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Converting Recurring Decimal 0.090909... to Fraction | 循环小数0.090909... 转换为分数

2026-08-03 05:36 · 本文部分内容由AI辅助创作

📚 Converting Recurring Decimal 0.090909... to Fraction | 循环小数0.090909... 转换为分数

In IGCSE Edexcel Mathematics, you will often meet questions that ask you to convert a recurring decimal into an exact fraction. The decimal 0.090909... with the repeating block '09' is a classic example that appears in exam practice. Turning this never-ending pattern into the simple fraction 1/11 shows the power of algebraic manipulation. This process relies on setting up an equation, multiplying by powers of 10, and careful subtraction to eliminate the repeating part.

在IGCSE Edexcel数学中,你常会遇到要求将循环小数转换为准确分数的题目。像 0.090909... 这样以 "09" 为循环节的小数就是考试练习中经典的例子。将这种永无止境的模式化为简单的分数 1/11,充分展示了代数操作的威力。整个过程依赖于建立方程、乘以10的幂以及通过减法消去重复部分。

1. What Is a Recurring Decimal? | 什么是循环小数?

A recurring decimal, also called a repeating decimal, is a decimal number where a digit or a block of digits repeats infinitely after the decimal point. We usually indicate the repeating pattern by placing a dot (or dots) above the repeating digits. For instance, 0.0̇9̇ means the digits 0 and 9 repeat forever: 0.0909090909...

循环小数(也叫重复小数)是指小数点后有一位或一组数字无限重复的小数。我们通常通过在重复的数字上方加点的方式来表示循环节。例如,0.0̇9̇ 表示数字 0 和 9 无限循环:0.0909090909...

In the Edexcel IGCSE specification, you need to distinguish between 'terminating' decimals, which come to an end, and 'recurring' decimals, which do not. Only recurring decimals require the algebraic method to be expressed as fractions.

在Edexcel IGCSE大纲中,你需要区分“有限”小数(会终止)和“循环”小数(不会终止)。只有循环小数才需要代数方法才能表示为分数。


2. Recognising the Pattern in 0.090909... | 识别 0.090909... 中的模式

The number 0.090909... looks small, but it has a clear two-digit cycle. Observe that after the decimal point you always have a zero followed by a nine, then another zero and nine, and so on. The repeating block is '09' and it starts immediately after the decimal point.

0.090909... 这个数看起来很小,但它具有清晰的两数循环周期。可以看到,小数点后总是先是一个零,然后是九,接着又是一个零和一个九,如此往复。循环块是 "09",并且它紧挨着小数点之后就开始。

This is an example of a pure recurring decimal, meaning the repetition begins right after the decimal point. When the repetition does not start immediately (e.g. 0.1090909...), it is called a mixed recurring decimal, which requires a slightly different approach.

这是一个纯循环小数的例子,意味着循环从小数点后立刻开始。当循环不是立刻开始时(比如 0.1090909...),则被称为混循环小数,处理方法稍有不同。


3. Setting Up the Algebraic Equation | 建立代数方程

To convert 0.0̇9̇ to a fraction, we start by letting the unknown x represent our number. Write:

要将 0.0̇9̇ 转化为分数,我们首先用未知数 x 表示这个数。记作:

Let x = 0.0̇9̇

设 x = 0.0̇9̇

hift the decimal point exactly after one complete cycle, leaving the repeating part identical to the original. This is the key step that allows subtraction to clear the infinite tail.

由于循环块有两位数字,乘以 10² = 100 会将小数点向后移动刚好一个完整循环的位置,让循环部分与原数完全相同。这就是允许通过减法消去无限尾部的最关键一步。

100x = 9.0̇9̇

100x = 9.0̇9̇


4. Subtracting to Eliminate the Repeating Part | 相减消去循环部分

Now we have two equations: x = 0.0̇9̇ and 100x = 9.0̇9̇. Subtract the first from the second:

现在我们有了两个等式:x = 0.0̇9̇ 和 100x = 9.0̇9̇。用第二个减去第一个:

100x − x = 9.0̇9̇ − 0.0̇9̇

100x − x = 9.0̇9̇ − 0.0̇9̇

On the left, 100x − x simplifies to 99x. On the right, the repeating tail ̇0̇9 in both numbers cancels out completely, leaving only 9.

左边,100x − x 化简为 99x。右边,两个数中的循环尾部 0̇9̇ 完全消去,只剩下 9。

99x = 9

99x = 9

Solve for x by dividing both sides by 99:

将两边同除以 99,解出 x:

x = 9/99

x = 9/99


5. Simplifying to the Lowest Terms | 化简到最简分数

The fraction 9/99 can be simplified. Both numerator and denominator share a common factor of 9. Dividing top and bottom by 9 gives the simplest form:

分数 9/99 可以化简。分子和分母有公因数 9。分子分母同除以 9 得到最简形式:

9 ÷ 9 = 1, 99 ÷ 9 = 11 → x = 1/11

9 ÷ 9 = 1,99 ÷ 9 = 11 → x = 1/11

Thus 0.0̇9̇ is exactly equal to 1/11. You can verify this quickly with a calculator: 1 divided by 11 equals 0.0909090909..., confirming the conversion.

因此 0.0̇9̇ 恰好等于 1/11。你可以用计算器快速验证:1 除以 11 等于 0.0909090909...,证实了转换结果。


6. Understanding Why This Works | 理解为什么这样做可行

general rule is: multiply by 10ⁿ, where n is the number of digits in the repeating block.

这种代数方法的原理在于,相减时无限循环的数字串会完美抵消。如果循环块有三个数字,比如 0.123123...,就会乘以 10³ = 1000。一般规则是:乘以 10ⁿ,其中 n 是循环块中数字的个数。

For mixed recurring decimals with a non-repeating starting section, you must first separate the non-repeating part, or use two multiplications to align the repeating parts before subtraction. However, 0.090909... is pure, making the process very straightforward.

对于开头不循环、后面才循环的混循环小数,必须先分离不循环部分,或者通过两次乘法让循环部分对齐后再相减。不过 0.090909... 是纯循环的,过程十分直接。


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7. Alternative View: Geometric Series | 另一种视角:几何级数

Another method, which is sometimes covered in extension work, views 0.090909... as an infinite geometric series:

另一种方法(有时在拓展内容中出现)是将 0.090909... 看作一个无穷几何级数:

0.090909... = 9/100 + 9/10000 + 9/1000000 + ...

0.090909... = 9/100 + 9/10000 + 9/1000000 + ...

11. The algebraic method remains the preferred IGCSE approach because it is simpler and avoids series notation.

这是一个首项 a = 9/100、公比 r = 1/100 的几何级数。无穷和为 a/(1 − r),得到 (9/100) / (99/100) = 9/99 = 1/11。代数法仍是IGCSE推荐的方法,因为它更简单,也避免了级数符号。


8. A Related Curiosity: 0.9̇ = 1 | 相关趣题:0.9̇ = 1

When studying recurring decimals, many students encounter the famous fact that 0.9̇ (0.999...) is exactly equal to 1. Using the same steps: let y = 0.9̇. The repeating block has one digit, so multiply by 10: 10y = 9.9̇ his demonstrates that two different decimal representations can stand for the same number.

学习循环小数时,许多学生会遇到一个著名的事实:0.9̇ (0.999...) 正好等于 1。用同样的步骤:设 y = 0.9̇。循环块有一个数字,所以乘以 10:10y = 9.9̇。减去 y:10y − y = 9,于是 9y = 9,y = 1。这说明了两个不同的小数表示可以代表同一个数。

While 0.090909... does not cause the same surprise, it is part of the same family of fraction-decimal equivalences. Being comfortable with both standard and unusual cases helps you tackle any IGCSE question with confidence.

虽然 0.090909... 不会引发同样的惊奇,但它属于同一个小数-分数等价家族。无论标准情况还是特殊情形都能自如应对,有助于你自信地解答任何IGCSE题目。


9. Common Errors to Avoid | 常见错误及避免方法

Using the wrong multiplier: Always count the number of digits in the repeating block. For 0.0̇9̇ it is two digits, so multiply by 100. Multiplying by 10 would give 10x = 0.9̇0̇, which does not align the repeating pattern correctly for cancellation.

乘数使用错误:一定要数清楚循环块中的数字个数。对于 0.0̇9̇,是两位数字,所以要乘以 100。乘以 10 会得到 10x = 0.9̇0̇,这样循环模式没有对齐,无法正确相消。

Forgetting to simplify: After obtaining 9/99, leaving the fraction unsimplified may lose marks if the question asks for the fraction in its simplest form. Always check for common factors.

忘记化简:得到 9/99 后,若不化简,当题目要求最简分数时就会失分。一定要检查公因数。

Misplacing the decimal point when writing 100x: nk mistakenly that 100 × 0.090909... = 0.90909..., so double-check with simple estimation.

写 100x 时小数点错位:仔细写:100 × 0.090909... = 9.090909... 容易误以为 100 × 0.090909... = 0.90909...,所以用简单的估算再检查一遍。


10. Practising with Similar Decimals | 用类似小数进行练习

Once you have mastered 0.0̇9̇ = 1/11, try converting these decimals to test your understanding:

一旦掌握了 0.0̇9̇ = 1/11,尝试转换以下小数来检验你的理解:

For each, set up x, multiply by 10ⁿ, subtract and simplify. You will see the pattern: the numerator is the repeating block and the denominator is a string of 9s of the same length, then simplify.

对每一题,设 x,乘以 10ⁿ,相减并化简。你会发现规律:分子是循环块,分母是同样长度的 9 组成的数,然后再约分。


11. Applying This Skill in IGCSE Exams | 在IGCSE考试中运用本技能

Edexcel IGCSE Mathematics often asks you to "express 0.0̇9̇ as a fraction in its simplest form" or a similar wording. The question may be embedded in a problem involving probability, recurring decimals in financial contexts, or comparing fractions. Showing clear algebraic steps earns full method marks.

Edexcel IGCSE数学经常要求“将 0.0̇9̇ 用最简分数表示”或类似说法。题目可能嵌入概率、财务情境中的循环小数,或比较分数大小等背景。展示清晰的代数步骤能获得完整的方法分。

Writing 'Let x = ...' writing the final answer without working, as you might lose marks if a small slip occurs.

写出“设 x = ...”、说明乘数、进行减法并化简是期望的解题过程。不要只写最终答案而没有过程,否则一旦出现小失误就可能失分。

You might also see questions that give a fraction and ask you to prove that its decimal equivalent is a specific recurring decimal. In that case, perform the division and show that the remainder repeats, confirming the cycle.

你也可能看到给出一个分数、要求证明它的小数形式是某个特定循环小数的题目。此时执行除法并展示余数重复出现,以证实循环节。


12. Summary and Key Takeaways | 总结与要点提炼

olve 99x = 9, and simplify to 1/11. The same method extends to any pure recurring decimal.

循环小数 0.090909... 恰好等于 1/11。核心技巧是:设 x,乘以 100 以匹配两位数字的循环块,用 100x 减去 x,解方程 99x = 9,化简得到 1/11。同样的方法可以推广到任何纯循环小数。

Remember to always count the repeating digits correctly, align decimal points, and simplify fully. Practice with a variety of examples to build speed and confidence for your Edexcel IGCSE exam.

记住要正确数出循环数字的个数、对齐小数点并彻底化简。通过多样化的例子练习,为你的Edexcel IGCSE考试提升速度和信心。

Published by TutorHao | Mathematics Revision Series | aleveler.com

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