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Mastering Second Order Differential Equations for OCR A-Level | OCR A-Level 二阶微分方程考点精讲

2026-07-13 14:07 · 本文部分内容由AI辅助创作

📚 Mastering Second Order Differential Equations for OCR A-Level | OCR A-Level 二阶微分方程考点精讲

A second-order differential equation lies at the heart of many physical and engineering problems, from the motion of a vibrating spring to the decay of an electric circuit. In OCR A-Level Mathematics (Further Pure), you are expected to solve linear second-order ordinary differential equations with constant coefficients, both homogeneous and non-homogeneous, and to apply initial or boundary conditions. This article distils the essential methods, common pitfalls, and exam-winning strategies into a clear, bilingual review.

二阶微分方程是许多物理和工程问题的核心,从弹簧振动到电路衰减。在 OCR A-Level 数学(Further Pure)中,你需要掌握求解常系数线性二阶常微分方程的方法,包括齐次和非齐次方程,并能运用初始条件或边界条件。本文将以清晰的中英双语形式,提炼核心解法、常见错误与应试策略。


1. General Form and Key Terminology | 一般形式与核心术语

f(x) = 0, the equation is homogeneous; otherwise it is non-homogeneous. The solution y = yc + yp consists of the complementary function yc (solving the homogeneous equation) and a particular integral yp (any function satisfying the full equation).

常系数线性二阶常微分方程的形式为:a · d²y/dx² + b · dy/dx + c · y = f(x)。其中 a, b, c 为常数(a ≠ 0),f(x) 称为强制函数。当 f(x) = 0 时,方程为齐次方程,否则为非齐次方程。解的结构为 y = yc + yp,其中 yc 是余函数(齐次方程的通解),yp 是特解(满足非齐次方程的任意函数)。


2. The Homogeneous Equation and Auxiliary Equation | 齐次方程与辅助方程

To find yc, set f(x) = 0 and assume a trial solution y = emx. Differentiating gives dy/dx = m emx and d²y/dx² = m² emx s m₁ and m₂ of this quadratic completely determine the form of the complementary function.

求 yc 时,令 f(x) = 0,并设试探解 y = emx。求导得 dy/dx = m emx,d²y/dx² = m² emx。代入齐次方程即得辅助方程:a m² + b m + c = 0。该二次方程的根 m₁ 和 m₂ 完全决定了余函数的形式。


3. Distinct Real Roots | 相异实根

When the discriminant b² - 4ac > 0, the auxiliary equation has two distinct real roots m₁ and m₂. The complementary function is yc = A em₁ x + B em₂ x, where A and B are arbitrary constants. This is the simplest case and appears frequently in exam questions involving exponential growth or decay dynamics.

当判别式 b² - 4ac > 0 时,辅助方程有两个相异实根 m₁ 和 m₂。余函数为 yc = A em₁ x + B em₂ x,其中 A 与 B 为任意常数。这是最简单的情形,常见于涉及指数增长或衰减动态的考题。


4. Repeated Real Root | 重实根

auxiliary equation has one repeated root m = -b/(2a). The complementary function is now yc = (A + B x) em x. The extra factor of x is essential to capture the full set of independent solutions; forgetting this is one of the most frequent errors in exams.

若 b² - 4ac = 0,辅助方程有一个重根 m = -b/(2a)。此时余函数为 yc = (A + B x) em x。额外的 x 因子是获得完整独立解组的关键;考试中忘记乘上 x 是最常见的错误之一。


5. Complex Conjugate Roots | 共轭复根

When b² - 4ac < 0, the roots are complex conjugates m = α ± iβ, where α = -b/(2a) and β = √4ac - b²/(2a). The complementary function takes the oscillatory form yc = eα x (A cos β x + B sin β x). This case models damped vibrations, and the constants A and B are typically determined by initial conditions such as initial displacement and velocity.

当 b² - 4ac < 0 时,根为一对共轭复数 m = α ± iβ,其中 α = -b/(2a),β = √4ac - b²/(2a)。余函数呈振荡形式:yc = eα x (A cos β x + B sin β x)。这类情况用于建模阻尼振动,常数 A、B 通常由初始位移和初始速度等条件确定。


6. Non-Homogeneous Equations: Choosing a Particular Integral | 非齐次方程:特解的选定

For a non-homogeneous equation a d²y/dx² + b dy/dx + c y = f(x), the particular integral yp is found by the method of undetermined coefficients. The first step is to guess a form for yp based on the type of f(x). The guess must not duplicate any term already present in yc by x (or x²) until all terms are distinct. Always write the full general solution as y = yc + yp before substituting conditions.

对于非齐次方程 a d²y/dx² + b dy/dx + c y = f(x),特解 yp 通过待定系数法求得。首先根据 f(x) 的类型猜测一个 yp 的形式。该形式不得与 yc 中的任何项重复;若出现重复,则需将猜测项乘以 x(或 x²)直至所有项互异。在代入条件求常数前,务必写出完整的通解 y = yc + yp。


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7. Standard Guesses for f(x) | f(x) 的标准猜测形式

The table below summarises the standard trial functions for common forcing terms. Always use the full polynomial even if some terms are missing; for trigonometric functions, include both sine and cosine even when only one appears in f(x). Remember: if the standard guess overlaps with yc, multiply by x and re-check.

下表总结了常见强制项的标准试探函数。即使多项式缺少某些项,也应使用完整的同次多项式;对于三角函数,即使 f(x) 中只出现正弦或余弦,试探解也需同时包含正弦和余弦项。切记:若标准猜测与 yc 重叠,则乘以 x 后重新检验。

f(x)Trial yp
constant kC
polynomial Pₙ(x) of degree nAₙ xⁿ + Aₙ₋₁ xⁿ⁻¹ + ... + A₀
k ep xC ep x (unless p is a root)
k sin ωx or k cos ωxC cos ωx + D sin ωx
k x ep x etc.(C x + D) ep x if p is a repeated root of auxiliary eqn

8. Modifying Guesses When Overlap Occurs | 重叠时的猜测修正

If the unmodified trial yp shares a term with yc, multiply the entire trial yp by x (or by x² if the overlap persists). For instance, if yc contains e2x and f(x) = 5 e2x, the initial guess yp = C e2x is invalid. Multiply by x to get yp = C x e2x. If 2 is a repeated root, use yp = C x² e2x. This rule avoids missing a valid particular integral.

若未经修正的试探 yp 与 yc 有共同项,则将整个试探 yp 乘以 x(若仍重叠则进一步乘以 x²)。例如 yc 含有 e2x 而 f(x) = 5 e2x,初始猜测 yp = C e2x 无效,需乘以 x 得 yp = C x e2x。若 2 为重根,则采用 yp = C x² e2x。此规则可避免遗漏有效的特解。


9. Substituting and Solving for Coefficients | 代入并求解系数

Once the trial yp is chosen, compute its first and second derivatives, substitute them into the original non-homogeneous ODE, and equate coefficients of like terms. This yields a system of linear equations for the unknown constants. Solve them carefully; algebraic slips are common. After finding yp, write y = yc + yp and proceed to impose any given conditions.

选定试探 yp 后,求出它的一阶和二阶导数,代入原非齐次常微分方程,并比较同类项系数,从而得到关于未知常数的线性方程组。请仔细求解,代数失误是常见丢分点。求出 yp 后,写出 y = yc + yp,然后代入所给条件。


10. Using Initial or Boundary Conditions | 运用初始条件或边界条件

olution and its derivative to obtain two equations in the arbitrary constants (A, B from yc). Solve simultaneously to find the unique particular solution. Always differentiate y before plugging in conditions — and double-check the arithmetic.

OCR 考题通常会给出两个条件,例如当 x = 0 时 y = 1 且 dy/dx = 0。将 x = 0 代入通解及其导数,得到关于任意常数(yc 中的 A、B)的两个方程,联立求解即得唯一特解。务必先将 y 求导再代入条件,并核验每一步计算。


11. Applications: SHM and Damped Oscillations | 应用:简谐运动与阻尼振动

bes a damped harmonic oscillator. For underdamping (complex roots), the displacement x = eα t (A cos β t + B sin β t) exhibits decaying oscillations — the real part α controls the envelope. These models appear regularly in mechanics and circuit questions.

一个经典应用是运动方程 m d²x/dt² + λ dx/dt + k x = F(t)。当无外力时,齐次方程描述阻尼谐振子。在欠阻尼(复根)情形下,位移 x = eα t (A cos β t + B sin β t) 呈现衰减振荡,实部 α 控制包络线。这类模型频繁出现在力学与电路考题中。


12. Exam Strategy and Common Pitfalls | 应试策略与常见陷阱

Always begin by identifying a, b, c and the form of f(x). Write the auxiliary equation clearly and state its discriminant to avoid sign errors. When guessing yp, check for overlap with yc before solving. Keep constants A and B until the very end; premature substitution loses generality. Finally, leave your final answer in the requested form, and under- line the key steps to gain method marks.

解题时,首先识别 a、b、c 及 f(x) 的形式。清晰写出辅助方程并注明显判别式以防符号错误。猜测 yp 时,务必先检验是否与 yc 重叠。将常数 A、B 保留到最后,过早代入会丧失一般性。最后按照题目要求的形式给出答案,并突出关键步骤以获得过程分。

Published by TutorHao | Further Pure Mathematics Revision Series | aleveler.com

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