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IB AQA Chemistry: Atomic Structure Key Concepts | IB AQA化学:原子结构考点精讲

2026-07-13 17:51 · 本文部分内容由AI辅助创作

📚 IB AQA Chemistry: Atomic Structure Key Concepts | IB AQA化学:原子结构考点精讲

Understanding atomic structure is the bedrock of chemistry, linking the microscopic world of subatomic particles to macroscopic properties and periodic trends. For IB and AQA specifications, you need to master the composition of atoms, isotopic variations, electron arrangement, and how these relate to ionisation energies.

理解原子结构是化学的基石,它将亚原子粒子的微观世界与宏观性质及周期趋势联系起来。对于IB和AQA考纲,你需要掌握原子的组成、同位素变化、电子排布,以及它们如何与电离能相关联。

1. Subatomic Particles: Protons, Neutrons, Electrons | 基本粒子:质子、中子、电子

An atom consists of a dense, positively charged nucleus surrounded by a cloud of negatively charged electrons. The nucleus contains protons and neutrons, collectively called nucleons.

原子由一个致密的、带正电的原子核和被带负电的电子云包围组成。原子核包含质子和中子,统称为核子。

Protons have a relative mass of 1 and a charge of +1; neutrons have a relative mass of 1 and a charge of 0; electrons have a relative mass of 1/1836 (negligible) and a charge of –1.

质子的相对质量为1,电荷为+1;中子的相对质量为1,电荷为0;电子的相对质量约为1/1836(可忽略),电荷为–1。


2. Atomic Number (Z) and Mass Number (A) | 原子序数 (Z) 与质量数 (A)

The atomic number Z is the number of protons in the nucleus, defining the element. For a neutral atom, the number of electrons equals Z.

原子序数Z是原子核内质子的数目,决定了元素种类。对于中性原子,电子数等于Z。

The mass number A is the total number of protons and neutrons. It is always an integer and is written as a superscript before the element symbol, e.g. ¹²₆C for carbon-12.

质量数A是质子与中子总数。它恒为整数,写在元素符号的左上角,例如 ¹²₆C 表示碳-12。


3. Isotopes: Definition and Notation | 同位素:定义与表示

Isotopes are atoms of the same element with the same atomic number Z but different mass numbers A, meaning they have different numbers of neutrons.

同位素是同种元素的原子,具有相同的原子序数Z但不同的质量数A,即它们的中子数不同。

For example, carbon has three naturally occurring isotopes: ¹²C, ¹³C, and ¹⁴C. They all contain 6 protons but have 6, 7, and 8 neutrons respectively.

例如,碳有三种天然同位素:¹²C、¹³C和¹⁴C。它们都含有6个质子,但中子数分别为6、7和8。


4. Relative Atomic Mass and Isotopic Abundance | 相对原子质量与同位素丰度

The relative atomic mass Aᵣ is the weighted average mass of an atom compared to 1/12th the mass of a carbon-12 atom. It takes into account the relative abundances of all isotopes.

相对原子质量Aᵣ是原子质量相对于碳-12原子质量的1/12的加权平均值,它考虑了所有同位素的相对丰度。

The formula is: Aᵣ = Σ (isotopic mass × % abundance) / 100. For chlorine, with ⁷⁵% ³⁵Cl (mass 35) and ²⁵% ³⁷Cl (mass 37), Aᵣ = (35 × 75 + 37 × 25) / 100 = 35.5.

计算公式为:Aᵣ = Σ (同位素质量 × 丰度百分比) / 100。对于氯,⁷⁵% ³⁵Cl(质量35)和 ²⁵% ³⁷Cl(质量37),Aᵣ = (35 × 75 + 37 × 25) / 100 = 35.5。


5. Mass Spectrometry: Determining Isotopic Composition | 质谱法:测定同位素组成

A mass spectrometer vaporises and ionises the sample, then separates ions by their mass-to-charge ratio (m/z). The resulting spectrum shows peaks corresponding to different isotopes.

质谱仪将样品气化并离子化,然后按质荷比(m/z)分离离子。所得的质谱图显示对应于不同同位素的峰。

The height of each peak is proportional to the relative abundance of that isotope. Aᵣ is calculated directly from these peaks.

每个峰的高度与该同位素的相对丰度成正比。Aᵣ可直接从这些峰计算得出。

The main stages are: vaporisation, ionisation (electron impact), acceleration, deflection in a magnetic field, and detection.

主要步骤为:气化、离子化(电子轰击)、加速、在磁场中偏转以及检测。


6. The Electron: Energy Levels and Shells | 电子:能级与电子层

lled with the principal quantum number n = 1, 2, 3... The energy increases as n increases.

电子占据原子核外分立的能级(电子层),以主量子数n = 1, 2, 3…标识。能量随n增大而升高。

lectrons in a shell is given by 2n². So n=1 holds 2, n=2 holds 8, n=3 holds 18, and so on.

每层最多可容纳的电子数为2n²。因此n=1层容纳2个,n=2层容纳8个,n=3层容纳18个,以此类推。


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7. Subshells and Orbitals (s, p, d) | 亚层与轨道 (s, p, d)

Each energy level n is split into sub-levels (subshells): s, p, d, and f. The number of sub-levels in a shell equals n.

