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Circle Theorems | 圆定理

2026-08-03 05:22 · 本文部分内容由AI辅助创作

📚 Circle Theorems | 圆定理

Circle theorems form a crucial part of the IGCSE Edexcel Mathematics syllabus. They describe the relationships between angles, chords, tangents, and arcs within a circle. Understanding these geometric principles not only helps you solve complex angle problems but also builds a strong foundation for further studies in geometry and proof. In this article, we will explore the essential circle theorems you need to know for the exam, with clear explanations, diagrams described in words, and practical examples.

圆定理是IGCSE Edexcel数学大纲的重要组成部分。它们描述了圆内角、弦、切线和弧之间的关系。理解这些几何原理不仅有助于解决复杂的角度问题,还为几何与证明的深入学习打下坚实基础。本文将讲解考试必须掌握的基本圆定理,提供清晰的文字描述、图形说明和实用例题。


1. Angle at the Centre | 圆心角定理

centre and an angle at the circumference, the centre angle = 2 x the circumference angle.

由两条半径在圆心形成的角,恰好是由同一弧在圆周任意其他点所对圆周角的两倍。换句话说,若一条弧所对的圆心角为 θ,则它所对的圆周角为 θ/2。即圆心角 = 2 x 圆周角。

Example: If the angle at the centre is 120°, the angle at the circumference from the same arc is 60°.

例如:若圆心角为120°,则同一弧所对的圆周角为60°。


2. Angle in a Semicircle | 半圆上的圆周角

Any angle subtended by a diameter at the circumference is a right angle (90°). This is a special case of the angle at the centre theorem, since the diameter forms a 180° angle at the centre.

直径所对的任意圆周角都是直角(90°)。这是圆心角定理的特例,因为直径在圆心形成180°角。

Whenever you see a circle with a diameter drawn and a point on the circumference, complete the right-angled triangle.

只要看到圆中有直径和圆周上一点,就可补全直角三角形。


3. Angles in the Same Segment | 同弓形内的圆周角

Angles subtended by the same chord (or arc) in the same segment of a circle are equal. That is, if a chord AB divides the circle into two segments, all angles in the same (major or minor) segment that stand on AB are equal.

同一弦(或弧)在圆的同一弓形上所对的圆周角相等。也就是说,若弦AB将圆分成两个弓形,那么在同一弓形(优弧或劣弧)内、以AB为底边的所有圆周角都相等。

If you spot several angles 'standing on' the same chord and they lie on the same side of the chord, they are equal.

如果你发现几个角都'站立'于同一条弦上,且位于弦的同一侧,那么它们相等。


4. Cyclic Quadrilateral | 圆内接四边形

circumference of a circle. The key property is that opposite angles sum to 180°. That is, ∠A + ∠C = 180° and ∠B + ∠D = 180°.

圆内接四边形是指四个顶点均在圆周上的四边形。其关键性质是对角互补,即对角之和为180°:∠A + ∠C = 180°,∠B + ∠D = 180°。

Remember: 'opposite angles sum to 180°' is a quick test for whether a quadrilateral is cyclic.

记住:对角互补是检验四边形是否为圆内接四边形的快捷方法。


5. Tangent and Radius | 切线与半径

A tangent to a circle is perpendicular to the radius drawn to the point of tangency. This 90° angle is the single most important fact when working with tangents.

圆的切线垂直于经过切点的半径。这个90°角是处理切线问题时最为重要的事实。

If a line touches the circle at exactly one point and meets the radius at that point, the angle between them is 90°.

若一直线与圆仅交于一点,并在该点与半径相交,则它们之间的角为90°。


6. Tangents from an External Point | 从外部点引出的两条切线

From a point outside a circle, two tangents can be drawn to the circle. These two tangents have equal length. Additionally, the line segment joining the external point to the circle's centre bisects the angle between the two tangents.

