CCEA Psychology Unit Test Mock Paper Analysis | CCEA 心理学单元测试模拟卷解析

📚 CCEA Psychology Unit Test Mock Paper Analysis | CCEA 心理学单元测试模拟卷解析

This article provides a detailed breakdown of a CCEA-style psychology mock paper, covering key topics from memory and attachment to social influence and research methods. Each question is presented with a model answer and examiner-style commentary to help you grasp what gains marks and how to avoid common pitfalls. By working through these analyses, you will strengthen your understanding of both core content and essential application skills.

本文对一套CCEA风格的心理模拟试卷进行了逐题精讲，涵盖记忆、依恋、社会影响与研究方法等重点主题。每一题都配有标准答案和评分导向的解析，帮助你理解得分要点，避开常见失分陷阱。通过这些分析，你将进一步巩固核心知识，并提升应用与评鉴能力。

1. Q1: Multi-Store Model of Memory | 第1题：记忆的多存储模型

Question: Outline two components of the multi-store model of memory. (4 marks)

题目：简述记忆多存储模型的两个组成部分。（4分）

tion). It has a large capacity but only a fraction of data is attended to and passed on. The other component is short-term memory (STM), where attended information is held for approximately 18– s rehearsed. STM has a limited capacity of around 7±2 items and mainly codes acoustically.

一个组成部分是感觉登记器，它接收来自感官的信息并保持极为短暂的时长（视觉信息不足半秒）。其容量较大，但只有被注意到的信息才会进入下一阶段。另一个组成部分是短时记忆（STM），经注意的信息在此保持约18–30秒，除非得到复述。短时记忆的容量有限，大约为7±2个组块，并且主要以听觉形式编码。

It is important to describe function, capacity, duration, or coding to secure full marks. Many students lose marks by only naming the stores without elaboration. Also be precise: 'sensory memory' alone is insufficient; highlight its fleeting duration and modality-specific nature.

得满分的关键在于描述功能、容量、时长或编码，而不是仅仅写出名称。很多学生因为缺少展开说明而丢分。同时请做到术语准确：只写“感觉记忆”是不够的，还需点出其极短的保持时间和特定感官通道的性质。

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2. Q2: Reconstructive Memory & Eyewitness Testimony | 第2题：重构记忆与目击者证言

Question: Explain one finding from Loftus & Palmer's (1974) study and its implication for eyewitness testimony. (4 marks)

题目：解释Loftus与Palmer（1974）研究的一项发现，并说明其对目击者证言的启示。（4分）

One key finding was that the verb used in the critical question influenced speed estimates: participants who heard 'smashed' estimated a higher speed (mean 40.8 mph) than those who heard 'contacted' (mean 31.8 mph). This suggests that post-event information can distort memory, as the leading question altered participants' recollection of the car accident. The implication is that eyewitness testimony is malleable and may not be reliable, especially when witnesses are exposed to suggestive questioning by police or lawyers.

一项关键发现是问题中的动词显著影响了速度估计：听到“smashed”（碰撞）的被试给出的速度估计均值（40.8 mph）高于听到“contacted”（接触）的被试（31.8 mph）。这表明事后信息可以扭曲记忆，因为引导性问题改变了被试对车祸的记忆。其启示在于，目击者证词是可塑的，不够可靠，特别是当证人接触到警方或律师的暗示性提问时。

Avoid simply stating that 'memory is reconstructive' without tying it to the verb effect. Credit is given for making a clear link between the distortion of memory and real-world consequences, such as wrongful convictions. Use precise data to demonstrate knowledge of the study.

切忌仅说“记忆是重构的”却不联系动词效应。得分点在于清晰建立记忆扭曲与现实后果（例如冤假错案）之间的关联。可使用准确的数据体现对研究的掌握。

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3. Q3: Attachment Types & the Strange Situation | 第3题：依恋类型与陌生情境

Question: Describe how the three attachment types are identified in Ainsworth's Strange Situation. (6 marks)

题目：描述Ainsworth陌生情境实验中如何识别三种依恋类型。（6分）

Type B (secure attachment) is identified when the infant uses the caregiver as a safe base, shows distress upon separation, and is easily comforted upon reunion. The infant actively seeks proximity and can return to exploration once reassured.

B型（安全型依恋）表现为婴儿将照护者作为安全基地，分离时表现痛苦，重聚时容易被安抚。婴儿会主动寻求亲近，并在获得安慰后恢复探索。

Type A (insecure-avoidant) is characterised by high exploration regardless of the caregiver's presence, little distress during separation, and avoidance of contact on reunion. These infants tend to treat the caregiver and stranger similarly.

A型（不安全-回避型）的特征是无论照护者在场与否都积极探索，分离时痛苦程度低，重聚时回避接触。这类婴儿对待照护者和陌生人的方式较为相似。

Type C (insecure-resistant) is marked by intense distress upon separation, difficulty settling upon reunion, and a mix of clingy and resistant behaviour. The infant may angrily resist the caregiver's attempts to comfort.

C型（不安全-反抗型）表现为分离时极为痛苦，重聚后难以平静，同时呈现黏人与抗拒的矛盾行为。婴儿可能会愤怒地拒绝照护者的安抚。

Examiners look for specific behaviours – proximity seeking, exploration, separation anxiety, and reunion behaviour – linked to the type label. Students often confuse avoidant and resistant reactions at reunion; focus on the distinctive response when the caregiver returns.

评分关注具体行为指标——寻求亲近、探索、分离焦虑与重聚行为——并与类型标签对应。学生常将回避型与反抗型的重聚反应混淆；考前需重点区分照护者返回时两类婴儿截然不同的表现。

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4. Q4: Variables in Experiments | 第4题：实验中的变量

Question: A researcher investigates whether drinking caffeine affects reaction time. (a) Identify the IV and DV. (2 marks) (b) Explain why it is important to operationalise variables. (4 marks)

题目：一位研究者考察饮用咖啡因是否影响反应时。（a）指出自变量与因变量。（2分）（b）解释对变量进行操作化定义为何重要。（4分）

(a) The independent variable (IV) is the presence or amount of caffeine consumed, and the dependent variable (DV) is the reaction time measured in milliseconds.

（a）自变量（IV）是是否摄入或摄入多少咖啡因，因变量（DV）是以毫秒计的反应时。

(b) Operationalising variables means defining them in measurable terms. For the IV, the researcher might specify exactly 200 mg of caffeine in a standardised drink; for the DV, a computer-based response task yielding a precise reaction time in ms. This is important because it allows the study to be replicated, increases reliability, and ensures that another researcher can objectively check whether the IV was manipulated and the DV consistently measured. Without operationalisation, the experiment lacks clarity and may produce ambiguous results.

（b）操作化指用可测量的方式定义变量。对自变量，研究者可明确规定标准饮料中含200 mg咖啡因；对因变量，可采用计算机按键任务获得以毫秒为单位的精确反应时。操作化至关重要——它使研究可以被复制，提高信度，并确保其他研究者能够客观检验自变量是否被操控、因变量是否被一致测量。缺乏操作化，实验便不够清晰，可能得出模棱两可的结果。

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5. Q5: Data Analysis – Mean and Bar Chart | 第5题：数据分析——均值与条形图

Question: A study compared recall of words in quiet and noisy conditions. The numbers of words recalled by five participants in each condition were: Quiet: 14, 12, 15, 13, 11; Noise: 9, 8, 10, 7, 6. (a) Calculate the mean for each condition. (4 marks) (b) Sketch a fully labelled bar chart to display the mean scores. (4 marks)

题目：一项研究比较安静与噪音条件下的单词回忆量。安静组五名被试的回忆数量：14, 12, 15, 13, 11；噪音组：9, 8, 10, 7, 6。（a）计算每组均值。（4分）（b）绘制完整标注的平均值条形图。（4分）

(a) The mean is calculated by summing the scores and dividing by the number of participants. For the quiet condition:

mean = (14 + 12 + 15 + 13 + 11) ÷ 5 = 65 ÷ 5 = 13

For the noise condition:

mean = (9 + 8 + 10 + 7 + 6) ÷ 5 = 40 ÷ 5 = 8

(b) The bar chart must include: a title ('Mean Word Recall in Quiet vs. Noise'); labelled axes with the x-axis displaying the two conditions and the y-axis labelled 'Mean Number of Words Recalled'; bars rising to 13 and 8 respectively with the scale starting at zero; and consistent spacing. Deductions occur if bars touch or if absent labels.

（b）条形图必须包含：标题（“安静与噪音条件下的平均单词回忆量”）；标注清晰的坐标轴，X轴显示两个条件，Y轴标为“平均单词回忆数”；条形高度分别为13与8，纵轴需从零开始；条间距一致。若条形接触或缺失任何标注，均会扣分。

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6. Q6: Asch's Conformity Study – Variations | 第6题：阿希从众研究——变量变式

Question: Explain how the number of confederates affects conformity, with reference to Asch's findings. (6 marks)

题目：结合阿希的研究发现，解释同伴人数如何影响从众行为。（6分）

Asch found that conformity increased as the size of the majority group increased, but only up to a point. With one confederate, conformity was negligible; with two confederates, the real participant conformed on about 12.8% of critical trials; with three confederates, conformity rose to around 32%. Beyond three confederates, additional members produced no substantial increase, showing a curvilinear relationship. This suggests that the perception of group unanimity is more crucial than sheer group size.

阿希发现，随着多数派人数增加，从众行为会上升，但存在上限。只有一名假被试时几乎无从众；两名假被试时，真被试在关键试次中的从众率约12.8%；三名假被试时，从众率升至约32%。超过三人后，新增成员并未带来显著提升，呈现曲线关系。这表明群体一致性的感知比纯粹的人数规模更为关键。

Candidates should avoid general statements such as 'more people equals more conformity' without numerical support or qualification. Explicitly describe the levelling-off effect and mention that Asch used a line-judgement task with 18 trials, 12 of which were critical.

答题时切忌笼统地说“人越多从众越高”而不提供数据支撑或限定条件。务必描述拐点效应，并提及阿希采用的是线条判断任务，共18试次，其中12个为关键试次。

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7. Q7: Piaget's Conservation Task | 第7题：皮亚杰守恒任务

Question: Describe one Piagetian conservation task and explain what it demonstrates about pre-operational thinking. (6 marks)

题目：描述皮亚杰的一项守恒任务，并说明它揭示了前运算阶段思维的何种特点。（6分）

In the classic liquid conservation task, a child is shown two identical beakers with equal amounts of coloured water. Once the child agrees the amounts are equal, the researcher pours water from one beaker into a taller, narrower glass. A child in the pre-operational stage (roughly 2–7 years) typically states that the taller glass now contains more water, focusing only on the increased height (centration) and failing to consider the reduced width. This demonstrates an inability to perform reversible mental operations, and the child’s thinking is dominated by perceptual appearances rather than logical constancy.

在经典的液体守恒任务中，首先向儿童展示两个相同的烧杯装有等量有色水。待儿童确认水量相等后，研究者将其中一个烧杯的水倒入一个更高、更细的玻璃杯。处于前运算阶段（约2–7岁）的儿童通常声称高玻璃杯中的水更多，他们只关注到水位高度的增加（中心化），而忽略了杯身宽度的减小。这表明该阶段儿童尚无法进行可逆的心理操作，思维受到知觉外观主导，而非逻辑恒常性。

To reach the top marks, name the stage, explain centration and irreversibility, and link these concepts directly to the child's error. Do not forget to state that the pre-operational child has not yet developed conservation – the understanding that quantity remains invariant despite changes in shape.

要获得高分，需点出认知阶段，解释中心化和不可逆性，并直接将这些概念与儿童的错误建立联系。同时不要忘记指出前运算阶段儿童尚未形成守恒概念——即理解数量不因形状改变而变化的逻辑能力。

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8. Q8: Biological Explanation of Depression | 第8题：抑郁症的生物学解释

Question: Outline one biological explanation for depression. (4 marks)

题目：简述抑郁症的一种生物学解释。（4分）

The monoamine hypothesis proposes that depression is linked to a deficit in the activity of neurotransmitters such as serotonin, noradrenaline, and dopamine. For example, lower levels of serotonin are associated with low mood, poor sleep, and appetite disturbances. Drugs like SSRIs (selective serotonin reuptake inhibitors) work by blocking the reuptake of serotonin in the synapse, thereby increasing its availability and alleviating depressive symptoms. This treatment efficacy supports the neurochemical explanation.

单胺假说认为抑郁症与血清素、去甲肾上腺素和多巴胺等神经递质的活性不足有关。例如，血清素水平偏低与情绪低落、睡眠紊乱和食欲减退相关联。选择性血清素再摄取抑制剂（SSRIs）这类药物通过阻断突触中血清素的再摄取，提高其可用度，从而缓解抑郁症状。这种治疗效果为神经化学解释提供了支持。

Be specific – merely referring to 'chemical imbalance' will not gain full marks. Mention at least one named neurotransmitter and, ideally, connect the explanation to a known treatment. Genetic explanations (e.g., family or twin studies) can also be credited, but candidates should avoid mixing unrelated biological arguments into one superficial answer.

答题必须具体——仅提及“化学物质失衡”无法获得满分。至少点出某种神经递质名称，并尽可能将该解释与已知疗法相联系。遗传解释（例如家族或双生子研究）同样可用，但应避免将不相关的生物论点混在一起，写出表面化的答案。

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9. Q9: Stress and the Fight-or-Flight Response | 第9题：应激与战斗或逃跑反应

Question: Describe the physiological responses involved in the 'fight-or-flight' response. (6 marks)

题目：描述“战斗或逃跑”反应涉及的生理变化。（6分）

When a person perceives a threat, the hypothalamus activates the sympathetic branch of the autonomic nervous system. This triggers the adrenal medulla to release adrenaline and noradrenaline into the bloodstream. As a result, heart rate and blood pressure increase to transport oxygen to muscles, breathing rate accelerates, pupils dilate to improve vision, and non-essential functions such as digestion are inhibited. The liver also converts glycogen to glucose for immediate energy. Collectively, these responses prepare the body to confront the threat (fight) or escape from it (flight).

当个体感知到威胁时，下丘脑激活自主神经系统的交感支，继而刺激肾上腺髓质向血液中释放肾上腺素和去甲肾上腺素。结果是心率和血压升高以便为肌肉输送氧气，呼吸加快，瞳孔放大以增进视力，而消化等非必需功能受到抑制。肝脏同时将糖原转化为葡萄糖以提供即时能量。这些反应共同使身体做好对抗威胁（战斗）或逃离威胁（逃跑）的准备。

fic bodily changes. Avoid listing responses without naming the systems and hormones involved. Also note that the parasympathetic branch later returns the body to homeostasis once the threat subsides.

满分答案需要呈现清晰的因果链条：应激源感知→下丘脑→自主神经系统激活→激素释放→具体的身体变化。切忌只罗列反应而不指出涉及的系统与激素名称。同时可补充说明当威胁解除后，副交感神经支会使机体恢复稳态。

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10. Q10: Research Methods – Interviews vs Questionnaires | 第10题：研究方法——访谈与问卷对比

Question: Discuss strengths and weaknesses of using questionnaires compared to interviews in psychological research. (6 marks)

题目：讨论心理学研究中使用问卷相比访谈的优势与劣势。（6分）

Method	Questionnaire	Interview
Strengths	Can reach a large, geographically dispersed sample; quick to administer and economical; closed questions produce quantitative data that is easy to analyse and compare; high replicability due to standardised format.	Allows rich, qualitative data; the interviewer can clarify misunderstandings and probe deeper; flexibility to adapt questions; may develop rapport, encouraging more honest or detailed responses.
Weaknesses	Risk of low response rates; questions may be misinterpreted with no opportunity to clarify; closed questions limit the depth of data; social desirability bias may affect answers; no control over who completes it.	Time-consuming and costly per participant; interviewer effects (e.g., tone, appearance) may bias responses; less standardised, making reliability and comparison harder; small sample sizes may limit generalisability.

To earn the analysis marks, candidates must go beyond listing and provide a comparative discussion. For instance, questionnaires are suited for large-scale correlational studies on attitudes, whereas interviews are preferred when exploring sensitive topics where nuance is needed. Always frame a weakness in context: low response rate undermines the representativeness of questionnaire data, while interviewer bias threatens the validity of interview findings.

要拿到分析分值，考生不仅需罗列，还要进行比较性讨论。例如，问卷适合对态度进行大规模相关研究，而访谈更适合探索需要捕捉细微差别的高敏感话题。始终结合具体情境说明劣势：低回复率损害了问卷数据的代表性，而访谈者偏差威胁了访谈结果的有效性。

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