学大纲中,5.4.3 节要求你准确陈述该定律,运用公式 p₁V₁ = p₂V₂,并解读压强–体积图像。

1. Pressure and Volume in a Gas | 气体的压强与体积

Gas particles are in constant, random motion, colliding with each other and with the walls of their container. The pressure a gas exerts is caused by the force of these collisions acting over the internal surface area. If you halve the volume of the container while keeping the temperature and number of particles fixed, the same number of particles are squeezed into a smaller space. The frequency of collisions with the walls increases, so the pressure rises.

气体粒子不断地作无规则运动,与彼此及容器壁发生碰撞。气体施加的压强正是由这些碰撞力作用在容器内表面积上产生的。如果在保持温度和粒子数不变的情况下将容器体积减半,相同数量的粒子被挤入更小的空间,与器壁的碰撞频率就会增加,因此压强上升。

Pressure is measured in pascals (Pa) or kilopascals (kPa); volume is often given in cubic metres (m³), cubic decimetres (dm³) or litres (L). We always convert to consistent units before tackling calculations.

压强的单位是帕斯卡(Pa)或千帕(kPa);体积常用立方米(m³)、立方分米(dm³)或升(L)。在进行计算前,必须换算为一致的单位。


2. Boyle's Law: The Inverse Relationship | 波义耳定律:反比关系

Boyle' ideal gas at constant temperature, its pressure is inversely proportional to its volume. Written mathematically, p ∝ rds, if the volume doubles, the pressure halves, provided the temperature does not change.

波义耳定律指出:对于一定质量的气体,在温度不变时,其压强与体积成反比。用数学表示即 p ∝ 1/V,或 p × V = 常数。换句话说,如果体积变成两倍,压強就变为原来的一半,前提是温度不变。

The law applies accurately to most gases at low pressures and moderate temperatures. It is an empirical law discovered by Robert Boyle in 1662.

该定律在低压和中等温度下对大多数气体都相当准确。它是由罗伯特·波义耳于1662年通过实验发现的经验规律。


3. The Boyle's Law Equation | 波义耳定律公式

ts pressure changes from p₁ to p₂. Because the product p × V stays the same, we can write:

当气体在恒温下体积从 V₁ 变为 V₂ 时,压强相应地从 p₁ 变为 p₂。由于 p × V 保持不变,我们可以写出:

p₁V₁ = p₂V₂

Where units of pressure and volume must match on both sides. For example, if p₁ is in kPa, p₂ will also be in kPa; V₁ and V₂ can both be in cm³, as long as they are consistent.

式中两边的压强单位必须相同,体积单位也必须一致。例如,p₁ 用 kPa,p₂ 也用 kPa;V₁ 和 V₂ 可以同时以 cm³ 表示,只要保持一致即可。

Always identify the initial and final conditions clearly. It helps to label them as “before” and “after” in a table.

务必明确区分初始状态和最终状态。最好用表格标出“变化前”和“变化后”的各个量。

Quantity 物理量Before 变化前After 变化后
Pressure 压强p₁p₂
Volume 体积V₁V₂
Product 乘积p₁V₁p₂V₂ (equal 相等)

4. Graphical Representations | 图像表示

A pressure–volume graph for a fixed mass of gas at constant temperature is a smooth curve called a hyperbola. The curve approaches the axes but never touches them, illustrating the inverse proportion: as volume gets very large, pressure gets very small, and vice versa.

一定质量气体在恒温下的压强–体积图像是一条光滑曲线,称为双曲线。曲线逐渐靠近坐标轴但永不相交,直观地表现了反比关系:体积极大时压強极小,反之亦然。

If we plot pressure against 1/volume, we obtain a straight line through the origin. This confirms the direct proportionality between pressure and the reciprocal of volume, and makes it easier to verify Boyle's Law from experimental data.

如果画出压强与 1/体积 的关系图,会得到一条过原点的直线。这证实了压强与体积倒数成正比,从而更容易利用实验数据验证波义耳定律。

You need to be able to interpret such graphs and to extract the constant pV from the slope or from the product of corresponding values.

你需要能够解读这种图像,并能从斜率或对应数值的乘积中提取常数 pV。


5. Molecular Explanation | 分子层面的解释

According to the kinetic particle theory, gas particles move faster when the temperature is higher. At constant temperature, the average kinetic energy of the particles is fixed. When we reduce the volume, the particles are confined to a smaller space, so they hit the walls more often in a given time. More frequent collisions mean a larger total force per unit area, i.e. higher pressure.

根据粒子动理论,温度越高,气体粒子运动越快。在恒定温度下,粒子的平均动能是固定的。当我们减小体积时,粒子被限制在更小的空间,因而在单位时间内撞击器壁的次数增多。更频繁的碰撞意味着单位面积上的作用力更大,即压强更高。

The opposite happens when volume increases: collision frequency drops, so pressure falls. The explanation must always include the link between volume, collision frequency and force.

体积增大时则相反:碰撞频率下降,压强随之降低。解释时一定要涵盖体积、碰撞频率和力之间的联系。


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6. Experimental Investigation | 实验探究

A common practical to verify Boyle's Law uses a syringe connected to a pressure gauge. The syringe plunger is moved to different volumes, and the corresponding pressure is recorded. Throughout the experiment, it is vital to wait a few seconds at each position to let the gas return to room temperature after compression or expansion — this keeps the temperature constant.

验证波义耳定律的常用实验使用一支连接压强计的注射器。将注射器活塞移至不同体积,记录对应的压强。整个实验过程中,每次改变体积后必须等待数秒,让气体在压缩或膨胀后回到室温,从而保持温度恒定。

e roughly constant, the law is supported. A graph of p against 1/V can be plotted to check for a straight line.

然后处理数据,计算每次读数的 p × V;若数值大致不变,就支持该定律。也可绘制 p 对 1/V 图像,检验其是否为直线。

Syringe volume (cm³) 注射器体积Pressure (kPa) 压强pV (kPa·cm³)
601006000
501206000
401506000
302006000

7. Worked Example 1 – Simple Calculation | 例题1 – 简单计算

Question: A gas occupies 250 cm³ at 100 kPa. The temperature remains constant while the volume is compressed to 125 cm³. Find the final pressure.

题目:某气体在 100 kPa 下占据 250 cm³。温度不变,气体被压缩到 125 cm³。求最终压强。

Solution: Let p₁ = 100 kPa, V₁ = 250 cm³, V₂ = 125 cm³. Using Boyle's Law:

解答:设 p₁ = 100 kPa,V₁ = 250 cm³,V₂ = 125 cm³。运用波义耳定律:

p₁V₁ = p₂V₂ → 100 × 250 = p₂ × 125

So p₂ = (100 × 250) / 125 = 200 kPa. Notice how halving the volume doubled the pressure.

因此 p₂ = (100 × 250) / 125 = 200 kPa。可以看到,体积减半导致压强加倍。


8. Worked Example 2 – Changing Units | 例题2 – 单位换算

Question: A 2.0 dm³ balloon contains helium at 101 kPa. The balloon rises and its volume expands to 2.5 dm³ at the same temperature. Calculate the new pressure of the helium.

题目:一个 2.0 dm³ 的气球含有 101 kPa 的氦气。气球上升,体积在同温下膨胀至 2.5 dm³。计算氦气的新压强。

Solution: p₁ = 101 kPa, V₁ = 2.0 dm³, V₂ = 2.5 dm³. Apply the equation:

解答:p₁ = 101 kPa, V₁ = 2.0 dm³, V₂ = 2.5 dm³。代入公式:

p₂ = (p₁V₁) / V₂ = (101 × 2.0) / 2.5 = 80.8 kPa

As expected, an increase in volume results in a lower pressure. Always check that the final value makes sense: here, volume went up, so pressure went down.

不出所料,体积增大导致压强降低。始终要检查最终结果是否合理:这里体积增大,压强减小。


9. Real-World Applications | 现实应用

Boyle's Law explains numerous everyday and biological phenomena:

波义耳定律能解释众多日常和生物现象:


10. Assumptions and Limitations | 假设与局限

Boyle's Law assumes the gas behaves as an ideal gas. Real gases deviate from the law at very high pressures or very low temperatures because intermolecular forces and the volume of the particles themselves become significant. In IGCSE contexts, these complications are ignored, and the law is treated as applicable to all gases under normal laboratory conditions.

波义耳定律假设气体为理想气体。真实气体在极高压或极低温下会偏离该定律,因为分子间力和粒子自身体积的影响变得显著。在 IGCSE 阶段,我们忽略这些复杂情况,假定该定律适用于所有气体在常规实验室条件下的行为。

The temperature must be absolutely constant; even a small increase in temperature adds kinetic energy, raising the product pV and invalidating a direct comparison. Care must be taken in practical work to avoid heating from hands or the environment.

温度必须绝对恒定;哪怕温度略微升高都会增加动能,使 pV 乘积增大,导致直接比较失效。实验操作中应小心避免手部或环境加热气体。


11. Summary and Exam Tips | 总结与考试提示

Boyle's Law for a fixed mass of gas at constant temperature states: pressure ∝ = p₂V₂ is your main calculation tool. Remember to use identical units on both sides. The p– ollision frequency, and to relate the law to practical situations such as breathing or syringes.

波义耳定律针对恒温下一定质量的气体:压强 ∝ 1/体积,且 pV = 常数。公式 p₁V₁ = p₂V₂ 是你的主要计算工具。切记两边使用一致的单位。p–V 图像为双曲线,p 对 1/V 图像为过原点的直线。做好用碰撞频率阐述粒子动理论解释的准备,并能够将定律与呼吸、注射器等实际情境相联系。

ly substitute and solve for the unknown. Always check that your answer follows the inverse relationship: larger volume gives smaller pressure, and vice versa.

考试中,若已知 p₁V₁ = p₂V₂ 四个量中的三个,只需代入求解未知量。永远要检查答案是否符合反比关系:体积大对应压强小,反之亦然。


Published by TutorHao | Edexcel IGCSE Science Revision Series | aleveler.com

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