从圆外一点可以引圆的两条切线。这两条切线的长度相等。并且,连接该点与圆心的线段平分两切线之间的夹角。

Example: If two tangents meet at an external point P, and the angle between them is 50°, the line PO (O is centre) splits it into two 25° angles.

例如:若两条切线交于圆外一点P,夹角为50°,则PO(O为圆心)将该角平分为两个25°角。


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7. Alternate Segment Theorem | 弦切角定理

The angle between a tangent and a chord through the point of tangency is equal to the angle in the alternate segment. That is, the angle made by the chord with the tangent is the same as the angle subtended by that chord in the opposite segment of the circle.

切线与经过切点的弦所夹的角,等于该弦在另一弓形中所对的圆周角。也就是说,弦与切线所成的角,等于弦在圆的另一侧弓形中所对的圆周角。

Always identify the chord carefully; the 'alternate segment' is the segment from the other side of the chord.

务必仔细确定弦;'另一弓形'指的是弦的另一侧弓形。


8. Intersecting Chords Theorem (Internal) | 相交弦定理(内部)

heir segments are equal. If chords AB and CD intersect at point X, then AX x XB = CX x XD.

当圆内两弦相交时,各弦被交点分成的两线段之积相等。若弦AB与CD相交于点X,则AX x XB = CX x XD。

Be careful to label the segments correctly from the intersection point to the circle.

请务必正确标注从交点到圆上的各段长度。


9. Intersecting Secants Theorem (External) | 割线定理(外部)

is outside, A and C are the nearer intersections, B and D the farther), PA x PB = PC x PD.

如果从圆外一点引出两条割线(每条割线与圆交于两点),那么每条割线的全长与它在外部的线段之积相等。对于割线PAB和PCD(P在圆外,A和C为近交点,B和D为远交点),有PA x PB = PC x PD。

In the exam, look for lengths given from the same external point to two intersections on each line.

在考试中,要寻找从同一点出发到各交点的已知长度。


10. Combining Theorems for Problem-Solving | 综合运用定理解题

In IGCSE Edexcel questions, you often need to combine two or more circle theorems to find a missing angle or length. Start by labeling all obvious relationships: right angles from tangents and radii, equal angles in the same segment, alternate segment marks, and cyclic quadrilateral properties.

在IGCSE Edexcel的考题中,常常需要综合两个或以上的圆定理才能求出未知角度或长度。应首先标出所有明显的关系:切线-半径产生的直角,同弓形内的等角,弦切角标记,以及圆内接四边形性质。

With practice, you will quickly spot which theorem applies. Many problems become almost routine once you recognise the underlying geometry.

通过练习,你会迅速识别适用的定理。一旦你认出了背后的几何结构,许多问题都会变得近乎常规。


11. Common Mistakes and How to Avoid Them | 常见错误与避免方法

One frequent error is confusing the angle at the centre theorem with angles in the same segment. Remember: centre angle is double the circumference angle; angles in the same segment are equal.

一个常见错误是将圆心角定理与同弓形内圆周角相等混淆。请记住:圆心角是圆周角的两倍;同弓形内的圆周角才相等。

Double-check your reasoning by verifying whether the angles you have found are consistent with the triangle angle sum or other known facts.

通过验证所求角是否与三角形内角和或其他已知事实一致,来复核推理过程。


12. Practice Tips for Exam Success | 备考练习技巧

A thorough understanding of circle theorems is tested in both the calculator and non-calculator papers. Deduce angle values without measuring; use only given information and the theorems.

无论是可使用计算器还是不可使用计算器的试卷,都会考查对圆定理的透彻理解。应通过推理而非测量得出角度值,只使用给定的信息和定理。

Regularly testing yourself on these theorems will make them second nature, ensuring you can tackle any circle problem with confidence in the exam.

定期自我检测这些定理将使它们成为你的第二天性,确保你在考场上能够自信地应对任何圆的几何问题。

Published by TutorHao | Mathematics Revision Series | aleveler.com

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