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Differentials and the Solution of First-Order Equations | 微分与一阶微分方程解法

2026-08-03 02:32 · 本文部分内容由AI辅助创作

📚 Differentials and the Solution of First-Order Equations | 微分与一阶微分方程解法

Differential calculus equips us with the notion of the differential, a precise way to describe how small changes in input relate to changes in output. When we combine this concept with first-order differential equations, we gain the power to model dynamic systems – population growth, radioactive decay, cooling processes, and countless other natural phenomena. This article provides a thorough walkthrough of the definitions, techniques, and applications required for IB Mathematics, from basic differentials to the analytical solution of first-order equations.

微分学为我们提供了微分的概念,这是一种精确描述输入微小变化如何影响输出变化的方法。当我们将这一概念与一阶微分方程相结合,就获得了对动态系统建模的能力——人口增长、放射性衰变、冷却过程以及无数其他自然现象。本文全面梳理IB数学所需的定义、解题技巧与应用,从基本微分到一阶方程的解析求解。


1. What is a Differential? | 什么是微分?

If y = f(x) is a differentiable function, the differential dy is defined as dy = f ' en x moves by dx, while the actual change Δy is the rise on the curve. The equality dy = f 'x) dx formalises the idea that the derivative can be treated as a ratio of infinitesimals.

若 y = f(x) 是可微函数,则微分 dy 定义为 dy = f '(x) dx。这里 dx 表示自变量 x 的无穷小变化,dy 给出在 x 处切线方向上的相应变化。从几何角度看,dy 衡量的是当 x 移动 dx 时切线的纵向增量,而真实变化 Δy 是曲线上的增量。等式 dy = f '(x) dx 使得导数可以被当作无穷小之比的这一想法形式化。

ifferentials through more complicated relationships: if u = g(x) and v = h(u), then dv = h '(u) du = h '(g(x)) g '(x) dx, which is simply the chain rule in differential form.

我们也把自变量的微分记作 dx = Δx。这种记法使我们可以将微分在更复杂的函数关系中传递:若 u = g(x) 且 v = h(u),则 dv = h '(u) du = h '(g(x)) g '(x) dx,这正是微分形式的链式法则。


2. Differentiability and Linear Approximation | 可微性与线性近似

A function f is differentiable at a point a if the limit f '(a) = lim(h→0) [f(a+h) – rentiability implies continuity, but continuity alone does not guarantee differentiability – rential lies in linear approximation: for small Δx, Δy ≈ dy. That is, f(a + Δx) ≈ f(a) + f ' -line approximation, and it forms the basis for error propagation and numerical estimates.

函数 f 在点 a 处可微,当且仅当极限 f '(a) = lim(h→0) [f(a+h) – f(a)]/h 存在。可微性蕴含连续性,但连续性本身不能保证可微——尖点、角点和垂直切线都是典型反例。微分的实际威力在于线性近似:当 Δx 很小时,Δy ≈ dy。即 f(a + Δx) ≈ f(a) + f '(a) Δx。这就是切线近似,它构成了误差传递与数值估计的基础。

Example: Estimate √4.1 using the differential. Let f(x) = √x, with a = 4, Δx = 0.1. Then f '(x) = 1/(2√x), f '(4) = 1/4. The approximation gives √4.1 ≈ 2 + (1/4)×0.1 = 2.025. The true value is about 2.0248, showing excellent agreement.

例题:用微分估算 √4.1。设 f(x) = √x,取 a = 4,Δx = 0.1。则 f '(x) = 1/(2√x),f '(4) = 1/4。近似给出 √4.1 ≈ 2 + (1/4)×0.1 = 2.025。真实值约为 2.0248,吻合极好。


3. Differentials and Error Propagation | 微分与误差传播

able x, and the measurement has an error dx. Then the absolute error in Q is approximately |dQ| = |Q '(x) dx| /A = 2 dr/r, meaning the percentage error in area is twice the percentage error in radius.

