← 返回资讯屏轩教育 · 行业资讯

KS3 WJEC Further Mathematics: Interdisciplinary Problem-Solving Training | KS3 WJEC 进阶数学:跨学科综合题型训练

2026-07-26 20:37 · 本文部分内容由AI辅助创作

📚 KS3 WJEC Further Mathematics: Interdisciplinary Problem-Solving Training | KS3 WJEC 进阶数学:跨学科综合题型训练

Welcome to this revision guide on interdisciplinary problem-solving for KS3 WJEC Further Mathematics. In the real world, mathematics does not exist in isolation; it is deeply connected with science, geography, finance, sports, and art. This article will train you to apply mathematical concepts such as ratio, proportion, algebra, geometry, and statistics across different contexts. By mastering these cross-curricular skills, you will be better prepared for both assessments and real-life challenges.

欢迎阅读这篇针对KS3 WJEC进阶数学的跨学科解题复习指南。在现实世界中,数学不是孤立存在的;它与科学、地理、金融、体育和艺术紧密相连。本文将训练你如何在不同情境中运用比与比例、代数、几何和统计等数学概念。通过掌握这些跨学科技能,你将更好地应对评估和现实生活的挑战。


1. Rate and Unit Conversion in Science | 科学中的速率与单位换算

density is a key skill. Density (ρ) is defined as mass per unit volume: ρ = mass ÷ volume.

在科学中,计算密度是一项关键技能。密度(ρ)定义为单位体积的质量:ρ = 质量 ÷ 体积。

When mass is given in grams and volume in cm³, density is in g/cm³. To convert g/cm³ to kg/m³, multiply by 1000.

当质量以克为单位,体积以立方厘米为单位时,密度单位为克每立方厘米(g/cm³)。要将g/cm³转换为kg/m³,需要乘以1000。

ume of 50 cm³. Its density is 200 ÷ 50 = 4 g/cm³. In kg/m³, this is 4 × 1000 = 4000 kg/m³.

例如,一块金属的质量为200克,体积为50立方厘米。其密度为200 ÷ 50 = 4 g/cm³。转换为kg/m³,即4 × 1000 = 4000 kg/m³。

000/1000 = 1000. Similar logic helps convert speed from m/s to km/h by multiplying by 3.6.

这种换算利用了单位间的关联:1 g/cm³ = 1000 kg/m³,因为1千克=1000克,1立方米=1,000,000立方厘米,所以比率是1,000,000/1000 = 1000。类似的逻辑可将速度从m/s转换为km/h,乘以3.6。


2. Scale Drawings and Map Reading in Geography | 地理中的比例尺绘图与地图阅读

Maps use scale ratios to represent real distances. A scale of 1:25,000 means 1 cm on the map represents 25,000 cm in reality, which is 250 metres.

地图使用比例尺来表示实际距离。比例尺1:25,000表示地图上的1厘米代表实际的25,000厘米,即250米。

h is 4.5 cm long on the map, the real distance is 4.5 × 25,000 cm = 112,500 cm = 1.125 km.

如果地图上一条小路长4.5厘米,实际距离为4.5 × 25,000厘米 = 112,500厘米 = 1.125千米。

rea of 2 cm² on a 1:10,000 map represents 2 × (10,000)² cm² = 200,000,000 cm² = 20,000 m².

当从地图比例尺计算面积时,必须将比例因子平方。例如,在1:10,000的地图上,公园面积为2平方厘米,代表实际面积2 × (10,000)²平方厘米 = 200,000,000平方厘米 = 20,000平方米。

Understanding scale is also useful for interpreting floor plans and architectural drawings.

理解比例尺对于解读楼层平面图和建筑图纸也很有用。


3. Simple Interest and Budgeting in Finance | 金融中的单利息与预算规划

re P is the principal, R is the annual interest rate as a decimal, and T is time in years.

在个人理财中,单利通过公式 I = P × R × T 计算,其中P为本金,R为年利率(用小数表示),T为时间(年)。

If you save £500 at 3% per annum for 4 years, the interest earned is I = 500 × 0.03 × 4 = £60. The total amount becomes £560.

如果你以3%的年利率存入£500,期限4年,获得的利息为 I = 500 × 0.03 × 4 = £60。总额为£560。

Budgeting also uses addition, subtraction, and percentages. A student earns £20 per week and spends 15% on snacks, 40% on savings, and the rest on entertainment.

预算也涉及加减法和百分比。一名学生每周挣£20,15%用于零食,40%储存,剩余用于娱乐。

Snack cost: £20 × 0.15 = £3. Savings: £20 × 0.40 = £8. Entertainment: £20 - £3 - £8 = £9.

零食花费:£20 × 0.15 = £3。储蓄:£20 × 0.40 = £8。娱乐:£20 - £3 - £8 = £9。


广告 / Sponsored

4. Speed, Distance, Time in Physical Education | 体育与物理中的速度、距离和时间问题

nd time is fundamental in both physics and sports. The formula is speed = distance ÷ time.

速度、距离和时间的关系在物理和体育中都是基础。公式为 速度 = 距离 ÷ 时间。

A runner completes a 400 m lap in 50 seconds. Her average speed is 400 ÷ 50 = 8 m/s.

一名跑步者用50秒完成一圈400米。她的平均速度是400 ÷ 50 = 8 米/秒。

ge the formula to find distance or time: distance = speed × time; time = distance ÷ speed.

我们可以对公式进行变形来求距离或时间:距离 = 速度 × 时间;时间 = 距离 ÷ 速度。

els at a constant speed of 12 m/s for 25 seconds, the distance covered is 12 × 25 = 300 m.

如果一名自行车手以12 m/s的恒定速度骑行25秒,所覆盖的距离是12 × 25 = 300 米。


5. Ratio and Proportion in Cooking Recipes | 烹饪配方中的比与比例

Recipes often require scaling ingredients using ratio and proportion. If a recipe for 4 people needs 200 g of flour, how much flour is needed for 10 people?

食谱通常需要使用比和比例来调整食材分量。如果一份4人份的食谱需要200克面粉,那么10人份需要多少面粉?

The scaling factor is 10 ÷ 4 = 2.5. So flour needed = 200 × 2.5 = 500 g.

比例系数为10 ÷ 4 = 2.5。因此所需面粉 = 200 × 2.5 = 500克。

amount for 1 person first. For 1 person, 200 ÷ 4 = 50 g, then multiply by 10 to get 500 g.

你也可以使用归一法:先求出一人份的量。一人份为200 ÷ 4 = 50克,再乘以10得到500克。

ent and sand in a 1:3 ratio. If you have 2.5 kg of cement, sand needed = 2.5 × 3 = 7.5 kg.

在混合材料时也使用比,例如水泥和沙子按1:3的比例。如果有2.5千克水泥,需要沙子 = 2.5 × 3 = 7.5千克。


6. Interpreting Graphs in Biology | 生物学中的图表解读

In biology, line graphs show how a variable changes over time. Interpreting the slope of a graph is an important mathematical skill.

在生物学中,折线图展示一个变量如何随时间变化。解读图表斜率是一项重要的数学技能。

A steep positive slope means a rapid increase. If a bacterial colony's population (y-axis) is plotted against time (x-axis), the gradient indicates the growth rate.

斜率陡峭为正表示快速增长。如果绘制细菌菌落数量(y轴)随时间(x轴)变化的图,其梯度表示生长速率。

ours (3500 bacteria), growth rate = (3500-500) ÷ (6-2) = 3000 ÷ 4 = 750 bacteria per hour.

计算两点间的平均生长速率,使用:速率 = (数量变化) ÷ (时间变化)。从2小时(500个细菌)到6小时(3500个细菌),生长速率 = (3500-500) ÷ (6-2) = 3000 ÷ 4 = 每小时750个细菌。

Understanding graph shapes helps predict trends, like the plateau phase where growth slows or the exponential phase when numbers double rapidly.

理解图形形状有助于预测趋势,比如增长放缓的平台期,或数量快速翻倍的指数期。


7. Probability and Data in Sports Statistics | 体育统计中的概率与数据

f 0.8, the probability of scoring two in a row is 0.8 × 0.8 = 0.64, assuming independence.

体育分析师使用概率来预测结果。如果一位篮球运动员的罚球命中率为0.8,假设独立,那么连续罚中两球的概率是0.8 × 0.8 = 0.64。

Data sets from sports are also analysed using mean, median, mode, and range. A cricketer's

Published by TutorHao | KS3 进阶数学 Revision Series | aleveler.com

广告 / Sponsored
2026年秋初中实验班提优训练789年级上下册语文数学英语人教苏教北师大译林版 初中七八九教材同步随堂作业本强化习题练…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥19.9

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao