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Understanding Motion | 理解运动

2026-08-02 13:46 · 本文部分内容由AI辅助创作

📚 Understanding Motion | 理解运动

Kinematics is the branch of physics that describes the motion of objects without considering the forces that cause the motion. In the CIE A-Level Physics syllabus, mastering the concepts of displacement, velocity, acceleration, and their graphical representations is essential. This article explores motion in one and two dimensions, from uniform straight-line motion to projectile motion, building a solid foundation for mechanics.

运动学是物理学中描述物体运动的分支,而不考虑引起运动的力。在 CIE A-Level 物理课程中,掌握位移、速度、加速度及其图线表示等概念至关重要。本文从匀速直线运动到抛体运动,探讨一维和二维运动,为力学打下坚实基础。

1. Scalars and Vectors in Kinematics | 运动学中的标量与矢量

A scalar quantity has magnitude only. Mass, time, and temperature are examples of scalars. Distance and speed are also scalar quantities used to describe motion.

标量只有大小。质量、时间和温度都是标量。距离和速率也是用来描述运动的标量。

A vector quantity has both magnitude and direction. Displacement, velocity, and acceleration are vector quantities. It is essential to treat them with a sign convention or by using vector addition when solving problems.

矢量既有大小又有方向。位移、速度和加速度都是矢量。在解题时,必须用符号约定或矢量加法来处理它们。


2. Distance and Displacement | 距离与位移

Distance is the total length of the path traveled by an object. It is a scalar and is always positive. For example, if a car drives 10 km north, then 10 km south, the distance traveled is 20 km.

距离是物体运动路径的总长度。它是标量,总是正的。例如,一辆汽车先向北行驶 10 公里,再向南行驶 10 公里,通过的距离为 20 公里。

Displacement is the straight-line distance from the initial position to the final position in a specific direction. In the same car example, the displacement is 0 km because the car returns to its starting point. Displacement can be positive, negative, or zero.

位移是初位置到末位置的直线有向距离。在上例中,位移为零公里,因为汽车回到了起点。位移可以为正、为负或为零。


3. Speed and Velocity | 速率与速度

Average speed is defined as total distance divided by total time taken. It gives no information about direction. Instantaneous speed is the speed at a particular instant in time.

平均速率定义为总距离除以总时间。它不提供方向信息。瞬时速率是某一特定时刻的速率。

isplacement / total time. Since it is a vector, a change in direction means a change in velocity, even if the speed is constant. Instantaneous velocity is the velocity at an instant, equal to the gradient of the displacement–time graph.

速度是位移的变化率。平均速度 = 总位移 / 总时间。由于它是矢量,方向的改变意味着速度的改变,即使速率不变。瞬时速度是某时刻的速度,等于位移-时间图线的斜率。


4. Acceleration: Definition and Calculation | 加速度:定义与计算

Acceleration is defined as the rate of change of velocity. It is a vector. The SI unit is m s⁻². If an object slows down, it has negative acceleration, often called deceleration or retardation.

加速度定义为速度的变化率。它是矢量。国际单位是米每二次方秒(m s⁻²)。如果物体减速,它具有负加速度,常称为减速度或减速。

e Δv is the change in velocity. For constant acceleration problems, this formula is the starting point. On a velocity–time graph, acceleration is the gradient.

平均加速度 a = Δv / Δt,其中 Δv 是速度的变化量。对于匀加速问题,这个公式是出发点。在速度-时间图上,加速度是斜率。


5. Motion Graphs: Displacement–Time | 运动图像:位移-时间图

On a displacement–time (s–t) graph, the gradient at any point gives the instantaneous velocity. A straight line with a constant positive gradient indicates uniform positive velocity. A horizontal line means the object is stationary.

在位移-时间 (s–t) 图上,任意点的斜率给出瞬时速度。一条具有恒定正斜率的直线表示匀速正向运动。水平线表示物体静止。

A curved line on an s–t graph indicates changing velocity, i.e. acceleration. If the curve becomes steeper with time, the speed is increasing. The area under an s–t graph has no useful physical meaning.

s–t 图上的曲线表示速度在变化,即存在加速度。若曲线随时间变得越来越陡,说明速率增加。s–t 图下的面积没有有用的物理意义。


6. Motion Graphs: Velocity–Time and Acceleration–Time | 速度-时间与加速度-时间图

A velocity–time (v–t) graph is extremely useful. The gradient gives the instantaneous acceleration, and the area under the graph between two times gives the change in displacement (or distance if motion is in one direction).

速度-时间 (v–t) 图非常有用。斜率给出瞬时加速度,而图线下两个时刻之间的面积给出位移的变化(若运动方向不变,也等于路程)。

An acceleration–time (a–t) graph can show when acceleration is constant or varying. The area under the a–t graph between two times gives the change in velocity. In uniform acceleration, a–t is a horizontal line.

加速度-时间 (a–t) 图可显示加速度是恒定还是变化。a–t 图下两时刻之间的面积给出速度的变化量。在匀加速运动中,a–t 图是一条水平线。


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7. Equations of Uniformly Accelerated Motion | 匀加速运动方程

For motion in a straight line with constant acceleration, four equations relate the five quantities: u (initial velocity), v (final velocity), a (acceleration), t (time), and s (displacement).

对于匀加速直线运动,有四个方程联系着五个物理量:u(初速度),v(末速度),a(加速度),t(时间)和 s(位移)。

v = u + a t

s = (u + v)t / 2

s = u t + ½ a t²

v² = u² + 2 a s


8. Applying the Equations: Signs and Directions | 应用方程:符号与方向

motion, up is often taken as positive, making gravitational acceleration g = −9.81 m s⁻².

由于速度、加速度和位移都是矢量,必须定义一个正方向。在竖直运动中,通常取向上为正,那么重力加速度 g = −9.81 m s⁻²。

When an object is thrown upward, its velocity decreases, passes through zero at maximum height, and then becomes negative on the way down. The acceleration remains constant at −9.81 m s⁻² throughout the flight.

当物体被向上抛出时,其速度减小,在最高点处为零,然后在下落过程中变为负值。在整个飞行过程中,加速度保持 −9.81 m s⁻² 不变。


9. Free Fall and Vertical Motion | 自由落体与竖直运动

ce). All the equations of motion apply, with a = g or a = −g depending on sign convention.

仅在重力作用下下落的物体具有向下的恒定加速度 g = 9.81 m s⁻²(忽略空气阻力)。所有运动方程均适用,根据符号约定 a = g 或 a = −g。

quation. For a vertically projected object, the time to reach maximum height is t = u / g.

飞行时间、最大高度和落地速度可通过将已知值代入相应方程来计算。对于竖直上抛的物体,到达最大高度的时间为 t = u / g。


10. Projectile Motion: Independence of Horizontal and Vertical Motions | 抛体运动:水平与竖直运动的独立性

In projectile motion, the horizontal and vertical components of motion are independent. Horizaontal velocity remains constant (ignoring air resistance), while vertical motion is uniformly accelerated downwards at g.

在抛体运动中,运动的水平分量和竖直分量相互独立。水平速度保持不变(忽略空气阻力),而竖直运动以 g 向下做匀加速运动。

To analyse a projectile, resolve the initial velocity u at angle θ to the horizontal. The horizontal component is u cos θ, and the initial vertical component is u sin θ. These components are used separately in kinematic equations.

要分析抛体,先将初速度 u 按与水平面的夹角 θ 分解。水平分量为 u cos θ,初始竖直分量为 u sin θ。这些分量分别用于运动学方程中。


11. Solving Projectile Motion Problems | 解决抛体运动问题

The time of flight is determined entirely by vertical motion. Using s = uy t + ½ ay t², with vertical displacement possibly zero (same level), you can solve for t. The body hits the ground when vertical displacement matches the initial height difference.

飞行时间完全由竖直运动决定。利用 s = uy t + ½ ay t²,若竖直位移可能为零(等高起落),就可以解出 t。当竖直位移等于初始高度差时,物体落地。

The horizontal range is horizontal velocity multiplied by time of flight. The maximum range on level ground occurs at 45°. Maximum height is found using vy² = uy² + 2 ay s, with vy = 0 at the peak.

水平射程等于水平速度乘以飞行时间。在水平地面上,最大射程出现在 45° 抛射角时。最大高度可用 vy² = uy² + 2 ay s 求得,在最高点 vy = 0。


12. Motion with Air Resistance (Qualitative) | 考虑空气阻力的运动(定性)

Air resistance opposes the motion and increases with speed. For a falling object, air resistance reduces the net acceleration, leading to a terminal velocity when drag equals weight.

空气阻力阻碍运动,且随速度增加而增大。对于下落物体,空气阻力使净加速度减小,当阻力等于重力时,物体达到终极速度。

In projectile motion, air resistance causes the path to be asymmetric: the range and maximum height are reduced, and the trajectory is no longer parabolic. The angle for maximum range becomes less than 45°.

在抛体运动中,空气阻力使路径不对称:射程和最大高度都减小,轨迹不再是抛物线。最大射程对应的抛射角小于 45°。

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