← 返回资讯屏轩教育 · 行业资讯

Year 12 WJEC Mathematics: Quick Reference Formula & Theorem Handbook | WJEC 数学公式定理速查手册

2026-07-22 01:47 · 本文部分内容由AI辅助创作

📚 Year 12 WJEC Mathematics: Quick Reference Formula & Theorem Handbook | WJEC 数学公式定理速查手册

This handbook compiles the essential formulas, identities, and theorems required for the Year 12 WJEC Mathematics specification. It serves as a quick revision aid covering Pure Mathematics, Statistics, and Mechanics. Use it alongside past papers and your class notes to reinforce your understanding.

本手册汇集了 Year 12 WJEC 数学考试所需的核心公式、恒等式和定理,涵盖纯数学、统计与力学,供快速复习使用。请结合历年真题与课堂笔记,查漏补缺,巩固理解。


1. Algebraic Fundamentals | 代数基础

The quadratic formula: For ax² + bx + c = 0, the solutions are given by x = (–b ± √b² – 4ac) / (2a).

二次公式:对于 ax² + bx + c = 0,解为 x = (–b ± √b² – 4ac) / (2a)。

The discriminant Δ = b² – ct real roots; if Δ = 0 there is one repeated real root; if Δ < 0 there are no real roots.

判别式 Δ = b² – 4ac 决定了根的性质:Δ > 0 时有两个不等实根;Δ = 0 时有一个重根;Δ < 0 时无实根。

Completing the square transforms x² + bx into (x + b/2)² – (b/2)². This is useful for solving quadratics and finding the vertex of a parabola.

配方法:x² + bx = (x + b/2)² – (b/2)²,常用于解二次方程和求抛物线的顶点。

Sum and product of roots: if α and β are the roots of ax² + bx + c = 0, then α + β = –b/a and αβ = c/a.

根的和与积:若 α 和 β 是 ax² + bx + c = 0 的根,则 α + β = –b/a,αβ = c/a。

Factor theorem: (x – f(x) if and only if f(p) = 0. The remainder theorem states that when f(x) is divided by (x – p) the remainder is f(p).

因式定理:(x – p) 是多项式 f(x) 的因式当且仅当 f(p) = 0。余数定理指出,f(x) 除以 (x – p) 的余数为 f(p)。


2. Quadratics and the Discriminant | 二次函数与判别式

Quadratic function in completed-square form: a(x + p)² + q. The vertex is at (–p, q) and the line of symmetry is x = –p.

二次函数的完全平方形式:a(x + p)² + q,顶点为 (–p, q),对称轴为 x = –p。

Using the discriminant to identify the number of intersections between a line and a curve: substitute the line equation into the quadratic, form a new quadratic, and examine its discriminant.

利用判别式判断直线与二次曲线的交点个数:将直线方程代入二次式,得到关于 x 的二次方程,计算其判别式即可。

Quadratic inequalities such as ax² + bx + c > 0 are solved by finding critical values where the expression equals zero, then testing intervals or using a sketch.

二次不等式如 ax² + bx + c > 0 的解法:先求出等于零的临界值,再通过区间测试或草图确定解集。


广告 / Sponsored

3. Indices and Logarithms | 指数与对数

Index laws for a > 0, b > 0:

指数律 (a > 0, b > 0):

The logarithm logₐ x is the power to which a must be raised to give x, i.e. alogₐ x = x. The natural logarithm ln x has base e.

对数 logₐ x 表示以 a 为底 x 的指数,即 alogₐ x = x。自然对数 ln x 以 e 为底。

Laws of logarithms for any valid base:

对数的基本运算法则(任意有效底数):

The exponential function y = eˣ and the natural log are inverses: eln x = x for x > 0, and ln(eˣ) = x.

指数函数 y = eˣ 与自然对数互为反函数:对于 x > 0 有 eln x = x,且 ln(eˣ) = x。


4. Sequences and the Binomial Expansion | 数列与二项展开

Arithmetic sequence: n-th term uₙ = a + (n – 1)d, sum of first n terms Sₙ = n/2 [2a + (n – 1)d] = n/2 (a + l), where l is the last term.

等差数列:第 n 项 uₙ = a + (n – 1)d,前 n 项和 Sₙ = n/2 [2a + (n – 1)d] = n/2 (a + l),其中 l 为末项。

Geometric sequence: n-th term uₙ = arⁿ⁻¹, sum of first n terms Sₙ = a(1 – rⁿ)/(1 – r) for r ≠ 1. Sum to infinity exists when |r| < 1 and is S∞ = a/(1 – r).

等比数列:第 n 项 uₙ = arⁿ⁻¹,前 n 项和 Sₙ = a(1 – rⁿ)/(1 – r),r ≠ 1。当 |r| < 1 时存在无穷和 S∞ = a/(1 – r)。

Binomial expansion for positive integer n: (a + b)ⁿ = Σⁿr=0 ⁿCᵣ aⁿ⁻ʳ bʳ, where ⁿCᵣ = n! / (r!(n – r)!). For (1 + x)ⁿ the expansion is 1 + nx + n(n–1)/2! x² + …

正整数 n 的二项展开:(a + b)ⁿ = Σⁿr=0 ⁿCᵣ aⁿ⁻ʳ bʳ,其中 ⁿCᵣ = n! / (r!(n – r)!)。(1 + x)ⁿ = 1 + nx + n(n–1)/2! x² + …

For rational n, the expansion (1 + x)ⁿ is valid for |x| < 1 and gives an infinite series: 1 + nx + n(n–1)/2! x² + n(n–1)(n–2)/3! x³ + …

对于有理数 n,(1 + x)ⁿ 在 |x| < 1 时展开为无穷级数:1 + nx + n(n–1)/2! x² + n(n–1)(n–2)/3! x³ + …


5. Coordinate Geometry | 坐标几何

Distance between two points (x₁, y₁) and (x₂, y₂): √[(x₂ – x₁)² + (y₂ – y₁)²]. Midpoint: ((x₁ + x₂)/2, (y₁ + y₂)/2).

两点间距离:√[(x₂ – x₁)² + (y₂ – y₁)²];中点坐标:((x₁ + x₂)/2, (y₁ + y₂)/2)。

Gradient of a straight line: m = (y₂ – y₁)/(x₂ – x₁). Equation of a line: y – y₁ = m(x – or y = mx + c. Parallel lines have equal gradients; perpendicular lines satisfy m₁ × m₂ = –1.

直线斜率:m = (y₂ – y₁)/(x₂ – x₁)。直线方程:y – y₁ = m(x – x₁) 或 y = mx + c。平行线斜率相等;垂直线斜率之积为 –1。

The equation of a circle with centre (a, b) and radius

Published by TutorHao | Year 12 Mathematics Revision Series | aleveler.com

广告 / Sponsored
2026年秋初中实验班提优训练789年级上下册语文数学英语人教苏教北师大译林版 初中七八九教材同步随堂作业本强化习题练…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥19.9

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao