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Electronic Configurations | 电子排布

2026-08-02 12:28 · 本文部分内容由AI辅助创作

📚 Electronic Configurations | 电子排布

Understanding electronic configurations is central to A-Level Chemistry. It explains how electrons are arranged in atoms, which in turn determines chemical properties, bonding behaviour, and periodic trends. This article covers everything you need to know about writing and interpreting electronic configurations according to the Cambridge International specification.

理解电子排布是A-Level化学的核心内容。它解释了电子在原子中的排列方式,进而决定了化学性质、成键行为以及周期性的变化趋势。本文将涵盖根据剑桥国际考试大纲你需要掌握的关于书写和解读电子排布的所有知识点。

1. Introduction to Electronic Configurations | 电子排布简介

Electronic configuration describes the distribution of electrons in an atom's orbitals. Electrons occupy specific energy levels and sub-levels around the nucleus, following a set of rules. Knowing how to write and interpret these configurations helps predict an element’s reactivity, its position in the periodic table, and the type of ions it forms.

电子排布描述的是原子轨道中电子的分布情况。电子按照一系列规则占据原子核周围特定的能级和亚层。学会书写和解读电子排布有助于预测元素的反应活性、在周期表中的位置以及形成的离子类型。


2. Energy Levels and Sub-shells | 能级与亚层

mber of sub-shells in a shell equals n. For example, the first shell (n=1) has only an s sub-shell; the second shell (n=2) has s and p sub-shells; the third shell (n=3) has s, p, and d sub-shells. Each sub-shell consists of a specific number of atomic orbitals, and each orbital can hold up to two electrons.

电子位于标记为 n = 1, 2, 3, 4 等的主能级(电子层)中。每一层包含 s, p, d, f 等亚层。一个电子层中亚层的数量等于 n。例如,第一层 (n=1) 只有 s 亚层;第二层 (n=2) 有 s 和 p 亚层;第三层 (n=3) 有 s, p 和 d 亚层。每个亚层由特定数量的原子轨道组成,每个轨道最多可容纳两个电子。

Sub-shellNumber of orbitalsMaximum electrons
s12
p36
d510
f714

3. Atomic Orbitals: Shapes and Types | 原子轨道:形状与类型

An atomic orbital is a region of space where there is a high probability of finding an electron. s orbitals are spherical. Each p orbital has a dumbbell shape and there are three p orbitals oriented along the x, y, and z axes (px, py, pz). d orbitals have more complex shapes; four of the five d orbitals are clover-leaf shaped, while the fifth (dz²) has a doughnut-like ring around a lobe. Understanding orbital shapes is important for visualising bonding and molecular geometry.

原子轨道是电子出现概率很高的空间区域。s 轨道呈球形。每个 p 轨道呈哑铃形,有三个 p 轨道分别沿 x, y, z 轴取向(px, py, pz)。d 轨道形状更复杂;五个 d 轨道中有四个呈四瓣花形,第五个(dz²)具有在一个凸起周围环绕着类似甜甜圈的形状。理解轨道形状对于想象化学键和分子几何结构非常重要。


4. Rules for Filling Orbitals | 轨道填充规则

Three fundamental rules govern how electrons fill orbitals:

三条基本规则决定了电子如何填充轨道:

Energy order: 1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7p


5. Writing Electronic Configurations: Notation | 书写电子排布:符号表示

The standard notation lists sub-shells in order of increasing energy (or by principal quantum number for full configurations) with superscripts indicating the number of electrons. For example, oxygen (atomic number 8) has the configuration 1s² 2s² 2p⁴. For calcium (20), the configuration is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s². It is essential to write the sub-shells in the correct sequence; when using the full notation, many textbooks list by shell number first (e.g., 1s 2s 2p 3s 3p 3d 4s). However, the 4s sub-shell is filled before 3d because it is lower in energy for neutral atoms.

标准表示法按照能量递增的顺序(或对完整排布按主量子数顺序)列出亚层,并用上标标明电子数。例如,氧(原子序数8)的电子排布为 1s² 2s² 2p⁴。钙(20)的电子排布为 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²。必须以正确的顺序书写亚层;使用完整表示法时,许多教材会先按能层序号列出(如 1s 2s 2p 3s 3p 3d 4s)。但要注意,4s 亚层的能量低于 3d,因此中性原子中 4s 先填充。

Example: Iron (Fe, Z=26) → 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

When writing configurations for transition metals, the 3d sub-shell is often written after 4s even though 4s is filled first, because once electrons occupy 3d, it falls below 4s in energy. For Fe, either 4s² 3d⁶ or 3d⁶ 4s² is acceptable, but Cambridge typically uses the order of increasing principal quantum number: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s².

书写过渡金属的电子排布时,通常将 3d 亚层写在 4s 之后,尽管 4s 先被填满,因为一旦有电子占据 3d,3d 的能量就会低于 4s。对于铁,4s² 3d⁶ 或 3d⁶ 4s² 都可接受,但剑桥考试通常按主量子数递增的顺序:1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s²。


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6. Shorthand Notation Using Noble Gas Cores | 使用稀有气体核心的简写表示

e gas in square brackets. For instance, sodium (Na, Z=11) has the configuration 1s² 2s² 2p⁶ 3s¹, which can be abbreviated as [Ne] 3s¹. Calcium (Ca, Z=20) becomes [Ar] 4s². This notation highlights the valence electrons and is widely used in periodicity discussions.

对于电子数较多的元素,常用简写形式,即将内层电子排布用前一周期的稀有气体元素符号加方括号代替。例如,钠 (Na, Z=11) 的电子排布为 1s² 2s² 2p⁶ 3s¹,可简写为 [Ne] 3s¹。钙 (Ca, Z=20) 可简写为 [Ar] 4s²。这种表示法突出了价电子,在讨论周期律时被广泛使用。

ElementZFull configurationShorthand
Chlorine171s² 2s² 2p⁶ 3s² 3p⁵[Ne] 3s² 3p⁵
Vanadium231s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³[Ar] 4s² 3d³
Bromine351s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵[Ar] 4s² 3d¹⁰ 4p⁵

7. Electronic Configurations of Ions | 离子的电子排布

When atoms form positive ions (cations), electrons are removed from the highest energy level first. For transition metals, this means the 4s electrons are lost before the 3d electrons. For example, Fe atom: [Ar] 4s² 3d⁶; Fe²⁺: [Ar] 3d⁶; Fe³⁺: [Ar] 3d⁵. Negative ions (anions) are formed by adding electrons to the valence shell. For instance, O²⁻: 1s² 2s² 2p⁶ or [Ne]. Always write the ion’s configuration based on the number of electrons present.

当原子形成阳离子时,电子首先从最高能级失去。对过渡金属而言,这意味着 4s 电子先于 3d 电子失去。例如,Fe 原子:[Ar] 4s² 3d⁶;Fe²⁺:[Ar] 3d⁶;Fe³⁺:[Ar] 3d⁵。阴离子则由价层获得电子形成。例如 O²⁻:1s² 2s² 2p⁶ 或 [Ne]。书写离子排布时,务必根据实际电子数来写。

Ti²⁺ (Z=22): [Ar] 3d² (not [Ar] 4s²)


8. Anomalous Configurations: Chromium and Copper | 异常排布:铬和铜

configurations due to the extra stability associated with half-filled and fully filled d sub-shells. The expected configuration for Cr would be [Ar] 4s² 3d⁴, but the actual configuration is [Ar] 3d⁵ 4s¹. For Cu, the expected [Ar] 4s² 3d⁹ becomes [Ar] 3d¹⁰ 4s¹. In both cases, one 4s electron is promoted to the 3d sub-shell to achieve a more stable arrangement. These anomalies are often tested; remember that similar behaviour is observed in molybdenum (Mo) and silver (Ag) in the next period.

铬 (Cr, Z=24) 和铜 (Cu, Z=29) 表现出不寻常的电子排布,这是由于半充满和全充满的 d 亚层具有额外的稳定性。Cr 的预期排布为 [Ar] 4s² 3d⁴,但实际排布是 [Ar] 3d⁵ 4s¹。Cu 的预期 [Ar] 4s² 3d⁹ 实际变为 [Ar] 3d¹⁰ 4s¹。在这两种情况下,都有一个 4s 电子跃迁到 3d 亚层,形成更稳定的结构。这些异常是常考的内容;要记住下一周期的钼 (Mo) 和银 (Ag) 也会有类似行为。


9. Electronic Configurations and the Periodic Table | 电子排布与周期表

The periodic table is divided into s, p, d, and f blocks based on which sub-shell is being filled. The s-block includes Groups 1 and 2 (and helium); the p-block contains Groups 13 to 18; the d-block comprises the transition metals (Groups 3–12); and the f-block contains the lanthanides and actinides. The period number equals the highest principal quantum number for s and p block elements, while for d block elements it is n−1 for the d sub-shell. Understanding these relationships makes it easy to deduce the electronic configuration of an element from its position in the table.

周期表根据正在填充的亚层分为 s 区、p 区、d 区和 f 区。s 区包括第 1 族和第 2 族(以及氦);p 区包含第 13 至 18 族;d 区由过渡金属(第 3–12 族)组成;f 区则包含镧系和锕系元素。周期数等于 s 区和 p 区元素的最高主量子数,而对于 d 区元素,d 亚层的 n 值比周期数小 1。理解这些关系就能轻松地从元素在表中的位置推断其电子排布。

Example: Element in Period 4, Group 6 → [Ar] 4s² 3d⁴ (expected, but for Cr it’s anomalous)


10. Ionisation Energies and Electronic Configurations | 电离能与电子排布

es that an electron is being removed from a shell closer to the nucleus (lower principal quantum number) or from a stable fully-filled or half-filled sub-shell. For example, magnesium (1s² 2s² 2p⁶ 3s²) shows a steep increase between the second and third ionisation energies, confirming the removal of an electron from the 2p sub-shell after the 3s electrons are gone. Dips between Group 2 and Group 13 (e.g., Be → B) arise because the p electron is easier to remove than the s electron in the same shell. The drop from Group 15 to Group 16 (N → O) is due to electron pairing in the p orbital, causing repulsion and making the electron easier to remove. Knowledge of configurations explains these trends perfectly.

逐级电离能为电子排布提供了有力的实验证据。电离能的巨大跃升表明电子正从一个更靠近原子核的能层(较低主量子数)或从稳定的全满/半满亚层中被移除。例如,镁 (1s² 2s² 2p⁶ 3s²) 的第二和第三电离能之间出现突增,证实在 3s 电子失去后,下一个电子来自 2p 亚层。第二族与第十三族之间(如 Be → B)的电离能下降,是因为同一能层中 p 电子比 s 电子更容易失去。第十五族到第十六族(N → O)的电离能下降,则是由于 p 轨道中电子配对引起的排斥力使电子更容易移除。掌握电子排布能完美解释这些变化趋势。


11. Summary and Key Points | 总结与要点


12. Practice Questions | 练习题

Try these questions to test your understanding:

试着做以下题目来检验你的理解:

  1. Write the full electronic configuration of a manganese atom (Z=25) and its Mn²⁺ ion. 写出锰原子 (Z=25) 及其 Mn²⁺ 离子的完整电子排布。
  2. Explain why the first ionisation energy of oxygen is lower than that of nitrogen. 解释为什么氧的第一电离能比氮的低。
  3. State the anomalous configuration of chromium and explain why it occurs. 说出铬的异常电子排布并解释其原因。
  4. Use the shorthand notation to write the electronic configuration of selenium (Se, Z=34). 用简写表示法写出硒 (Se, Z=34) 的电子排布。

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