每个能级n分为若干亚层:s、p、d和f。一个电子层中亚层的数目等于n。

An orbital is a region of space where there is a high probability of finding an electron. An s orbital is spherical; p orbitals are dumbbell-shaped and oriented along x, y, z axes. Each orbital can hold a maximum of 2 electrons with opposite spins.

轨道是空间中电子出现概率较高的区域。s轨道呈球形;p轨道呈哑铃形,沿x、y、z轴取向。每个轨道最多容纳2个自旋相反的电子。

The energy order of filling is: 1s < 2s < 2p < 3s < 3p < 4s < 3d ... This is crucial for writing electron configurations.

填充的能量顺序为:1s < 2s < 2p < 3s < 3p < 4s < 3d … 这对书写电子排布至关重要。


8. Electron Configurations: Rules and Examples | 电子排布:规则与示例

Electron configurations are written using notation such as 1s² 2s² 2p⁶. Three rules govern filling: Aufbau principle (fill lowest energy first), Pauli exclusion principle (each orbital holds max 2 electrons with opposite spin), and Hund's rule (electrons fill degenerate orbitals singly before pairing).

电子排布用诸如1s² 2s² 2p⁶的符号书写。填充遵循三大规则:构造原理(优先填充低能量轨道)、泡利不相容原理(每个轨道最多容纳2个自旋相反的电子)和洪特规则(电子先以相同自旋分占简并轨道,再配对)。

y with parallel spins. For oxygen (Z=8): 1s² 2s² 2p⁴, where one p orbital contains a pair.

对于氮(Z=7):1s² 2s² 2p³。三个p电子以相同自旋分占三个p轨道。对于氧(Z=8):1s² 2s² 2p⁴,其中一个p轨道含有一对电子。


9. First Ionisation Energy: Definition and Trends | 第一电离能:定义与趋势

s atoms to form one mole of gaseous ions with a single positive charge: X(g) → X⁺(g) + e⁻.

第一电离能是指从一摩尔气态原子中移除一摩尔电子,形成一摩尔带+1电荷的气态离子所需的能量:X(g) → X⁺(g) + e⁻。

Across a period, ionisation energy generally increases because nuclear charge increases while shielding remains similar, so outer electrons are held more tightly. Down a group, it decreases because atomic radius increases and shielding increases, making the outer electron easier to remove.

在同一周期中,电离能通常升高,因为核电荷增加而屏蔽效应相近,外层电子被束缚得更紧。在同一族中,电离能下降,因为原子半径增大且屏蔽增强,使外层电子更容易失去。


10. Successive Ionisation Energies and Shell Evidence | 逐级电离能与电子层证据

Successive ionisation energies increase as successive electrons are removed. A large jump in ionisation energy indicates that an electron is being removed from an inner shell, providing evidence for electron shells.

逐级电离能随电子逐一移除而升高。电离能出现大幅跃升表明电子从内层移除,这为电子层的存在提供了证据。

For magnesium (1s² 2s² 2p⁶ 3s²), the first two ionisation energies are relatively low (removing 3s electrons). There is a huge jump between the 2nd and 3rd ionisation energies because the 3rd electron comes from the 2p subshell, which is closer to the nucleus and experiences less shielding.

例如镁(1s² 2s² 2p⁶ 3s²),前两级电离能相对较低(移除3s电子)。第二与第三电离能之间出现大幅跃升,因为第三个电子来自2p亚层,离核更近且受到的屏蔽更少。


11. Linking Atomic Structure to Periodic Trends | 原子结构与周期趋势的联系

Atomic and ionic radii, electronegativity, and melting points are all rationalised through electron configuration and nuclear charge. The periodic table itself is a map of filling order: s-block, p-block, d-block.

原子半径、离子半径、电负性和熔点都可以通过电子排布与核电荷来解释。元素周期表本身就是填充顺序的映射:s区、p区、d区。

A deep understanding of atomic structure allows you to predict chemical behaviour and justify the anomalies, such as the slightly lower first ionisation energy of oxygen compared to nitrogen, due to electron–electron repulsion in the doubly occupied p orbital.

深入理解原子结构使你能够预测化学行为并解释反常现象,例如氧的第一电离能略低于氮,这是由于双占p轨道中电子-电子排斥造成的。


12. Key Definitions and Revision Summary | 核心定义与复习汇总

tice drawing electron configurations using box-and-arrow diagrams for elements up to Z=36.

确保你能定义:原子序数、质量数、同位素、相对原子质量、第一电离能、轨道、电子屏蔽。练习用箱式箭头图绘制Z=36以内元素的电子排布。

Use past paper questions to test your ability to interpret mass spectra, calculate Aᵣ from isotopic abundance, and explain ionisation energy trends using shell structure and shielding arguments.

通过历年真题检验你解读质谱图、根据同位素丰度计算Aᵣ、以及运用电子层结构与屏蔽效应解释电离能趋势的能力。

Published by TutorHao | Chemistry Revision Series | aleveler.com

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