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Arc Length | 弧长

2026-08-02 15:22 · 本文部分内容由AI辅助创作

📚 Arc Length | 弧长

Arc length is a fundamental concept in calculus that measures the distance along a curved line between two points.

弧长是微积分中的一个基本概念,用于测量曲线上两点之间沿曲线的距离。

In A-Level Edexcel Mathematics, you need to compute arc lengths using definite integrals in Cartesian, parametric, and polar forms.

在A-Level Edexcel 数学中,你需要使用定积分计算笛卡尔坐标、参数方程和极坐标形式的弧长。

1. Understanding How Arc Length is Derived | 弧长公式的推导理解

To find the arc length, we approximate the curve by many small straight segments and sum their lengths, then take the limit as segment length approaches zero.

为了求弧长,我们将曲线近似为许多小的直线段,求长度之和,然后取极限,使段长趋近于零。

l segment length Δs satisfies (Δs)² ≈ (Δx)² + (Δy)², leading to the differential form ds = √dx² + dy².

利用勾股定理,小段长度 Δs 满足 (Δs)² ≈ (Δx)² + (Δy)²,从而得出微分形式 ds = √dx² + dy²。

Depending on how the curve is defined, we rewrite ds in terms of a single variable to obtain an integrable expression.

根据曲线定义方式的不同,我们将 ds 改写为单一变量的形式,以便进行积分。


2. Arc Length for Cartesian Curves y = f(x) | 笛卡尔曲线 y = f(x) 的弧长

For a curve defined as y = f(x) from x = a to x = b, the arc length s is given by s = ∫ab √(1 + (dy/dx)²) dx.

对于定义为 y = f(x) 从 x = a 到 x = b 的曲线,弧长 s 由公式 s = ∫ab √(1 + (dy/dx)²) dx 给出。

om factoring out dx in ds: ds = √(1 + (dy/dx)²) dx, where dy/dx is the derivative of f(x).

此公式来源于在 ds 中提取 dx:ds = √(1 + (dy/dx)²) dx,其中 dy/dx 是 f(x) 的导数。

Always ensure the function is smooth (differentiable) on the interval to apply the formula correctly.

务必确保函数在该区间上是光滑的(可导),才能正确应用此公式。


3. Arc Length for Parametric Curves | 参数曲线的弧长

rve is given parametrically by x = f(t), y = g(t) for t₁ ≤ t ≤ t₂, the arc length is s = ∫t₁t₂ √((dx/dt)² + (dy/dt)²) dt.

若曲线由参数方程 x = f(t), y = g(t) 给出,t₁ ≤ t ≤ t₂,则弧长为 s = ∫t₁t₂ √((dx/dt)² + (dy/dt)²) dt。

The expression under the square root represents the square of the speed, i.e., the magnitude of the velocity vector (dx/dt, dy/dt).

平方根内的表达式代表速度大小的平方,即速度向量 (dx/dt, dy/dt) 的模的平方。

Parametric form is powerful because it handles curves that are not functions of x, such as circles and loops.

参数形式功能强大,因为它能处理不是 x 的函数的曲线,例如圆和环线。


4. Arc Length in Polar Coordinates | 极坐标中的弧长

For a polar curve r = f(θ) from θ = α to θ = β, the arc length is s = ∫αβ √(r² + (dr/dθ)²) dθ.

对于极坐标曲线 r = f(θ),从 θ = α 到 θ = β,弧长为 s = ∫αβ √(r² + (dr/dθ)²) dθ。

by considering x = r cosθ, y = r sinθ as parametric equations and applying the chain rule.

这一公式是将 x = r cosθ, y = r sinθ 视为参数方程并应用链式法则推导出来的。

Polar curves often exhibit symmetry, which can simplify the limits of integration significantly.

极坐标曲线往往具有对称性,可用来大幅简化积分限。


5. Worked Example – Cartesian Curve | 例题解析——笛卡尔曲线

Find the length of the curve y = (2/3)x3/2 from x = 0 to x = 1.

求曲线 y = (2/3)x3/2 从 x = 0 到 x = 1 的长度。

First, compute dy/dx = x1/2. Then 1 + (dy/dx)² = 1 + x, so s = ∫01 √1 + x dx.

首先求导得 dy/dx = x1/2。于是 1 + (dy/dx)² = 1 + x,因此 s = ∫01 √1 + x dx。

Integrate using substitution u = 1 + x: s = (2/3)[(1+x)3/2]01 = (2/3)(2√2 − 1).

用代换 u = 1 + x 积分:s = (2/3)[(1+x)3/2]01 = (2/3)(2√2 − 1)。

This yields an exact answer, which is the typical expectation for Edexcel arc length questions.

这给出了精确答案,符合 Edexcel 弧长题目的典型要求。


6. Worked Example – Parametric Curve | 例题解析——参数曲线

h of one arch of the cycloid defined by x = a(t − sin t), y = a(1 − cos t) for 0 ≤ t ≤ 2π.

求摆线 x = a(t − sin t), y = a(1 − cos t) 在 0 ≤ t ≤ 2π 上一拱的弧长。

a(1 − cos t), dy/dt = a sin t. Then (dx/dt)² + (dy/dt)² = a²(2 − 2 cos t) = 4a² sin²(t/2).

计算 dx/dt = a(1 − cos t), dy/dt = a sin t。则 (dx/dt)² + (dy/dt)² = a²(2 − 2 cos t) = 4a² sin²(t/2)。

Thus √... = 2a sin(t/2) for t in [0, 2π]. Integrate: s = ∫02π 2a sin(t/2) dt = 8a.

因此平方根为 2a sin(t/2)(t∈[0,2π])。积分得 s = ∫02π 2a sin(t/2) dt = 8a。

Notice that using the half-angle identity simplifies the radical, a key technique in such problems.

注意,使用半角恒等式简化了根式,这是此类问题的关键技巧。


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7. Worked Example – Polar Curve | 例题解析——极坐标曲线

Find the total length of the cardioid r = a(1 + cosθ).

求心脏线 r = a(1 + cosθ) 的总长度。

r/dθ = −a sinθ. Then r² + (dr/dθ)² = a²(1+cosθ)² + a² sin²θ = 2a²(1+cosθ) = 4a² cos²(θ/2).

由对称性,可将 θ 从 0 到 π 的长度加倍。计算 dr/dθ = −a sinθ。那么 r² + (dr/dθ)² = a²(1+cosθ)² + a² sin²θ = 2a²(1+cosθ) = 4a² cos²(θ/2)。

For 0 ≤ θ ≤ π, cos(θ/2) ≥ 0, so the square root is 2a cos(θ/2). Integrate shalf = ∫0π 2a cos(θ/2) dθ = 4a. Total s = 8a.

对于 0 ≤ θ ≤ π,cos(θ/2) ≥ 0,平方根为 2a cos(θ/2)。积分半长 shalf = ∫0π 2a cos(θ/2) dθ = 4a。总长 s = 8a。

Polar arc length problems frequently require trigonometric simplifications and clever use of symmetry.

极坐标弧长问题通常需要三角化简和灵活运用对称性。


8. Common Mistakes to Avoid | 常见错误及避免方法

Forgetting to square the derivatives before adding; e.g., writing √dx/dt + dy/dt instead of √((dx/dt)² + (dy/dt)²).

忘记先平方再相加;例如写成 √dx/dt + dy/dt 而非 √((dx/dt)² + (dy/dt)²)。

Incorrect limits: ensure they match the variable of integration, especially in parametric and polar forms where limits are parameter values or angles.

积分限错误:务必使积分限与积分变量一致,特别是在参数和极坐标形式中,积分限是参数值或角度。

g absolute values when taking the square root of a squared expression, e.g., √(sin²(t)) is |sin t|, not simply sin t if sin t could be negative.

对平方开方时不考虑绝对值,例如 √(sin²(t)) = |sin t|,而在 sin t 可能为负时不能直接写成 sin t。

Overlooking the need for the curve to be smooth; discontinuities in the derivative cause the integral to be improper and may invalidate the formula.

忽略曲线需光滑的条件;导数不连续会导致积分为反常积分,并可能使公式失效。


9. Using Symmetry to Simplify Calculations | 利用对称性简化计算

Many exam questions feature symmetric curves, such as circles, cardioids and rose curves, where you can integrate over a half or quarter period and multiply.

许多考题涉及对称曲线,如圆、心脏线和玫瑰线,你可以对半个或四分之一周期积分再相乘。

Always check for symmetry about the x-axis, y-axis, or the origin, and adjust the limits and multipliers carefully.

务必检查关于 x 轴、y 轴或原点的对称性,并仔细调整积分限和倍数。

Using symmetry saves time, reduces algebraic complexity, and helps avoid sign errors during integration.

利用对称性能节省时间、降低代数复杂度,并有助于避免积分过程中的符号错误。


10. Exam Tips for Edexcel A-Level Arc Length Questions | Edexcel A-Level 弧长题目的考试技巧

Show clearly the step of setting up ds, writing the definite integral, and simplifying the integrand before integrating.

清晰地展示建立 ds、写出定积分表达式并在积分前化简被积函数的步骤。

r differentiation or look for identities such as double-angle formulas or sin² + cos² = 1.

如果积分显得过于困难,重新检查你的求导,或寻找如倍角公式、sin² + cos² = 1 等恒等式。

Memorise the three arc length forms: Cartesian (1 + (dy/dx)²), parametric ((dx/dt)² + (dy/dt)²), and polar (r² + (dr/dθ)²).

熟记三种弧长形式:笛卡尔(1 + (dy/dx)²)、参数((dx/dt)² + (dy/dt)²)和极坐标(r² + (dr/dθ)²)。

For polar curves, always start with r² + (dr/dθ)² and simplify using trigonometric identities before taking the square root.

对于极坐标曲线,始终从 r² + (dr/dθ)² 开始,并利用三角恒等式化简后再开方。

Keep answers in exact form (multiples of π or surds) unless the question explicitly asks for a decimal approximation.

除非题目明确要求小数近似,答案需保持精确形式(π 的倍数或根式)。


11. Connecting Arc Length to Further Integration Techniques | 弧长与进阶积分方法的联系

Arc length integrals sometimes require advanced techniques such as integration by substitution, trigonometric integrals, or completing the square.

弧长积分有时需要进阶技巧,如代换积分法、三角积分或配方法。

For instance, simplifying √(1 + (dy/dx)²) might lead to an expression like √a² − x², which invites a trigonometric substitution.

例如,化简 √(1 + (dy/dx)²) 可能得到类似 √a² − x² 的表达式,这就需要进行三角代换。

Practising these integrations in advance builds the fluency needed to handle unfamiliar curves in the exam.

提前练习这些积分方法可以培养处理考试中陌生曲线所需的熟练度。


12. Summary and Conclusion | 总结与结论 Published by TutorHao | A-Level Revision Series | aleveler.com

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