当某个量是由带有微小不确定度的测量值计算而来时,微分可以干净地估计结果误差。假设量 Q 依赖于被测量 x,且该测量具有误差 dx,则 Q 的绝对误差近似为 |dQ| = |Q '(x) dx|。对于乘积与幂函数,相对误差分析变得格外简洁。若 A = π r² 且半径有误差 dr,则 dA = 2π r dr,相对误差 dA/A = 2 dr/r,意味着面积的百分误差是半径百分误差的两倍。

Error typeFormula误差类型公式
Absolute errorΔQ ≈ dQ = Q '(x) dx绝对误差ΔQ ≈ dQ = Q '(x) dx
Relative errordQ / Q相对误差dQ / Q

4. First-Order Differential Equations: An Introduction | 一阶微分方程简介

ry constant C. If we additionally specify an initial condition y(x₀) = y₀, the resulting problem is an initial value problem (IVP), and its solution is a particular solution. Geometrically, the differential equation assigns a slope to every point (x,y), constructing a slope field.

一阶常微分方程的一般形式为 dy/dx = f(x, y),其中 f 是给定的二元函数。解是指任何在某个区间上满足该方程的函数 y = φ(x)。所有解构成的族称为通解,含有一个任意常数 C。若额外指定一个初始条件 y(x₀) = y₀,得到的就是初值问题,其解为特解。从几何上看,微分方程为平面上的每一点 (x,y) 赋予一个斜率,从而构造出斜率场。

Our goal is to develop analytical methods for several common families of first-order ODEs: separable, linear, homogeneous, and Bernoulli equations. Each method transforms the original equation into a form that can be integrated directly.

我们的目标是发展几类常见一阶常微分方程的解析解法:可分离变量方程、线性方程、齐次方程和伯努利方程。每种方法都将原方程转化为可直接积分求解的形式。


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5. Separable Equations | 可分离变量方程

+ C. After integration, we solve for y explicitly if possible, or leave the solution in implicit form.

若一个微分方程可以写成 dy/dx = g(x) h(y),或等价地写成 (1/h(y)) dy = g(x) dx(只要 h(y) ≠ 0),则称之为可分离变量方程。然后通过两边积分求解:∫ (1/h(y)) dy = ∫ g(x) dx + C。积分后,若可能则解出 y 的显式表达式,或保留隐式形式。

Solve dy/dx = 3x² y. Separating gives (1/y) dy = 3x² dx. Integrating both sides yields ln|y| = x³ + C, hence |y| = ex³ + C = eC ex³. Letting K = ±eC gives the general solution y = K ex³.

例题:求解 dy/dx = 3x² y。分离变量得 (1/y) dy = 3x² dx。两边积分得 ln|y| = x³ + C,因此 |y| = ex³ + C = eC ex³。令 K = ±eC 即得通解 y = K ex³。

ions where h(y) = 0. In the example, y = 0 is also a solution, which corresponds to K = 0.

务必检查遗失的常值解:除以 h(y) 的步骤会漏掉使 h(y) = 0 的解。上述例题中,y = 0 也是解,对应 K = 0。


6. First-Order Linear Equations and Integrating Factors | 一阶线性方程与积分因子

ntegrating both sides yields μ y = ∫ μ Q(x) dx + C, and finally y = (1/μ)[∫ μ Q(x) dx + C].

一阶线性常微分方程的标准形式为 dy/dx + P(x) y = Q(x),其中 P 和 Q 都只依赖于 x。求解的关键是积分因子 μ(x) = e^(∫ P(x) dx)。用 μ 乘以整个方程后,左侧变为乘积 μ y 的导数:d/dx (μ y) = μ Q(x)。两边积分得 μ y = ∫ μ Q(x) dx + C,最后解出 y = (1/μ)[∫ μ Q(x) dx + C]。

Why does this work? ith solution μ = e^(∫ P(x) dx). This choice guarantees the product rule simplifies neatly.

为什么可以这样做?我们需要 dμ/dx = μ P(x),这是关于 μ 的可分离变量方程,解为 μ = e^(∫ P(x) dx)。这一选择确保了乘法法则的简洁化简。

Example: Solve dy/dx + (2/x) y = x³ for x > 0. Here P(x) = 2/x, so μ = e∫ 2/x dx = e2 ln x he left side is d/dx (x² y). Integrate: x² y = ∫ x⁵ dx = x⁶/6 + C, giving y = x⁴/6 + C/x².

例题:求解 dy/dx + (2/x) y = x³(x > 0)。这里 P(x) = 2/x,因此 μ = e∫ 2/x dx = e2 ln x = x²。相乘:x² dy/dx + 2x y = x⁵。左侧即 d/dx (x² y)。积分:x² y = ∫ x⁵ dx = x⁶/6 + C,得 y = x⁴/6 + C/x²。


7. Homogeneous First-Order Equations | 齐次一阶方程

e dy/dx = v + x dv/dx, the original equation becomes v + x dv/dx = F(v), or x dv/dx = F(v) – v, which is separable.

如果一个方程可以写成 dy/dx = F(y/x) 的形式,即右边仅依赖于比值 y/x,则称之为齐次方程。标准代换 v = y/x,即 y = v x,可将该方程转化为关于 v 的可分离变量方程。由 dy/dx = v + x dv/dx,原方程化为 v + x dv/dx = F(v),即 x dv/dx = F(v) – v,这是一个可分离变量方程。

(1 + v²)/v. Rearranging: x dv/dx = 1/v. Separating: v dv = (1/x) dx, integrate: v²/2 = ln|x| + C. Substituting back: (y/x)²/2 = ln|x| + C, or y² = 2x² ln|x| + K x².

例题:dy/dx = (x² + y²)/(x y)。分子分母同除以 x²:dy/dx = (1 + (y/x)²)/(y/x)。令 v = y/x,则 v + x dv/dx = (1 + v²)/v。整理得 x dv/dx = 1/v。分离变量:v dv = (1/x) dx,积分:v²/2 = ln|x| + C。代回: (y/x)²/2 = ln|x| + C,或 y² = 2x² ln|x| + K x²。


8. Bernoulli Equations | 伯努利方程

0,1. Although nonlinear, it can be reduced to a linear equation by the substitution z = y1–n. Differentiating gives dz/dx = (1–n) y–n dy/dx. Multiplying the original equation by (1–n) y–n yields a linear equation in z.

伯努利方程是形如 dy/dx + P(x) y = Q(x) yⁿ 的非线性一阶常微分方程,其中 n 为实常数,且 n ≠ 0,1。该方程虽为非线性,但可通过代换 z = y1–n 化为线性方程。求导得 dz/dx = (1–n) y–n dy/dx。将原方程乘以 (1–n) y–n 即得关于 z 的线性方程。

After substitution, the equation becomes dz/dx + (1–n) P(x) z = (1– r in z and can be solved using an integrating factor. Once z is found, recover y = z^(1/(1–n)).

代换后,方程化为 dz/dx + (1–n) P(x) z = (1–n) Q(x),这是关于 z 的线性方程,可用积分因子法求解。求得 z 后,通过 y = z^(1/(1–n)) 还原 y。

Example: dy/dx – y = x y². Here P(x) = –1, Q(x) = x, n = 2. Let z = y1–2 = y–1. Then dz/dx = –y–2 dy/dx. Multiplying the original equation by –y–2 gives –y–2 dy/dx + y–1 = –x. That is dz/dx + z = –x. Solve this linear equation: μ = e∫1 dx = ex, so ex z = ∫ –x ex dx. Integration by parts gives –x ex + ex + C, hence z = –x + 1 + C e–x. Finally y = 1/z = 1/(1 – x + C e–x).

例题:dy/dx – y = x y²。此处 P(x) = –1,Q(x) = x,n = 2。令 z = y1–2 = y–1。则 dz/dx = –y–2 dy/dx。原方程乘以 –y–2 得 –y–2 dy/dx + y–1 = –x,即 dz/dx + z = –x。解该线性方程:μ = e∫1 dx = ex,所以 ex z = ∫ –x ex dx。分部积分得 –x ex + ex + C,因此 z = –x + 1 + C e–x。最终 y = 1/z = 1/(1 – x + C e–x)。


9. Slope Fields and Qualitative Analysis | 斜率场与定性分析

urves and helps identify equilibrium solutions where dy/dx = 0. It also allows us to sketch approximate solutions passing through a given initial point without solving the equation explicitly.

即便一阶常微分方程无法解析求解,也可以通过斜率场研究其行为。给定 dy/dx = f(x,y),我们在网格点处计算 f 的值,并画出相应斜率的短线段。这种图形表示揭示了积分曲线的大致形状,并有助于识别使 dy/dx = 0 的平衡解。它也使我们无需显式求解方程,便可绘制通过给定初始点的近似解曲线。

elds a slope field in which solution curves trend upward as x and y increase. The line y = –x – 1 makes dy/dx = –1, while along y = –x the slope is zero. By tracing the field, we imagine how particular solutions evolve.

例如,方程 dy/dx = x + y 产生的斜率场中,当 x 和 y 增大时,解曲线上扬。直线 y = –x – 1 上斜率为 –1,而沿着 y = –x 斜率为零。通过追踪斜率场,我们可以想象特解的演化

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