← 返回资讯屏轩教育 · 行业资讯

Bearings | 方位角

2026-08-03 05:55 · 本文部分内容由AI辅助创作

📚 Bearings | 方位角

Bearings are a fundamental part of geometry used to describe direction precisely. In mathematics and navigation, they give the angle measured clockwise from the north line, allowing ships, planes and hikers to follow exact courses. Understanding bearings is essential for the Edexcel IGCSE Mathematics syllabus, where you will be expected to interpret, draw and solve problems involving bearings in a variety of contexts.

方位角是几何学中用于精确描述方向的基本内容。在数学和导航中,它们给出了从北线顺时针方向测量的角度,使船舶、飞机和徒步者能够沿着精确的路线行进。理解方位角对于Edexcel IGCSE数学大纲至关重要,你将需要掌握在各种情境中解释、绘制并解答涉及方位角的问题。


1. What are Bearings? | 什么是方位角?

A bearing is an angle, measured in degrees, that describes the direction of one point from another. It is always measured clockwise from the north direction, starting at 0° for due north, moving to 090° for east, 180° for south, 270° for west, and back to 360° (or 000°). Bearings are used to navigate in a straight line without landmarks.

方位角是一个以度数表示的角度,用来描述从一个点到另一个点的方向。它始终从北方向顺时针测量,正北为0°,正东为090°,正南为180°,正西为270°,最后回到360°(或记为000°)。方位角用于在没有地标的情况下沿直线导航。


2. Three Key Rules of Bearings | 方位角的三个关键规则

There are three essential rules you must remember for writing and interpreting bearings:

在书写和解释方位角时,必须记住以下三个关键规则:

These conventions prevent any confusion about the intended direction. Even if the angle is less than 100°, you must add leading zeros.

这些约定可避免对预期方向产生任何混淆。即使角度小于100°,也必须添加前导零。


3. Measuring and Drawing Bearings | 测量与绘制方位角

To measure a bearing on a diagram, first draw a vertical north line at the point you are starting from. Place the protractor with its centre on the point and align the 0° mark exactly with the north line. Measure clockwise from north to the line joining the two points. When drawing a bearing, you do the reverse: draw the north line, mark the required angle clockwise, and construct the path.

要在图上测量方位角,首先在出发点绘制一条垂直的北线。将量角器的中心放在该点上,使0°刻度与北线精确对齐。从北顺时针测量到连接两点的直线上。当按方位角绘制时,步骤相反:画出北线,顺时针标出所需角度,然后构造路径。


4. Back Bearings (Reverse Bearings) | 反向方位角

If you travel from point A to point B on a certain bearing, the return bearing from B back to A is called the back bearing. It can be calculated easily with these rules:

如果你从A点沿某一方位角行至B点,那么从B返回A的方位角称为反向方位角。它可以用以下规则轻松计算:

If the forward bearing ≤ 180°, add 180°.
If the forward bearing > 180°, subtract 180°.

前向方位角 ≤ 180° 时,加 180°。
前向方位角 > 180° 时,减 180°。

+ 180° = 245°. If the bearing from C to D is 230°, the back bearing is 230° − 180° = 050°.

例如,A到B的方位角是065°,那么B到A的反向方位角为065° + 180° = 245°。如果C到D的方位角是230°,反向方位角则为230° − 180° = 050°。


5. Bearings in Scale Drawings | 比例图中的方位角

Many IGCSE questions require you to construct a scale drawing using bearings and distances. Start by fixing a point for your starting location and drawing its north line. Use a protractor to mark the given bearing and draw a light construction line. Then measure the given distance to scale (e.g. 1 cm represents 10 km) along that line to locate the next point. Repeat for subsequent legs of the journey. Finally, you may be asked to measure a new bearing or distance from the drawing.

许多IGCSE题目要求你通过方位角和距离构建比例图。首先确定起点的位置并画出北线。用量角器标出给定方位角,画一条淡淡的构造线。然后沿该线按比例测量给定距离(例如1厘米代表10公里)以确定下一个点。对后续航段重复上述步骤。最后,可能要求你从图中测量新的方位角或距离。


广告 / Sponsored

6. Bearings and Right‑Angled Trigonometry | 方位角与直角三角形三角函数

When a bearing problem creates a right‑angled triangle, you can apply Pythagoras' theorem and basic trigonometric ratios. A typical question might describe a ship sailing east then altering course, forming a right angle with the north‑south line. Use sine (sin), cosine (cos) or tangent (tan) to find unknown angles or sides. Always ensure your calculator is in degree mode.

当方位角问题构成直角三角形时,可以应用勾股定理和基本的三角函数比。一个典型的问题可能是船向东航行然后改变航向,与南北线形成直角。使用正弦(sin)、余弦(cos)或正切(tan)来求未知角度或边长。务必确保计算器处于角度模式。

For example, a boat travels 6 km on a bearing of 060° from A to B, then 8 km due south to C. When you sketch this, you often get a right‑angled triangle where the east‑west and north‑south components can be resolved to find the direct distance AC.

例如,一艘船从A以060°的方位角航行6公里到B,然后向正南航行了8公里到C。当你画出示意图时,通常会得到一个直角三角形,通过东西向和南北向的分量可以求出A到C的直线距离。


7. Bearings and the Sine/Cosine Rules | 方位角与正弦余弦定理

When the triangle formed is not right‑ed, you must use the sine rule or cosine rule. These are powerful tools for tackling multi‑ cos A. Combined with the back bearing idea, you can solve for distances and missing bearings.

当构成的三角形不是直角三角形时,就必须使用正弦定理或余弦定理。这些是处理多段方位角问题的有力工具。正弦定理为 a / sin A = b / sin B = c / sin C,而余弦定理为 a² = b² + c² − 2bc cos A。结合反向方位角的概念,你就可以求出距离和缺失的方位角。

Consider a plane flying from P to Q on a bearing of 035° for 200 km, then from Q to R on a bearing of 125° for 150 km. The angle at Q inside triangle PQR can be found using the difference in bearings, enabling the cosine rule to calculate PR.

设想一架飞机从P以035°的方位角飞行200公里到达Q,然后从Q以125°的方位角飞行150公里到达R。利用方位角之差可以求出三角形PQR中顶点Q处的角,然后应用余弦定理计算PR的距离。


8. Worked Example | 典型例题

Problem: A hiker walks from base camp A to point B on a bearing of 145° for 4 km, then to point C on a bearing of 215° for 5 km. Find the bearing and distance to return directly from C to A.

问题:一名徒步者从大本营A沿145°方位角走4公里到B点,然后沿215°方位角走5公里到C点。求直接从C返回A的方位角和距离。

Solution: rom B to A of 145° + 180° = 325°. At B, the north line and BC differ, allowing you to find ∠ en use the sine rule to determine an angle at C, which converts into the required bearing.

解答:画出旅程草图。B点处北线与BA路径的夹角为180° − 145° = 35°,得到B到A的反向方位角为145° + 180° = 325°。在B点,北线和BC线有差异,可求出∠ABC为BA与BC方位角的差。构建三角形ABC,应用余弦定理求出CA。再用正弦定理求出C点的一个内角,并将其转换为所需的方位角。

p, you will find CA ≈ 7.2 km and the bearing from C to A ≈ 005° (rounded to three digits).

分步计算,可得出CA约等于7.2公里,C到A的方位角约为005°(三位数格式)。


9. Common Mistakes and How to Avoid Them | 常见错误及规避方法


10. Exam Tips for IGCSE Edexcel | IGCSE Edexcel 应试技巧

Always include a clear, labelled diagram with north lines, even if the question doesn't provide one. Show all calculations step by step to earn method marks. Write your final bearing as a three‑digit number and include units for distances (km, m, cm as appropriate). When using the sine or cosine rule, write the formula first before substituting values. Check the reasonableness of your answer — bearings can only be between 000° and 360°.

始终要画出清晰、带标注的示意图和北线,即使题目没有提供。逐步展示所有计算过程以获得步骤分。最终的方位角要写成三位数,距离要注明单位(公里、米、厘米等)。在使用正弦或余弦定理时,先写出公式再代入数值。检查答案的合理性——方位角只能在000°到360°之间。

Published by TutorHao | Mathematics Revision Series | aleveler.com

广告 / Sponsored
原版培生爱德思考试教材IGCSE计算机科学(含电子书) Pearson Edexcel International G…
计算机 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥398.0

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao