← 返回资讯屏轩教育 · 行业资讯

Exercise 13D: Trigonometric Equations | 练习13D:三角方程

2026-08-02 22:33 · 本文部分内容由AI辅助创作

📚 Exercise 13D: Trigonometric Equations | 练习13D:三角方程

Trigonometric equations are a cornerstone of the IB Mathematics curriculum, appearing in both Analysis and Approaches (AA) and Applications and Interpretation (AI) courses. Exercise 13D targets the essential skill of solving equations involving sine, cosine, and tangent functions, building a strong foundation for calculus, wave analysis, and modelling periodic phenomena. In this article, we explore systematic strategies to tackle such problems, from using the unit circle to applying trigonometric identities, preparing you to handle any equation confidently.

三角方程是IB数学课程的重要基石,同时出现在分析与方法 (AA) 以及应用与解释 (AI) 课程中。练习13D专门练习求解含有正弦、余弦和正切函数的方程,为微积分、波动分析以及周期性现象建模打下坚实基础。本文将探索系统的解题策略,从运用单位圆到应用三角恒等式,帮助你自信地应对任何方程。


1. Understanding Trigonometric Equations | 理解三角方程

of an unknown angle. Common examples include sin x = 0.5, 2cos²θ − cos θ = 0, or tan(2x) = √3 tions within a given interval, such as 0 ≤ x ≤ 2π, or to express the general solution set.

三角方程是包含未知角的三角函数的任何方程。常见例子有 sin x = 0.5、2cos²θ − cos θ = 0 或 tan(2x) = √3。与代数方程不同,由于三角函数的周期性,三角方程通常有无穷多个解。我们的目标通常是在给定区间(如 0 ≤ x ≤ 2π)内求出所有解,或者写出通解集合。


2. The Power of the Unit Circle | 单位圆的威力

n radians, the circle makes it easy to locate all angles sharing the same sine, cosine, or tangent value. The x-coordinate of a point on the unit circle gives cos θ, the y-coordinate gives sin θ, and the ratio y/x gives tan θ (where defined). Remember that sine is positive in the first and second quadrants, cosine in the first and fourth, and tangent in the first and third.

单位圆是直观呈现 sin x = k、cos x = k 和 tan x = k 的解的不可或缺的工具。对于以弧度表示的角,单位圆可以轻易地定位出具有相同正弦、余弦或正切值的所有角。单位圆上某点的 x 坐标给出 cos θ,y 坐标给出 sin θ,比值 y/x 给出 tan θ(在有定义处)。请记住,正弦在第一和第二象限为正,余弦在第一和第四象限为正,正切在第一和第三象限为正。


3. Solving Basic Sine Equations | 解基本正弦方程

Consider the equation sin x = k, where |k| . To find the principal solutions, first determine the reference angle α such that sin α = |k| utions are obtained by adding integer multiples of 2π: x = α + 2nπ or x = (π − α) + 2nπ, n ∈ ℤ.

考虑方程 sin x = k,其中 |k| ≤ 1。为求主解,需先确定参考角 α,使得 sin α = |k|。例如,若 sin x = ½,参考角为 α = π/6。在区间 [0, 2π) 内的解为 x = α(第一象限)和 x = π − α(第二象限),即 x = π/6 和 5π/6。所有其他解可通过加上 2π 的整数倍得到:x = α + 2nπ 或 x = (π − α) + 2nπ,n ∈ ℤ。


4. Mastering Cosine Equations | 掌握余弦方程

For cos x = k, where −1 ≤ k ≤ 1, we again find the reference angle α with cos α = |k| x = α + 2nπ and x = −α + 2nπ. Always check the specific interval required in the exercise.

对于 cos x = k,−1 ≤ k ≤ 1,我们同样找出参考角 α,满足 cos α = |k|。以 cos x = ½ 为例,α = π/3。余弦在第一和第四象限为正,因此主解为 x = α 和 x = 2π − α,即 x = π/3 和 5π/3。其通解集可写作 x = ±α + 2nπ,或更清晰地写为 x = α + 2nπ 和 x = −α + 2nπ。一定要根据练习要求检验特定的区间。


5. Working with Tangent Equations | 处理正切方程

s like tan x = k have a period of π, meaning solutions repeat every π radians. For tan x = √3, the reference angle is π/3 because tan(π/3) = √3 and x = π + π/3 = 4π/3. The general solution can be expressed compactly as x = π/3 + nπ, n ∈ ℤ. This compact form highlights the advantage of recognising the period.

像 tan x = k 这样的正切方程以 π 为周期,意味着解每隔 π 弧度重复一次。对于 tan x = √3,参考角为 π/3,因为 tan(π/3) = √3。正切在第一和第三象限为正,因此主解为 x = π/3 和 x = π + π/3 = 4π/3。通解可简洁地表示为 x = π/3 + nπ,n ∈ ℤ。这种简洁形式凸显了识别周期性的优势。


广告 / Sponsored

6. General Solutions and Integer Multiples | 通解与整数倍

IB exam questions often ask for the general solution to a trigonometric equation. The general solution captures all possible angles that satisfy the equation, using an integer parameter n. The three fundamental patterns are:

IB考题经常要求写出三角方程的通解。通解通过一个整数参数 n,包含了满足方程的所有可能角度。三个基本模式如下:

using inverse trigonometric functions, e.g., α = arcsin(0.5) = π/6. Do not forget to set n ∈ ℤ (integers).

始终需要用反三角函数明确定义 α,例如 α = arcsin(0.5) = π/6。不要忘记标明 n ∈ ℤ(整数集合)。


7. Solving within a Given Interval | 在给定区间内求解

s cos x = −½, giving α = π/3. Solutions are x = π − π/3 = 2π/3 and x = π + π/3 = 4π/3, both within the interval.

练习13D中的许多问题都限定了定义域,例如 0 ≤ x ≤ 360° 或 −π ≤ θ ≤ π。先求出通解,然后代入连续的整数值 n,得到具体角度。列出所有落在目标区间内的解。比如在 [0, 2π) 上解 2cos x + 1 = 0,先化为 cos x = −½,得 α = π/3。解为 x = π − π/3 = 2π/3 和 x = π + π/3 = 4π/3,两者都在区间内。


8. Using Trigonometric Identities to Simplify | 利用三角恒等式化简

nsformed using cos 2x = 1 − 2sin²x to become 1 − 2sin²x + sin x = 0, a quadratic in sin x.

有些方程在原形下无法直接求解,需要运用恒等式。常见恒等式包括 sin²x + cos²x = 1、tan x = sin x / cos x,以及倍角公式,如 cos 2x = 1 − 2sin²x。例如,方程 cos 2x + sin x = 0 可利用 cos 2x = 1 − 2sin²x 转化为 1 − 2sin²x + sin x = 0,这是一个关于 sin x 的二次方程。


9. Tackling Quadratic Trigonometric Equations | 攻克二次型三角方程

to reject any u outside [−1, 1]. Always check the validity of factorised solutions, as not all will yield real angles.

像 2sin²θ − sin θ − 1 = 0 这样的方程是关于 sin θ 的二次方程。令 u = sin θ,得到 2u² − u − 1 = 0。因式分解为 (2u + 1)(u − 1) = 0,故 u = −½ 或 u = 1。然后分别求解 sin θ = −½ 和 sin θ = 1。注意舍去任何在 [−1, 1] 之外的 u 值。始终检查因式分解所得的解是否有效,因为不是所有的 u 都能对应实数角。


10. Double- and Half-Angle Equations | 倍角与半角方程

3π/12, 17π/12, ensuring each x remains in the original interval. Always expand the range appropriately before dividing.

当角度是 x 的倍数或分数时,如 2x 或 x/2,先对复合角求解。假设在 0 ≤ x ≤ 2π 上解 sin(2x) = ½。令 θ = 2x,则由 sin θ = ½ 得到 θ = π/6、5π/6、13π/6、17π/6 等。然后除以 2 得到 x = π/12、5π/12、13π/12、17π/12,确保每个 x 仍在原区间内。在除以系数前,务必适当扩大角的范围。


11. Avoiding Common Mistakes | 避免常见错误

Students often forget that sine and cosine values must lie between −1 and 1. Always check that the given constant k is valid; |k| > 1 means no solution. Another frequent error is mixing degrees and radians – IB questions normally specify the unit, but it’s safer to work consistently. Also, don’t lose solutions when diving both sides by a trigonometric expression, as it could be zero. Instead, factorise and set each factor to zero.

学生常忘记正弦和余弦值必须在 −1 到 1 之间。务必检查给定的常量 k 是否有效;|k| > 1 意味着无解。另一个常见错误是混淆角度与弧度——IB 题目通常会标明单位,但始终保持统一更安全。此外,不要轻易将方程两边同除以一个三角函数表达式,因为它可能为零。正确的做法是因式分解并令每个因式为零。


12. Practical Tips for IB Success | IB 成功实用技巧

ore restricting it to the given interval. Practice with both exact values (e.g., sin π/4 = √2/2) and decimal approximations where required. Finally, double-check your answers by substituting them back into the original equation. These disciplined steps will build fluency and earn top marks on the IB exam.

在做练习13D时,始终画出单位圆或三角函数草图,以预估解的个数。清晰地写下参考角。标出象限,写出通解,再按给定区间筛选。既要用精确值(如 sin π/4 = √2/2),也要在需要时练习求近似小数解。最后,将答案代回原方程进行检验。这些严谨的步骤将培养解题的熟练度,助你在IB考试中斩获高分。

Published by TutorHao | Mathematics Revision Series | aleveler.com

广告 / Sponsored
官网正版 国际课程数学核心词汇 唯寻国际教育 全英 学科 GCSE A Level IB MYP IB IBDP 美高…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥19.7

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao